Java 在Spring中添加管理部分

我有一个SpringWeb项目，它需要一个管理部分。我认为这部分很简单，而且我会有安全问题，但我甚至不能指向a/admin/section

我在dispatcher-servelet.xml中有以下内容可以将JSP文件映射到控制器：

<context:component-scan base-package="controller"/>
<context:component-scan base-package="controller.admin"/>

<bean id="viewResolver"
      class="org.springframework.web.servlet.view.InternalResourceViewResolver"
      p:prefix="/WEB-INF/jsp/"
      p:suffix=".jsp" />

现在，在/WEB-INF/jsp/中有一个名为“admin”的文件夹，其中有adminindex.jsp。我在web.xml中还有以下内容

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext.xml</param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>2</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>
    <session-config>
        <session-timeout>
            30
        </session-timeout>
    </session-config>
    <welcome-file-list>
        <welcome-file>redirect.jsp</welcome-file>
    </welcome-file-list>
    <security-constraint>
        <display-name>Constraint1</display-name>
    </security-constraint>
    <security-constraint>
        <display-name>admin pages</display-name>
        <web-resource-collection>
            <web-resource-name>Administration Pages</web-resource-name>
            <description/>
            <url-pattern>/admin/*</url-pattern>
        </web-resource-collection>
        <auth-constraint>
            <description/>
            <role-name>eCommerceAdmin</role-name>
        </auth-constraint>
        <!--  <user-data-constraint>
            <description/>
            <transport-guarantee>CONFIDENTIAL</transport-guarantee>
        </user-data-constraint>-->
    </security-constraint>
</web-app>

上下文配置位置
/WEB-INF/applicationContext.xml
org.springframework.web.context.ContextLoaderListener
调度员
org.springframework.web.servlet.DispatcherServlet
2.
调度员
*.htm
30
redirect.jsp
约束1
管理页面
管理页面
/管理员/*
电子商务管理员

当我尝试访问

localhost:8080/NewWebsite/admin/adminindex.htm

，我明白了

已拒绝访问请求的资源

信息：ContextListener: attributeAdded（'org.apache.jasper.compiler.tldLocationCache'， 'org.apache.jasper.compiler。TldLocationsCache@44d1bd08")

我在访问上没有问题

localhost:8080/NewWebsite/index.htm，我还希望对admin文件夹进行自动重定向，就像根文件夹一样。也就是去

localhost:8080/NewWebsite/directs to index.htm

---

任何帮助都很好。

您是否尝试将前缀更改为WEB-INF/jsp/admin/？

问题不在viewresolver中，因此您提供的信息不足以回答您的问题。请在您的安全配置中显示更多配置

---

除了你的问题。控制器的组件扫描是不必要的，因为第一个将扫描它。

< P>我认为您应该考虑使用Spring Security，然后您可以配置Spring Security角色系统来控制访问。下面是我的一个应用程序的一个代码片段，您可以看到/admin路径要求调用方具有admin角色。SpringSecurity的设置有点复杂，但一旦设置完成，它就会工作得很好

<http auto-config='true' use-expressions="true" >

    <!-- public resources that everyone should be able to access -->
    <intercept-url pattern="/favicon.ico" access="permitAll" />
    <intercept-url pattern="/login"       access="permitAll" />
    <intercept-url pattern="/login/error" access="permitAll" />
    <intercept-url pattern="/**/*.js"        access="permitAll" />
    <intercept-url pattern="/**/*.jsp"       access="denyAll" />

    <intercept-url pattern="/admin/**"     access="hasRole('admin')" />

    </session-management>

</http>

---

首先需要验证用户？不是吗？否则，您的应用程序将如何识别管理员是试图访问还是普通用户
在执行此操作之前，请从web.xml中删除

安全约束
因此，请在应用程序中添加spring身份验证。

首先创建一个pojo类，它有一个
GrantedAuthority
列表，应该实现
org.springframework.security.core.userdetails.userdetails
。以下是一个示例：

public class YourPojo implements UserDetails{


    /** The authorities. */
    //This collection will have eCommerceAdmin
    public Collection<GrantedAuthority> authorities;

    /** The username. */
    public String username;

    /** The account non expired. */
    public boolean accountNonExpired;

    /** The credentials non expired. */
    public boolean credentialsNonExpired;

    /** The enabled. */
    public boolean enabled;

    /** The Constant serialVersionUID. */
    private static final long serialVersionUID = -2342376103893073629L;

    /* (non-Javadoc)
     * @see org.springframework.security.core.userdetails.UserDetails#getAuthorities()
     */
    @Override
    public Collection<GrantedAuthority> getAuthorities() {
        return authorities;
    }

    /* (non-Javadoc)
     * @see org.springframework.security.core.userdetails.UserDetails#getPassword()
     */
    @Override
    public String getPassword() {
        return null;
    }

    /* (non-Javadoc)
     * @see org.springframework.security.core.userdetails.UserDetails#getUsername()
     */
    @Override
    public String getUsername() {
        return username;
    }

    /* (non-Javadoc)
     * @see org.springframework.security.core.userdetails.UserDetails#isAccountNonExpired()
     */
    @Override
    public boolean isAccountNonExpired() {
        return accountNonExpired;
    }

    /* (non-Javadoc)
     * @see org.springframework.security.core.userdetails.UserDetails#isAccountNonLocked()
     */
    @Override
    public boolean isAccountNonLocked() {
        return accountNonLocked;
    }

    /* (non-Javadoc)
     * @see org.springframework.security.core.userdetails.UserDetails#isCredentialsNonExpired()
     */
    @Override
    public boolean isCredentialsNonExpired() {
        return credentialsNonExpired;
    }

    /* (non-Javadoc)
     * @see org.springframework.security.core.userdetails.UserDetails#isEnabled()
     */
    @Override
    public boolean isEnabled() {
        return enabled;
    }


    /**
     * Sets the authorities.
     *
     * @param authorities the new authorities
     */
    public void setAuthorities(Collection<GrantedAuthority> authorities) {
        this.authorities = authorities;
    }

    /**
     * Sets the username.
     *
     * @param username the new username
     */
    public void setUsername(String username) {
        this.username = username;
    }

    /**
     * Sets the account non expired.
     *
     * @param accountNonExpired the new account non expired
     */
    public void setAccountNonExpired(boolean accountNonExpired) {
        this.accountNonExpired = accountNonExpired;
    }

    /**
     * Sets the account non locked.
     *
     * @param accountNonLocked the new account non locked
     */
    public void setAccountNonLocked(boolean accountNonLocked) {
        this.accountNonLocked = accountNonLocked;
    }

    /**
     * Sets the credentials non expired.
     *
     * @param credentialsNonExpired the new credentials non expired
     */
    public void setCredentialsNonExpired(boolean credentialsNonExpired) {
        this.credentialsNonExpired = credentialsNonExpired;
    }

    /**
     * Sets the enabled.
     *
     * @param enabled the new enabled
     */
    public void setEnabled(boolean enabled) {
        this.enabled = enabled;
    }

}

FYR您可以参考web.xml中的安全xml文件，如下所示。而且您的web.xml应该具有spring安全过滤器

<context-param>
 <param-name>contextConfigLocation</param-name>
  <param-value>
    /WEB-INF/your-applicationContext.xml
    /WEB-INF/your-spring-security.xml
  </param-value>
</context-param>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>


上下文配置位置
/WEB-INF/your-applicationContext.xml
/WEB-INF/your-spring-security.xml
org.springframework.web.context.ContextLoaderListener
springSecurityFilterChain
org.springframework.web.filter.DelegatingFilterProxy
springSecurityFilterChain
/*

您还需要spring安全依赖项。如果您在项目中使用Maven，请添加以下依赖项，否则您可以手动下载这些JAR并继续

<!-- Spring Security -->
<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-core</artifactId>
    <version>${spring.version}</version>
</dependency>
<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-web</artifactId>
    <version>${spring.version}</version>
</dependency>

<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-config</artifactId>
    <version>${spring.version}</version>
</dependency>


org.springframework.security
如果您在此处提供更多代码，则很容易回答。只有这么多的设置不会有帮助。您是否正在向您的用户添加角色，如角色\管理员？？对不起，我不确定还要添加什么。我已经添加了web.xml的全部内容，但我不确定如何调整它以包含管理员角色？您在哪里将
ecommercemadmin
此角色添加到您的spring
org.springframework.security.core.Authentication
？？我认为这是以前的一次失败尝试，我忘记了删除它。你知道我应该在哪里添加它吗？谢谢你的建议，我已经包括了web.xml的其余部分，我如何才能包括管理员角色和可能的分配登录详细信息？哇，这真的很好，谢谢你。如果可以的话，我有几个问题我把你的POJO课放在哪里有关系吗？HTTP标记和bean是否要放在applicationContext中？我把customeAuthProvider放在哪里重要吗？我还没有机会尝试一下，但我只是想澄清一下。不用谢我。您可以对答案进行投票，稍后如果答案有效（如果配置正确，则应该如此），则可以接受答案。现在，您的答案是：您可以将
YourPjojo
放在任何地方。身份验证提供者也是如此，但您应该在bean中提供正确的包详细信息。。http标记和bean不应位于
applicationContext
中。您可以将其放置在其他xml文件中，并将其附加到web.xml中。如何将UserDetails包含到项目中？Netbeans目前正处于一种状态。YourPojo在抱怨，我也不知道如何包含新的XML文件。它们在dispatcher中被引用了吗？UserDetails是spring的接口…你没有使用applicationContext.xml吗？你是如何在web.xml中引用它的？同样的方法也可以添加新的xml..添加了一些代码..请参阅你可以看到的编辑器..你将看到详细的解释..还有一些源代码。：）
@Override
    public Authentication authenticate(Authentication authentication)
            throws AuthenticationException {

        UsernamePasswordAuthenticationToken userToken = (UsernamePasswordAuthenticationToken)authentication;
        String username = userToken.getName();
        String password = (String) authentication.getCredentials();
          //Do whatevr you want with the credentials
         //Then populate the authorities for this credential
         YourPojo user=new YourPojo ();
         user.setUserName("add username");
        //set other details
        List<GrantedAuthority> grantedAuthorityList = new ArrayList<GrantedAuthority>();
        //if user is admin add the below line
        GrantedAuthorityImpl grantedAuthorityImpl = new GrantedAuthorityImpl("eCommerceAdmin");
       //Add other authorities as applicable like 'user' etc.
       user.setAuthorities(grantedAuthorityList);
       return new UsernamePasswordAuthenticationToken(username, password, user.getAuthorities());

<context-param>
 <param-name>contextConfigLocation</param-name>
  <param-value>
    /WEB-INF/your-applicationContext.xml
    /WEB-INF/your-spring-security.xml
  </param-value>
</context-param>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<!-- Spring Security -->
<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-core</artifactId>
    <version>${spring.version}</version>
</dependency>
<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-web</artifactId>
    <version>${spring.version}</version>
</dependency>

<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-config</artifactId>
    <version>${spring.version}</version>
</dependency>