Java json简单容器工厂
使用containerFactory的解码示例,我得到以下输出:Java json简单容器工厂,java,json-simple,Java,Json Simple,使用containerFactory的解码示例,我得到以下输出: [{DeviceType=foo, DeviceName=foo1, IPAddress=192.168.1.1, UserName=admin, Password=pw}, {DeviceType=foo, DeviceName=foo2, IPAddress=192.168.1.2, UserName=admin, Password=pw}] 这些是调用entry.getValue()时输出的条目 如何从这些对象中获
[{DeviceType=foo, DeviceName=foo1, IPAddress=192.168.1.1, UserName=admin, Password=pw}, {DeviceType=foo, DeviceName=foo2, IPAddress=192.168.1.2, UserName=admin, Password=pw}]
这些是调用entry.getValue()时输出的条目
如何从这些对象中获取数据
例如,如何获取DeviceName的值
Map obj = (Map)parser.parse(new FileReader("example.yml"),containerFactory);
Iterator iter = obj.entrySet().iterator();
//Iterator iterInner = new Iterator();
while(iter.hasNext()){
Map.Entry entry = (Map.Entry)iter.next();
System.out.println(entry.getValue());
}
//System.out.println("==toJSONString()==");
//System.out.println(JSONValue.toJSONString(json));
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch(ParseException pe){
System.out.println(pe);
}
尝试使用
System.out.println(entry.getValue().getClass())
(或在调试器中检查)找出值所在的类以及实际类的值。从输出来看,它看起来像是List
或其他什么东西。ahhh…好主意!输出是java.lang.String类。在第一个parser.parse语句中是否有方法将其转换为键值对?
//The innermost data is in a LinkedHashMap
//I hope this snippet helps someone
while(iter.hasNext)
{
LinkedList entry = (LinkedList)iter.next();
LinkedList myList = new LinkedList();
Map.Entry entry = (Map.Entry)iter.next();
System.out.println(entry.getValue().getClass());
myList = (LinkedList) (entry.getValue());
System.out.println(myList);
Iterator iterate = myList.iterator();
while (iterate.hasNext())
{
LinkedHashMap entry2 = (LinkedHashMap)iterate.next();
System.out.println(entry2.get("DeviceName"));
}
}