Java 将二进制字符串转换为字符
我已经把一些字符转换成二进制。现在我想将它们转换回原始字符。谁能告诉我怎么做 这是我将字符转换为二进制的代码Java 将二进制字符串转换为字符,java,android,type-conversion,Java,Android,Type Conversion,我已经把一些字符转换成二进制。现在我想将它们转换回原始字符。谁能告诉我怎么做 这是我将字符转换为二进制的代码 string = Integer.toBinaryString(c); 其中c是字符类型。所以,当我把一个字符'a'转换成二进制时,我得到了类似这样的东西-1101101我不确定它在安卓系统中是否有效,但你试过简单强制转换吗 byte b = 90; //char Z char c = (char) b; 与基数=2(对于二进制)一起使用,将字符串转换为int,然后将int转换为字符
string = Integer.toBinaryString(c);
其中
c
是字符类型。所以,当我把一个字符'a'
转换成二进制时,我得到了类似这样的东西-1101101
我不确定它在安卓系统中是否有效,但你试过简单强制转换吗
byte b = 90; //char Z
char c = (char) b;
与基数=2
(对于二进制)一起使用,将字符串
转换为int
,然后将int
转换为字符
,如下所示:
int parseInt = Integer.parseInt(your_binary_string, 2);
char c = (char)parseInt;
幸运的是,JavaAPI提供了一种相当简单的方法将二进制字节转换回原始字符
String char = (char)Integer.parseInt(string, 2)
该字符串是二进制代码的一个字节(8位)。2表示我们目前在2号基地。为了实现这一点,您需要将上述二进制代码块分成8位的部分
但是,函数Integer.tobinarysting(c)并不总是以8的形式返回。这意味着您需要确保原始输出都是8的倍数
结果会是这样的:
public String encrypt(String message) {
//Creates array of all the characters in the message we want to convert to binary
char[] characters = message.toCharArray();
String returnString = "";
String preProcessed = "";
for(int i = 0; i < characters.length; i++) {
//Converts the character to a binary string
preProcessed = Integer.toBinaryString((int)characters[i]);
//Adds enough zeros to the front of the string to make it a byte(length 8 bits)
String zerosToAdd = "";
if(preProcessed.length() < 8) {
for(int j = 0; j < (8 - preProcessed.length()); j++) {
zerosToAdd += "0";
}
}
returnString += zerosToAdd + preProcessed;
}
//Returns a string with a length that is a multiple of 8
return returnString;
}
//Converts a string message containing only 1s and 0s into ASCII plaintext
public String decrypt(String message) {
//Check to make sure that the message is all 1s and 0s.
for(int i = 0; i < message.length(); i++) {
if(message.charAt(i) != '1' && message.charAt(i) != '0') {
return null;
}
}
//If the message does not have a length that is a multiple of 8, we can't decrypt it
if(message.length() % 8 != 0) {
return null;
}
//Splits the string into 8 bit segments with spaces in between
String returnString = "";
String decrypt = "";
for(int i = 0; i < message.length() - 7; i += 8) {
decrypt += message.substring(i, i + 8) + " ";
}
//Creates a string array with bytes that represent each of the characters in the message
String[] bytes = decrypt.split(" ");
for(int i = 0; i < bytes.length; i++) {
/Decrypts each character and adds it to the string to get the original message
returnString += (char)Integer.parseInt(bytes[i], 2);
}
return returnString;
}
公共字符串加密(字符串消息){
//创建消息中要转换为二进制的所有字符的数组
char[]characters=message.toCharArray();
字符串returnString=“”;
字符串预处理=”;
for(int i=0;i
下面的源代码对我很有用
StringBuilder binary;
创建一个类
public String stringToBinary(String str, boolean pad) {
byte[] bytes = str.getBytes();
binary = new StringBuilder();
for (byte b : bytes)
{
binary.append(Integer.toBinaryString((int) b));
if(pad) { binary.append(' '); }
}
System.out.println("String to Binary : "+binary);
return binary.toString();
}
然后,调用类
stringToBinary("a",true);
输出:
1000001
您是如何从字符生成二进制的?发布一些工作代码[1]: