Java 如何测试实现线程的代码?
我希望能够junit测试以下内容:Java 如何测试实现线程的代码?,java,junit,mocking,mockito,Java,Junit,Mocking,Mockito,我希望能够junit测试以下内容: private ExecutorService executor = Executors.newSingleThreadExecutor(); public void foo() { final EntityManagerFactory entityManagerFactory = entityManager.getEntityManagerFactory(); executor.execute(new Runnable() {
private ExecutorService executor = Executors.newSingleThreadExecutor();
public void foo() {
final EntityManagerFactory entityManagerFactory =
entityManager.getEntityManagerFactory();
executor.execute(new Runnable() {
@Override
public void run() {
EntityManager entityManager =
entityManagerFactory.createEntityManager();
Session session = (Session) entityManager.getDelegate();
try {
SQLQuery query =
session.createSQLQuery("SELECT * from foo_function()");
} catch (HibernateException exception) {
LOGGER.error("Exception: " + exception);
}
}
});
}
我用的是Mockito。我试图让它抛出一个异常,例如:
Mockito.doThrow(SQLException.class).when(mockSession).createSQLQuery(any(String.class));
它将在生成的线程中引发异常,但当我将其作为Junit测试运行时,它不会失败。您需要替换被测类中的Executor或ExecutorService:
public class YourClass {
private Executor executorService = Executor.newSingleThreadExecutor();
public YourClass() {}
/** package-visible for testing */
YourClass(Executor executor) {
/* ... */
}
public void foo() { /* ... */ }
}
…或者只是在您正在测试的方法中:
public class YourClass {
public void foo() {
foo(executorService);
}
/** package-visible for testing */
void foo(Executor executor) {
/* ... */
}
}
之后,您可以使用手动或基于番石榴的直接执行器,如中所示:
或者将其替换为Mockito mock,以便在Runnable运行之前和之后进行测试:
@Test public void fooShouldHandlException() {
Executor mockExecutor = Mockito.mock(Executor.class);
ArgumentCaptor<Runnable> runnableCaptor =
ArgumentCaptor.forClass(Runnable.class);
systemUnderTest.foo(mockExecutor);
// assert "before Runnable is run" state, if applicable
verify(mockExecutor).execute(runnableCaptor.capture());
runnableCaptor.getValue().run();
// assert "after Runnable is run" state
}
调试线程入口过程时,会话对象确实是mockito mock对象吗?是的,会话是mock的。whenmockEntityManager.getDelegate.thenReturnmockSession;你到底想测试什么?我不明白这句话:它会在生成的线程中抛出异常,但当我将其作为Junit测试运行时,它不会失败。我猜我要做什么,如何捕获executor服务生成的线程中抛出的异常?
@Test public void fooShouldHandlException() {
Executor mockExecutor = Mockito.mock(Executor.class);
ArgumentCaptor<Runnable> runnableCaptor =
ArgumentCaptor.forClass(Runnable.class);
systemUnderTest.foo(mockExecutor);
// assert "before Runnable is run" state, if applicable
verify(mockExecutor).execute(runnableCaptor.capture());
runnableCaptor.getValue().run();
// assert "after Runnable is run" state
}