为什么可以';在java中,我是否将一个变量作为格式字符串传递给System.out.printf(…)?
我试图用Java向System.out.printf(…)传递一个字符串对象,但我一直收到这个错误为什么可以';在java中,我是否将一个变量作为格式字符串传递给System.out.printf(…)?,java,printf,Java,Printf,我试图用Java向System.out.printf(…)传递一个字符串对象,但我一直收到这个错误“Java.util.FormatFlagsConversionMismatchException:Conversion=s,Flags=0”,这对我来说实际上没有多大意义 String format = "%" + (3 * n) + "s"; // n is an int defined somewhere above, could be 0 System.out.printf(format,
“Java.util.FormatFlagsConversionMismatchException:Conversion=s,Flags=0”
,这对我来说实际上没有多大意义
String format = "%" + (3 * n) + "s"; // n is an int defined somewhere above, could be 0
System.out.printf(format, "My string");
有人知道这是允许的吗
有关详细信息,请编辑:
int n = 0;
String fm = "%" + (3 * level) + "s";
String realFm = "%0s";
System.out.println("fm = " + fm);
System.out.println("realfm = " + realFm);
System.out.println("equals? " + (fm.equals(realFm)));
System.out.printf(fm, " ");
以下是输出:
fm = %0s
realfm = %0s
equals? true
java.util.FormatFlagsConversionMismatchException: Conversion = s, Flags = 0
谢谢是的,这是允许的,但如果n为0,它将不起作用。是否存在发生这种情况的可能性(从错误消息中看起来是这样的) 如果在代码中添加一行以进行调试,该怎么办:
// line added below for debugging. To remove later:
System.out.println("n is: " + n);
String format = "%" + (3 * n) + "s"; // n is an int defined somewhere above
System.out.printf(format, "My string");
它是否打印过n is:0?
e、 g
publicstaticvoidmain(字符串[]args){
//尝试n=0与n=1的for循环
对于(int n=1;n我已经用代码和输出的详细信息更新了帖子。请检查。Thanks@user1064918:我给出的答案是正确的--标志不能为0。您需要修复代码以防止发生这种情况。您更新的代码仍然没有显示n不为零的示例。格式字符串%0s
无效。
public static void main(String[] args) {
// try the for loop with n = 0 vs. n = 1
for (int n = 1; n <= 10; n++) {
// line added below for debugging. To remove later:
System.out.println("\nn is: " + n);
String format = "%" + (3 * n) + "s";
System.out.printf(format, "My string");
}
}