Java 为什么Scanner#nextInt inside for loop不断抛出异常?

Java 为什么Scanner#nextInt inside for loop不断抛出异常?,java,java.util.scanner,Java,Java.util.scanner,我一直在学习JAVA,我对代码有点怀疑: class apple { public static void main(String[] args) { int[] num = new int[3]; Scanner input = new Scanner(System.in); for (int i = 0; i < num.length; i++) { try { num

我一直在学习JAVA,我对代码有点怀疑:

class apple {
    public static void main(String[] args) {

        int[] num = new int[3];

        Scanner input = new Scanner(System.in);
        for (int i = 0; i < num.length; i++) {

            try {
                num[i] = input.nextInt();
            } catch (Exception e) {
                System.out
                    .println("Invalid number..assigning default value 20");
            num[i] = 20;
            }
        }

        for (int i = 0; i < num.length; i++) {
            System.out.println(num[i]);
        }
    }
}
我希望你们已经理解了我的问题。

如果无法解析整数,它不会超越输入,因此如果失败后继续调用它,它将继续尝试再次解析相同的输入,抛出
InputMismatchException

您可以忽略它返回的字符串,在
catch
块中调用以跳过无效输入:

try {
    num[i] = input.nextInt();
} catch (Exception e) {
    System.out
            .println("Invalid number..assigning default value 20");
    num[i] = 20;
    input.next();
}

更好的代码是,您可以检查下一个值是否为整数,这样您甚至不需要捕获异常:

   public static void main(String[] args) {

    int[] num = new int[3];

   Scanner input = new Scanner(System.in);  

    for (int i = 0; i < num.length; i++) 
     {
             if(input.hasNextInt())
             {
                  num[i] = input.nextInt();
             }

            else
            {
                System..out.println("non integer value.. will assign it default value 20");
                num[i]=20;
                input.next();
            }
    }

    for (int i = 0; i < num.length; i++) {

        System.out.println(num[i]);
    }


  }
publicstaticvoidmain(字符串[]args){
int[]num=新的int[3];
扫描仪输入=新扫描仪(System.in);
for(int i=0;i
这就是您的意思吗,它仍然会结转相同的值并引发异常<代码>尝试{num[i]=input.nextInt();}catch(异常e){System.out.println(“错误的值。请重试”);num[i]=input.nextInt();}+1但您应该添加一些代码解释。
        try
        {
            num[i] = input.nextInt();
        }
        catch(InputMismatchException ip)
        {
            System.out.println("Invalid number..assigning default value 20");
            num[i] = 20;
            input.next();
        }
   public static void main(String[] args) {

    int[] num = new int[3];

   Scanner input = new Scanner(System.in);  

    for (int i = 0; i < num.length; i++) 
     {
             if(input.hasNextInt())
             {
                  num[i] = input.nextInt();
             }

            else
            {
                System..out.println("non integer value.. will assign it default value 20");
                num[i]=20;
                input.next();
            }
    }

    for (int i = 0; i < num.length; i++) {

        System.out.println(num[i]);
    }


  }