使用Java，.equalsIgnoreCase不'；两个字不行。我怎么修理？

该程序适用于除高激活和稍微激活外的所有变量。我似乎不明白为什么，但我相信这和.equalsIgnoreCase有关

导入java.util.Scanner； 公共类BMI{

public static void main(String[] args) {
    // TODO Auto-generated method stub

    Scanner keyboard = new Scanner(System.in);
    System.out.println("Welcome to the BMR calculator!");
    System.out.println("Are you male or female? Enter m or f.");
    String gender = keyboard.next();
    System.out.println("How tall are you in inches?");
    int height = keyboard.nextInt();
    System.out.println("How much do you weigh in pounds?");
    int weight = keyboard.nextInt();
    System.out.println("How old are you in years?");
    int age = keyboard.nextInt();
    System.out.println("How would you describe your lifestyle? \"Sedentary\", \"Somewhat Active\", \"Active\", or \"Highly Active\"?");
    String active = keyboard.next();
        // This gets all the necessary information to calculate the BMI.

    if (gender.equalsIgnoreCase("f")) //If the person is female BMR = 655 + (4.3 x weight in pounds) + (4.7 x height in inches) – (4.7 x age in years) 
    {
        if (active.equalsIgnoreCase("Sedentary"))
        {
            double BMR = (655 + (4.3 * weight) + (4.7 * height) - (4.7 * age)) * 1.2;
            System.out.println("Your BMR is " +BMR+ " calories!");
        }
        ///My issue occurs here I think.
        else if (active.equalsIgnoreCase("Somewhat Active"))

        {
            double BMR = (655 + (4.3 * weight) + (4.7 * height) - (4.7 * age)) * 1.3;
            System.out.println("Your BMR is " +BMR+ " calories!");
        }
        else if (active.equalsIgnoreCase("Active"))
        {
            double BMR = (655 + (4.3 * weight) + (4.7 * height) - (4.7 * age)) * 1.4;
            System.out.println("Your BMR is " +BMR+ " calories!");
        }
        else if (active.equalsIgnoreCase("Highly Active"))
        {
            double BMR = (655 + (4.3 * weight) + (4.7 * height) - (4.7 * age)) * 1.5;
            System.out.println("Your BMR is " +BMR+ " calories!");
        }
    }       
    else if (gender.equalsIgnoreCase("m")) //If the person is male BMR = 66 + (6.3 x weight in pounds) + (12.9 x height in inches) – (6.8 x age in years)
        {
            if (active.equalsIgnoreCase("Sedentary"))
            {
                double BMR = (66 + (6.3 * weight) + (12.9 * height) - (6.8 * age)) * 1.2;
                System.out.println("Your BMR is " +BMR+ " calories!");
            }
            else if (active.equalsIgnoreCase("Somewhat Active"))
            {
                double BMR = (66 + (6.3 * weight) + (12.9 * height) - (6.8 * age)) * 1.3;
                System.out.println("Your BMR is " +BMR+ " calories!");
            }
            else if (active.equalsIgnoreCase("Active"))
            {
                double BMR = (66 + (6.3 * weight) + (12.9 * height) - (6.8 * age)) * 1.4;
                System.out.println("Your BMR is " +BMR+ " calories!");
            }
            else if (active.equalsIgnoreCase("Highly Active"))
            {
                double BMR = (66 + (6.3 * weight) + (12.9 * height) - (6.8 * age)) * 1.5;
                System.out.println("Your BMR is " +BMR+ " calories!");
            }
        }
    }
}

keyboard.next（）

仅检索单词

部分

。使用

nextLine

检索整个输入：

int age = keyboard.nextInt();
keyboard.nextLine();
System.out.println("How would you describe your lifestyle? \"Sedentary\", \"Somewhat Active\", \"Active\", or \"Highly Active\"?");
String active = keyboard.nextLine();

keyboard.next（）

仅检索单词

部分

。使用

nextLine

检索整个输入：

int age = keyboard.nextInt();
keyboard.nextLine();
System.out.println("How would you describe your lifestyle? \"Sedentary\", \"Somewhat Active\", \"Active\", or \"Highly Active\"?");
String active = keyboard.nextLine();

这是为您准备的。不要将keyboard.next（）用于active和skip\n

---

这是给你的。不要使用键盘。下一步（）对于active和skip\n.

我怀疑String.equalsIgnoreCase是否有问题，它和hills一样旧。请根据硬编码字符串仔细检查您的输入。确保它包含您认为它包含的文本。查找额外的空格，使用制表符而不是空格，反之亦然。调试器，或打印st以整数的形式打电话会对您有所帮助。为什么不为您的选项使用编号，这会让您的生活更轻松。例如，1用于久坐等。我怀疑String是否有问题。equalsIgnoreCase，它与hills一样古老。请根据硬编码字符串仔细检查您的输入。确保它包含您认为有问题的文本。请看对于额外的空白，使用制表符而不是空格，反之亦然。调试器或将字符串打印为整数将对您有所帮助。为什么不使用选项编号将使您的生活更加轻松。例如，1用于久坐等。这是有意义的。但如果我将其切换到nextLine（）当被问及我的生活方式时，我无法输入任何内容。@NiklasHopper为此，您需要添加一个额外的

键盘。nextLine（）

在获得

年龄后

如图所示，阅读键入年龄后输入的新行。太好了！谢谢。我整个上午都在试图解决这个问题。这是有道理的。但是如果我切换到nextLine（）当被问及我的生活方式时，我无法输入任何内容。@NiklasHopper为此，您需要在获得

年龄后添加一个额外的
键盘.nextLine（）；
，如图所示，以阅读您在输入年龄后输入的新行。太好了！谢谢。我整个上午都在努力解决这个问题。