Java 如何交错列表
我脑子里有些东西已经困扰了我很长一段时间了,希望我能得到一些善良的灵魂的帮助D 不管怎样,我想做的是: 比如说,我确实有一些清单Java 如何交错列表,java,arraylist,collections,Java,Arraylist,Collections,我脑子里有些东西已经困扰了我很长一段时间了,希望我能得到一些善良的灵魂的帮助D 不管怎样,我想做的是: 比如说,我确实有一些清单 List<String> a = {"for testA1", "for testA2", "for testA3"}; List<String> b; = {"for testB1", "for testB2", "for testB3"}; List<String> c; = {"for testC1", "for testC2
List<String> a = {"for testA1", "for testA2", "for testA3"};
List<String> b; = {"for testB1", "for testB2", "for testB3"};
List<String> c; = {"for testC1", "for testC2", "for testC3"};
我的最终输出应该是:
List<ObjectA> -
测试1
测试B1
测试C1
测试2
测试B2
测试C2
测试3
测试B3
测试C3
如何在给定的单个列表中设置对象中的这些字符串
对不起,我的英语不好,我希望这是可以理解的
我心里有个想法,但不太明白
我的密码是
List<String> aList = ....;
List<String> bList = ....;
List<String> cList = ....;
List<ObjectA> someList = new ArrayList<ObjectA>();
for(String a: aList){
ObjectA obj = new ObjectA();
obj.setTestA(a);
}
ListIterator litr = someList.listIterator();
while(litr.hasNext()) {
ObjectA element = (ObjectA) litr.next();
// I wanna loop List<String> bList and add element.setTestB but it doesn't work.
// This is what I wanna do...
}
下面的注释说明了一个很好的观点-对于链接列表或任何其他具有访问任意元素的时间限制的列表,这可能是一种基于^2的解决方案
Iterator<String> aIt = a.iterator();
Iterator<String> bIt = b.iterator();
Iterator<String> cIt = c.iterator();
List<ObjectA> thislist = new ArrayList<ObjectA>();
// assumes all the lists have the same size
while(aIt.hasNext())
{
Object A o = new ObjectA(aIt.next(), bIt.next(), cIt.next());
thisList.add(o);
}
下面的注释说明了一个很好的观点-如果链接列表或任何其他列表在访问时间上可以访问任意元素,那么这可能是一个基于^2的解决方案,假设您映射的对象是
Iterator<String> aIt = a.iterator();
Iterator<String> bIt = b.iterator();
Iterator<String> cIt = c.iterator();
List<ObjectA> thislist = new ArrayList<ObjectA>();
// assumes all the lists have the same size
while(aIt.hasNext())
{
Object A o = new ObjectA(aIt.next(), bIt.next(), cIt.next());
thisList.add(o);
}
public class Triplet{
private final String jedi;
private final String sith;
private final String padawan;
public Triplet(String jedi, String sith, String padawan){
this.jedi = jedi;
this.sith = sith;
this.padawan = padawan;
}
}
我们可以定义一个映射迭代器:
public static class TripletIterator implements Iterator<Triplet>{
Iterator<String> jedis;
Iterator<String> siths;
Iterator<String> padawans;
public TripletIterator(List<String> jedis, List<String> sith, List<String> padawns){
this.jedis = jedis.iterator();
this.siths = sith.iterator();
this.padawans = padawns.iterator();
}
@Override
public boolean hasNext() {
return jedis.hasNext() && siths.hasNext() && padawans.hasNext();
}
@Override
public Triplet next() {
return new Triplet(jedis.next(), siths.next(), padawans.next());
}
@Override
public void remove() {
throw new UnsupportedOperationException();
}
}
然后你可以简单地:
List<String> jedis = asList("Obiwan","Yoda","Luke");
List<String> siths = asList("Lord Sidious", "Darth Mul", "Darth Vader");
List<String> padawans = asList("Anakin", "Jarjar", "Poncho");
Iterator<Triplet> iter = new TripletIterator(jedis, siths, padawans);
while(iter.hasNext()){
Triplet t = iter.next();
System.out.println(t);
}
好吧,假设您映射的对象是
public class Triplet{
private final String jedi;
private final String sith;
private final String padawan;
public Triplet(String jedi, String sith, String padawan){
this.jedi = jedi;
this.sith = sith;
this.padawan = padawan;
}
}
我们可以定义一个映射迭代器:
public static class TripletIterator implements Iterator<Triplet>{
Iterator<String> jedis;
Iterator<String> siths;
Iterator<String> padawans;
public TripletIterator(List<String> jedis, List<String> sith, List<String> padawns){
this.jedis = jedis.iterator();
this.siths = sith.iterator();
this.padawans = padawns.iterator();
}
@Override
public boolean hasNext() {
return jedis.hasNext() && siths.hasNext() && padawans.hasNext();
}
@Override
public Triplet next() {
return new Triplet(jedis.next(), siths.next(), padawans.next());
}
@Override
public void remove() {
throw new UnsupportedOperationException();
}
}
然后你可以简单地:
List<String> jedis = asList("Obiwan","Yoda","Luke");
List<String> siths = asList("Lord Sidious", "Darth Mul", "Darth Vader");
List<String> padawans = asList("Anakin", "Jarjar", "Poncho");
Iterator<Triplet> iter = new TripletIterator(jedis, siths, padawans);
while(iter.hasNext()){
Triplet t = iter.next();
System.out.println(t);
}
除非您知道getint是一个O1操作,否则最好使用迭代器。除非您知道getint是一个O1操作,否则最好使用迭代器。太棒了。对于任意列表的情况,比我的解决方案更好。对于任意列表的情况,比我的解决方案要好