在java中，下面的curl命令等效于什么

我需要将下面的curl命令转换为java命令

$curl_handle = curl_init ();

curl_setopt ($curl_handle, CURLOPT_URL,$url);`enter code here`
curl_setopt ($curl_handle, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt ($curl_handle, CURLOPT_RETURNTRANSFER, 1);
curl_setopt ($curl_handle, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt ($curl_handle, CURLOPT_POST, 1);
curl_setopt ($curl_handle, CURLOPT_POSTFIELDS, $postfields);

//echo $postfields;

$curl_result = curl_exec ($curl_handle) or die ("There has been a CURL_EXEC error");

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请查看java.net.URL和java.net.URL连接库

URL url = new URL("yourUrl.com");

然后使用InputStreamReader&BufferedReader

有关Oracles示例的更多信息：

这也可能有帮助：

HttpsUrlConnection可能是您选择的武器：

public String sendData() throws IOException {
    // curl_init and url
    URL url = new URL("http://some.host.com/somewhere/to/");
    HttpURLConnection con = (HttpURLConnection) url.openConnection();

    //  CURLOPT_POST
    con.setRequestMethod("POST");

    // CURLOPT_FOLLOWLOCATION
    con.setInstanceFollowRedirects(true);

    String postData = "my_data_for_posting";
    con.setRequestProperty("Content-length", String.valueOf(postData.length()));

    con.setDoOutput(true);
    con.setDoInput(true);

    DataOutputStream output = new DataOutputStream(con.getOutputStream());
    output.writeBytes(postData);
    output.close();

    // "Post data send ... waiting for reply");
    int code = con.getResponseCode(); // 200 = HTTP_OK
    System.out.println("Response    (Code):" + code);
    System.out.println("Response (Message):" + con.getResponseMessage());

    // read the response
    DataInputStream input = new DataInputStream(con.getInputStream());
    int c;
    StringBuilder resultBuf = new StringBuilder();
    while ( (c = input.read()) != -1) {
        resultBuf.append((char) c);
    }
    input.close();

    return resultBuf.toString();
}

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我不太确定HTTPS\u VERIFYPEER-thing，但这可能会给你一个起点。

你尝试过什么吗？@TAsk基本上它会发送一个xml字符串到link，并从中得到响应，而在php中我取消了CURL\u VERIFYPEER=0。将一个字节转换为一个字符是个坏主意。