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Java SpringMVC显示HTTP状态404_Java_Spring_Jsp_Spring Mvc - Fatal编程技术网

Java SpringMVC显示HTTP状态404

Java SpringMVC显示HTTP状态404,java,spring,jsp,spring-mvc,Java,Spring,Jsp,Spring Mvc,这是错误消息:- 这是我的项目结构:- 以下是我的代码:- HelloController.java package com.home.pack; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.bind.annotation.RequestMethod

这是错误消息:-

这是我的项目结构:-

以下是我的代码:-

HelloController.java

package com.home.pack;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.ui.ModelMap;

@Controller
@RequestMapping("/hello")
public class HelloController{

   @RequestMapping(method = RequestMethod.GET)
   public String printHello(ModelMap model) {
      model.addAttribute("message", "Hello Spring MVC Framework!");

      return "hello";
   }

}
web.xml

<web-app id="WebApp_ID" version="2.4"
   xmlns="http://java.sun.com/xml/ns/j2ee" 
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
   http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
   <display-name>Spring MVC Application</display-name>
   <servlet>
      <servlet-name>HelloWeb</servlet-name>
      <servlet-class>
         org.springframework.web.servlet.DispatcherServlet
      </servlet-class>
      <load-on-startup>1</load-on-startup>
   </servlet>
   <servlet-mapping>
      <servlet-name>HelloWeb</servlet-name>
      <url-pattern>/</url-pattern>
   </servlet-mapping>

</web-app>
<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:context="http://www.springframework.org/schema/context"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="
   http://www.springframework.org/schema/beans     
   http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
   http://www.springframework.org/schema/context 
   http://www.springframework.org/schema/context/spring-context-3.0.xsd">

   <context:component-scan base-package="com.home.pack" />

   <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
      <property name="prefix" value="/WEB-INF/jsp/" />
      <property name="suffix" value=".jsp" />
   </bean>
</beans>

SpringMVC应用程序
你好
org.springframework.web.servlet.DispatcherServlet
1.
你好
/
HelloWeb servlet.xml

<web-app id="WebApp_ID" version="2.4"
   xmlns="http://java.sun.com/xml/ns/j2ee" 
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
   http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
   <display-name>Spring MVC Application</display-name>
   <servlet>
      <servlet-name>HelloWeb</servlet-name>
      <servlet-class>
         org.springframework.web.servlet.DispatcherServlet
      </servlet-class>
      <load-on-startup>1</load-on-startup>
   </servlet>
   <servlet-mapping>
      <servlet-name>HelloWeb</servlet-name>
      <url-pattern>/</url-pattern>
   </servlet-mapping>

</web-app>
<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:context="http://www.springframework.org/schema/context"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="
   http://www.springframework.org/schema/beans     
   http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
   http://www.springframework.org/schema/context 
   http://www.springframework.org/schema/context/spring-context-3.0.xsd">

   <context:component-scan base-package="com.home.pack" />

   <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
      <property name="prefix" value="/WEB-INF/jsp/" />
      <property name="suffix" value=".jsp" />
   </bean>
</beans>

hello.jsp

<%@ page contentType="text/html; charset=UTF-8" %>
<html>
<head>
<title>Hello World</title>
</head>
<body>
   <h2>${message}</h2>
</body>
</html>

你好,世界
${message}

我正在遵循本教程->但我无法让它工作。似乎我在这里遗漏了一些东西,如果有人指出这一点,我将不胜感激。谢谢。

你想显示“你好”页面?Spring可能将其视为控制器,因为您执行了
@RequestMapping(“/hello”)
。。。所以我猜这里你试图将控制器显示为一个页面,这肯定会显示404错误

尝试将您的方法更改为“休耕”:

@RequestMapping(value = "/hello", method = RequestMethod.GET)
public String printHello(ModelMap model) {
   model.addAttribute("message", "Hello Spring MVC Framework!");

   return "hello";
}
并删除控制器上的请求映射 我想这样会更好


或者让请求映射在您的控制器上,并为其他内容更改方法的请求映射,然后通过添加…/hello/yourMethodValue来访问它

我对spring mvc一无所知,但404表示您的url不正确(找不到资源)。您是否检查了web.xml和绑定/hello的逻辑。HelloWebServlet与您的HelloController有何关联?只需提供特定方法的url,就像您刚才在@RequestMapping(method=RequestMethod.GET)中提供的方法一样。。。在这里提供价值,并将其添加到您的URL@NiravChhatrola:但我已经给出了类级别的url。请详细说明。@ParagKadam转到服务器的选项卡>右键单击tomcat>添加和删除>确保添加了SpringTest>删除其他服务器。重新启动服务器。不,这也没用。问题是,为什么上面的代码不运行。如何以另一种方式运行是另一件事,我看到了,我的错误。