Java中按字段对对象数组排序：“变量无法解析或不是字段”

我试图按字段对对象数组进行排序，但我一直收到这样的错误消息，即价格/位置无法解析或不是字段，即使它们都是类Realestate中声明的字段。在处理ArrayList时，我也遇到了同样的错误，即不是字段，所以我转向了简单的对象数组，我仍然会遇到同样的错误。我做错了什么？我找到了关于将数组与Comparable and Comparator进行比较的信息，但我不知道如何将任何结果应用于排序例程。请帮忙！这些是我的文件：

文件不动产：

public class Realestate {
    static String location = "";
    static String description = "";
    static String price = "";

    // constructor
    public Realestate(String loc, String desc, String prc) {
        location = loc;
        description = desc;
        price = prc;
    }
}

文件RealestateFinder:

import java.util.*;

public class RealestateFinder {

    // Hold properties' info
    static String[] locations = {"Miami", "Las Vegas", "Paris", "London"};
    static String[] descriptions = {"1-bedroom", "2-bedrooms", "3-bedrooms", "penthouse"};
    static String[] prices = {"1,000,000", "2,000,000", "3,000,000", "4,000,000"};

    // Sort per field
    public static void sortArray(Realestate arr[]) {
        for(int x = 0; x < arr.length; ++x) {            
            //use array Sort
            Arrays.sort(arr);
        }           
    }

    public static void main(String[] args) {        
        int numProperties = 4;

        //Create new Realestate object newProperty
        Realestate[] newProperty = new Realestate[numProperties]; 

        // Initialize array of objects Realestate[] newProperty using arrays from top
        for(int x = 0; x < newProperty.length; ++x) {
            newProperty[x] = new Realestate(locations[x], descriptions[x], prices[x]); // constructor
        }

        //Get user's input
        //...

        while(true) {
            if(holdUserInput == 1) {
                //sort per price
                sortArray(newProperty.price);//price cannot be resolved or is not a field
                break;
            }

            else if(holdUserInput == 2) {
                // sort per location
                sortArray(newProperty.location);//location cannot be resolved or is not a field
                break;
            }

            else {
                System.out.println("Program Ended \n");
                break;
            }// end else statement
        }// end while loop
    }// end main()
}// end class RealestateFinder

---

首先，您可能不会在3个字段中使用static，static意味着它与特定实例无关，这不是您想要的

然后使用列表更容易排序，因此：

int numProperties = 4;
List<Realestate> list = new ArrayList<>();
for (int x = 0; x < numProperties; ++x) {
    list.add(new Realestate(locations[x], descriptions[x], prices[x]));
}

最后，由于在发生故障和中断时使用没有意义，因此最好使用更好的开关：

switch (holdUserInput) {
    case 1:
        list.sort(Comparator.comparing(Realestate::getPrice));
        break;
    case 2:
        list.sort(Comparator.comparing(Realestate::getLocation));
        break;
    case 3:
        list.sort(Comparator.comparing(Realestate::getDescription));
        break;
    default:
        System.out.println("Program Ended \n");
        break;
}

---

是的，newProperty是一个数组-数组没有价格。。。听起来你可能想看看你的问题有多个与你的问题无关的问题谢谢，@azro，你的回答真的很有帮助，不仅仅是因为这段代码，还有我对一些概念的理解：

switch (holdUserInput) {
    case 1:
        list.sort(Comparator.comparing(Realestate::getPrice));
        break;
    case 2:
        list.sort(Comparator.comparing(Realestate::getLocation));
        break;
    case 3:
        list.sort(Comparator.comparing(Realestate::getDescription));
        break;
    default:
        System.out.println("Program Ended \n");
        break;
}