Java 是否保留文本文件中字母出现的次数？_Java

Java 是否保留文本文件中字母出现的次数？

java

Java 是否保留文本文件中字母出现的次数？,java,Java,我必须编写一个程序，在这个程序中，我必须找到“test.txt”文件中每个字母的数量，然后将这个数字除以字母总数，找到每个字母的出现百分比（我还没有做到）。然而，我甚至不知道如何找到文本文件中每个字母的编号。这是我极其失败的尝试。谁能帮帮我吗 import java.io.*; class EnglishAnalysis { public static void main(String[] args) { try { char letters[] = {'a','b','c','d','e'

我必须编写一个程序，在这个程序中，我必须找到“test.txt”文件中每个字母的数量，然后将这个数字除以字母总数，找到每个字母的出现百分比（我还没有做到）。然而，我甚至不知道如何找到文本文件中每个字母的编号。这是我极其失败的尝试。谁能帮帮我吗

import java.io.*;
class EnglishAnalysis
{
public static void main(String[] args)
{
try
{
  char letters[] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
  FileReader fr = new FileReader("test.txt");
  BufferedReader br = new BufferedReader(fr);

  int count = 0;
  int totalLetters = 0;
  String lineCharacters [];
  String line;
  line = br.readLine();
  while (line != null)
  {
    lineCharacters = line.split("");
    for (int i = 0; i < lineCharacters.length; i++)
    {
      if (!Character.isWhitespace(line.charAt(i)))
      totalLetters++;
      for (int j = 0; j <= i; j++)
      {
        if (line.charAt(i) == letters[j])
          count++;
          System.out.println(line.charAt(i) + " : " + count);
      }
    }
    line = br.readLine();
  }
  System.out.println(totalLetters);
  br.close();
  }
catch (IOException e) {}
}
}

import java.io.*；
课堂英语分析
{
公共静态void main（字符串[]args）
{
尝试
{
字符字母[]={'a'、'b'、'c'、'd'、'e'、'f'、'g'、'h'、'i'、'j'、'k'、'l'、'm'、'n'、'o'、'p'、'q'、'r'、's'、't'、'u'、'v'、'w'、'x'、'y'、'z'；
FileReader fr=新的FileReader（“test.txt”）；
BufferedReader br=新的BufferedReader（fr）；
整数计数=0；
整数=0；
字符串行字符[]；
弦线；
line=br.readLine（）；
while（行！=null）
{
lineCharacters=行。拆分（“”）；
对于（int i=0；i对于（int j=0；j我采用了不同的方法。请参阅下面的代码和代码注释以了解解释
代码：
样本输出：
"a" has a percentage of 5.88%
"b" has a percentage of 5.88%
"c" has a percentage of 5.88%
"d" has a percentage of 5.88%
"e" has a percentage of 5.88%
"f" has a percentage of 5.88%
"g" has a percentage of 5.88%
"h" has a percentage of 5.88%
"i" has a percentage of 2.94%
"j" has a percentage of 2.94%
"k" has a percentage of 2.94%
"l" has a percentage of 2.94%
"m" has a percentage of 2.94%
"n" has a percentage of 2.94%
"o" has a percentage of 2.94%
"p" has a percentage of 2.94%
"q" has a percentage of 2.94%
"r" has a percentage of 2.94%
"s" has a percentage of 2.94%
"t" has a percentage of 2.94%
"u" has a percentage of 2.94%
"v" has a percentage of 2.94%
"w" has a percentage of 2.94%
"x" has a percentage of 2.94%
"y" has a percentage of 2.94%
"z" has a percentage of 2.94%

这只适用于文件中的单词在一行的情况，但可以使用空格。如果你仍然有问题，我可能明天就能解决这个问题，但我明天有课，所以我必须去睡觉。希望这有帮助
import java.io.*;
import java.util.*;

public class CountLettersFromFile {

public static void main(String[] args) throws IOException {

    FileReader file = new FileReader("test.txt");
    BufferedReader br=new BufferedReader(file);

    String[] lineCharacters;
    String line;

    line=br.readLine();
    int totalLetters=0;


    lineCharacters=line.split("");
    for (int i = 0; i < lineCharacters.length; i++) {
        if(!Character.isWhitespace(line.charAt(i)))
            totalLetters++;

    }


    double[] count = new double[255];
    int length = line.length();


    for (int i = 0; i < length; i++) {
        count[line.charAt(i)]++;
    }

    char[] ch = new char[line.length()];
    for (int i = 0; i < length; i++) {
        ch[i] = line.charAt(i);
        int find = 0;
        for (int j = 0; j <= i; j++) {
            if (line.charAt(i) == ch[j])
                find++;
        }

        if (find == 1 && !Character.isWhitespace(line.charAt(i))) {
            System.out.printf("Occurance of character \"" + line.charAt(i) + "\" is: %.0f %n"
                    , count[line.charAt(i)]);
            System.out.printf("Percent occurance of character \"" +line.charAt(i) + "\" is: %.3f %n"
                    , (count[line.charAt(i)])/totalLetters,"%");
            System.out.println("\n------------------------------------------------");
        }
    }
}

import java.io.*；
导入java.util.*；
公共类CountLettersFromFile{
公共静态void main（字符串[]args）引发IOException{
FileReader文件=新的FileReader（“test.txt”）；
BufferedReader br=新的BufferedReader（文件）；
字符串[]行字符；
弦线；
line=br.readLine（）；
整数=0；
lineCharacters=行。拆分（“”）；
对于（int i=0；ifor（int j=0；j提示：每个字符都是一个int。通过一点数学运算，您可以将a
转换为0
，b
转换为1
等等。然后，只需在数组中的该位置增加一个int即可（这是假设所有字母都是小写，就像在数组中一样）提示2：或者，您可以使用映射
（但数组是更有效的解决方案）。您的计数++；全局用于所有字符，您可以按照Elliott的建议在映射上设置计数。一种可能的解决方案。
"a" has a percentage of 5.88%
"b" has a percentage of 5.88%
"c" has a percentage of 5.88%
"d" has a percentage of 5.88%
"e" has a percentage of 5.88%
"f" has a percentage of 5.88%
"g" has a percentage of 5.88%
"h" has a percentage of 5.88%
"i" has a percentage of 2.94%
"j" has a percentage of 2.94%
"k" has a percentage of 2.94%
"l" has a percentage of 2.94%
"m" has a percentage of 2.94%
"n" has a percentage of 2.94%
"o" has a percentage of 2.94%
"p" has a percentage of 2.94%
"q" has a percentage of 2.94%
"r" has a percentage of 2.94%
"s" has a percentage of 2.94%
"t" has a percentage of 2.94%
"u" has a percentage of 2.94%
"v" has a percentage of 2.94%
"w" has a percentage of 2.94%
"x" has a percentage of 2.94%
"y" has a percentage of 2.94%
"z" has a percentage of 2.94%

import java.io.*;
import java.util.*;

public class CountLettersFromFile {

public static void main(String[] args) throws IOException {

    FileReader file = new FileReader("test.txt");
    BufferedReader br=new BufferedReader(file);

    String[] lineCharacters;
    String line;

    line=br.readLine();
    int totalLetters=0;


    lineCharacters=line.split("");
    for (int i = 0; i < lineCharacters.length; i++) {
        if(!Character.isWhitespace(line.charAt(i)))
            totalLetters++;

    }


    double[] count = new double[255];
    int length = line.length();


    for (int i = 0; i < length; i++) {
        count[line.charAt(i)]++;
    }

    char[] ch = new char[line.length()];
    for (int i = 0; i < length; i++) {
        ch[i] = line.charAt(i);
        int find = 0;
        for (int j = 0; j <= i; j++) {
            if (line.charAt(i) == ch[j])
                find++;
        }

        if (find == 1 && !Character.isWhitespace(line.charAt(i))) {
            System.out.printf("Occurance of character \"" + line.charAt(i) + "\" is: %.0f %n"
                    , count[line.charAt(i)]);
            System.out.printf("Percent occurance of character \"" +line.charAt(i) + "\" is: %.3f %n"
                    , (count[line.charAt(i)])/totalLetters,"%");
            System.out.println("\n------------------------------------------------");
        }
    }
}