在android Java中,截击请求只执行一次
我提出这样的截击要求。我想根据arraylist的大小执行一次或多次post命令。但是执行此代码只执行一次截击命令 这是我试过的在android Java中,截击请求只执行一次,java,android,android-volley,Java,Android,Android Volley,我提出这样的截击要求。我想根据arraylist的大小执行一次或多次post命令。但是执行此代码只执行一次截击命令 这是我试过的 for(int i = 0; i<listofobjects.size(); i++){ makeRequest(listobjects.get(i)); } public void makeRequest(Customobject obj){ RequestQueue requestQueue = Volley.newRequestQueue(
for(int i = 0; i<listofobjects.size(); i++){
makeRequest(listobjects.get(i));
}
public void makeRequest(Customobject obj){
RequestQueue requestQueue = Volley.newRequestQueue(this);
String modifiedUrl = MainActivity.URL + "XXXXX";
StringRequest stringRequest = new StringRequest(Request.Method.POST, modifiedUrl, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.v("Response", response);
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.v("Error", error.toString());
}
})};
requestQueue.add(stringRequest);
}
for(inti=0;i试试这个:
public void makeRequest(Customobject obj){
boolean status = true;
int i=0;
do
{
RequestQueue requestQueue = Volley.newRequestQueue(this);
String modifiedUrl = MainActivity.URL + "XXXXX";
StringRequest stringRequest = new StringRequest(Request.Method.POST, modifiedUrl, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
status = true;
Log.v("Response", response);
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
status = true;
Log.v("Error", error.toString());
}
})};
if(status)
{
requestQueue.add(stringRequest);
i++;
status =false;
}
}while(i<listofobjects.size());
}
public void生成请求(Customobject obj){
布尔状态=真;
int i=0;
做
{
RequestQueue RequestQueue=Volley.newRequestQueue(this);
字符串modifiedUrl=MainActivity.URL+“XXXXX”;
StringRequest StringRequest=new StringRequest(Request.Method.POST、modifiedUrl、new Response.Listener()){
@凌驾
公共void onResponse(字符串响应){
状态=真;
Log.v(“响应”,响应);
}
},new Response.ErrorListener(){
@凌驾
公共无效onErrorResponse(截击错误){
状态=真;
Log.v(“Error”,Error.toString());
}
})};
如果(状态)
{
添加(stringRequest);
i++;
状态=假;
}
}而(i试试这个:
public void makeRequest(Customobject obj){
boolean status = true;
int i=0;
do
{
RequestQueue requestQueue = Volley.newRequestQueue(this);
String modifiedUrl = MainActivity.URL + "XXXXX";
StringRequest stringRequest = new StringRequest(Request.Method.POST, modifiedUrl, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
status = true;
Log.v("Response", response);
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
status = true;
Log.v("Error", error.toString());
}
})};
if(status)
{
requestQueue.add(stringRequest);
i++;
status =false;
}
}while(i<listofobjects.size());
}
public void生成请求(Customobject obj){
布尔状态=真;
int i=0;
做
{
RequestQueue RequestQueue=Volley.newRequestQueue(this);
字符串modifiedUrl=MainActivity.URL+“XXXXX”;
StringRequest StringRequest=new StringRequest(Request.Method.POST、modifiedUrl、new Response.Listener()){
@凌驾
公共void onResponse(字符串响应){
状态=真;
Log.v(“响应”,响应);
}
},new Response.ErrorListener(){
@凌驾
公共无效onErrorResponse(截击错误){
状态=真;
Log.v(“Error”,Error.toString());
}
})};
如果(状态)
{
添加(stringRequest);
i++;
状态=假;
}
}而
调用这个函数
makeRequest(listobjects.get(i));
makeRequest方法将被递归调用
public void makeRequest(Customobject obj){
RequestQueue requestQueue = Volley.newRequestQueue(this);
String modifiedUrl = MainActivity.URL + "XXXXX";
StringRequest stringRequest = new StringRequest(Request.Method.POST, modifiedUrl, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.v("Response", response);
i++;
if(i < listobjects.size()){
// make a recursive function
makeRequest(listobjects.get(i));
} else {
// Completed
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.v("Error", error.toString());
}
})};
requestQueue.add(stringRequest);
}
public void生成请求(Customobject obj){
RequestQueue RequestQueue=Volley.newRequestQueue(this);
字符串modifiedUrl=MainActivity.URL+“XXXXX”;
StringRequest StringRequest=new StringRequest(Request.Method.POST、modifiedUrl、new Response.Listener()){
@凌驾
公共void onResponse(字符串响应){
Log.v(“响应”,响应);
i++;
if(i
调用这个函数
makeRequest(listobjects.get(i));
makeRequest方法将被递归调用
public void makeRequest(Customobject obj){
RequestQueue requestQueue = Volley.newRequestQueue(this);
String modifiedUrl = MainActivity.URL + "XXXXX";
StringRequest stringRequest = new StringRequest(Request.Method.POST, modifiedUrl, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.v("Response", response);
i++;
if(i < listobjects.size()){
// make a recursive function
makeRequest(listobjects.get(i));
} else {
// Completed
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.v("Error", error.toString());
}
})};
requestQueue.add(stringRequest);
}
public void生成请求(Customobject obj){
RequestQueue RequestQueue=Volley.newRequestQueue(this);
字符串modifiedUrl=MainActivity.URL+“XXXXX”;
StringRequest StringRequest=new StringRequest(Request.Method.POST、modifiedUrl、new Response.Listener()){
@凌驾
公共void onResponse(字符串响应){
Log.v(“响应”,响应);
i++;
if(i
我想这个方法会解决你的问题
int i = 0;
makeRequest(listObjects.get(i));
public void makeRequest(Customobject obj){
RequestQueue requestQueue = Volley.newRequestQueue(this);
String modifiedUrl = MainActivity.URL + "XXXXX";
StringRequest stringRequest = new StringRequest(Request.Method.POST, modifiedUrl, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.v("Response", response);
if(reposnse==success && i<listobjects.size){
i++;
makeRequest(listObjects.get(i));
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.v("Error", error.toString());
}
})};
requestQueue.add(stringRequest);
}
inti=0;
makeRequest(listObjects.get(i));
公共作废生成请求(Customobject obj){
RequestQueue RequestQueue=Volley.newRequestQueue(this);
字符串modifiedUrl=MainActivity.URL+“XXXXX”;
StringRequest StringRequest=new StringRequest(Request.Method.POST、modifiedUrl、new Response.Listener()){
@凌驾
公共void onResponse(字符串响应){
Log.v(“响应”,响应);
如果(resosnse==success&&i我想这个方法会解决你的问题
int i = 0;
makeRequest(listObjects.get(i));
public void makeRequest(Customobject obj){
RequestQueue requestQueue = Volley.newRequestQueue(this);
String modifiedUrl = MainActivity.URL + "XXXXX";
StringRequest stringRequest = new StringRequest(Request.Method.POST, modifiedUrl, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.v("Response", response);
if(reposnse==success && i<listobjects.size){
i++;
makeRequest(listObjects.get(i));
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.v("Error", error.toString());
}
})};
requestQueue.add(stringRequest);
}
inti=0;
makeRequest(listObjects.get(i));
公共作废生成请求(Customobject obj){
RequestQueue RequestQueue=Volley.newRequestQueue(this);
字符串modifiedUrl=MainActivity.URL+“XXXXX”;
StringRequest StringRequest=new StringRequest(Request.Method.POST、modifiedUrl、new Response.Listener()){
@凌驾
公共void onResponse(字符串响应){
Log.v(“响应”,响应);
如果(resosnse==success&&iYou最终将在无限循环中运行。请记住,volley是异步的,while循环不会等待迭代的响应。您的新代码更改与问题中的代码更改相同。您只是对循环到while循环进行了重构。我没有看到任何增强,它仍然是一个无限运行的循环,带有一个布尔值使t他调用。检查其他解决方案,它们不使用无限循环,而是对响应进行处理。您最终将在无限循环中运行。请记住,volley是异步的,while循环不会等待响应迭代。您的新代码更改与问题中所问的相同。您只是对循环到while循环进行了重构。我没有看到任何增强功能nt,它仍然是一个带有布尔值的无限运行循环来进行调用。检查其他解决方案,它们不使用无限循环,而是处理响应。可能您的截击单例取消了对以前相同URL的请求。您需要进行更改,以便将响应序列化。可能您的截击单例取消了对相同URL的请求您需要进行更改以便序列化响应。