Java中的Math.pow和Math.sqrt

好的，我发现了两个短代码，但我想了解它们是如何工作的。我在谷歌上搜索并查看了以下链接：

但其中的解释并不清楚。换句话说，我希望知道/理解这两个代码的每一行都发生了什么

A下面的程序片段计算给定的整数数组数据，并打印数据中所有条目的几何平均值：

   double product = 1;// For example, I understand why it is 1, since if it was 0 then the product would be keep getting 0, since any number *0 is always zero.
    for(int i=0; i<data.length; i++)//okay for loop is getting out all the intergers from the data array.
    product*=data[i];//This is I am not too sure, I guess each item in array is getting multiplied with each other????
    double gmean=Math.pow(product,1.0/data.length); // Yes, I hate this line, because I don't understand it, can someone explain this line please? Please use easy English, I am not as smart as you.

double sum=0; //Okay the sum should be 0 because at the moment nothing has been summed up.
for(int i=0; i<data.length; i++)// Now getting out all the items in array called data.
sum+= data[i]*data[i];//Now I am not too sure, all the items in the array called data is getting multiplied with each other and then getting added up? I am not too sure, if would be good if someone could explain this with easy English.
double qmean = Math.sqrt(sum/data.length);// I hate this line, because I don't understand it.
System.out.println(qmean);// Displays the final result.

B第二个代码段计算给定的整数数组数据，并打印数据中所有条目的二次平均值：

   double product = 1;// For example, I understand why it is 1, since if it was 0 then the product would be keep getting 0, since any number *0 is always zero.
    for(int i=0; i<data.length; i++)//okay for loop is getting out all the intergers from the data array.
    product*=data[i];//This is I am not too sure, I guess each item in array is getting multiplied with each other????
    double gmean=Math.pow(product,1.0/data.length); // Yes, I hate this line, because I don't understand it, can someone explain this line please? Please use easy English, I am not as smart as you.

double sum=0; //Okay the sum should be 0 because at the moment nothing has been summed up.
for(int i=0; i<data.length; i++)// Now getting out all the items in array called data.
sum+= data[i]*data[i];//Now I am not too sure, all the items in the array called data is getting multiplied with each other and then getting added up? I am not too sure, if would be good if someone could explain this with easy English.
double qmean = Math.sqrt(sum/data.length);// I hate this line, because I don't understand it.
System.out.println(qmean);// Displays the final result.

好的，正如你所看到的，我确实理解代码中的一些行，但也有一些行，我不理解，如果有人能解释这些行，那就太棒了，我没有用简单的英语理解，也没有用复杂的方式

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提前谢谢。

数学。powa，b表示a^b，而math.sqrta是a的平方根。您不了解内容中的java方法或数学逻辑？

假设数据为{3,2,7}。数据长度为3。这将计算sqrt9+4+49/3

double sum=0;
// sum is now zero

for(int i=0; i<data.length; i++)
// Execute the following statement with i having each value starting from 0,
// incrementing by 1 each time (i++), as long as i remains less than 3.
    sum+= data[i]*data[i];
    // The sum+= statement is executed three times, with i each of 0, 1, and 2.
    // The first time adds 9 to sum getting 9
    // The second time adds 4 to sum getting 13
    // The third time adds 49 to sum, getting 62

double qmean = Math.sqrt(sum/data.length);
// make qmean equal to sqrt(62/3).

System.out.println(qmean);// Displays the final result.

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这只是简单的数学，将和RMS的公式转换为Java代码。您已经承认第一个代码确定几何平均值，第二个确定二次平均值。@NullUserException，谢谢您的回答，但您知道，我没有您那么聪明，虽然您觉得简单，但我觉得非常困难，我很难理解代码中的某些行，这就是为什么我会善意地询问是否有人能够逐一解释我不理解的行，因为这是唯一能帮助我的事情。@Acemi，我不是有意屈尊；但是，如果您知道平均值的公式，那么理解代码应该非常简单。您看过Math api吗？这些方法实际上没有做任何名称在内容中没有告诉你的事情，只是：double gmean=Math.powproduct，1.0/data.length；=product^1/data.length它只是一个数学java代码，表示一个数字的有效性，double qmean=Math.sqrtsum/data.length；是sum的data.length平方根吗？我们可以这么说，这些代码实际上就像烹饪食谱？另外，如果我想检查数据[]={1,2,3}这3个整数的两个代码，我该如何修改这两个代码？请注意，这个答案中的2^3表示2，其中3为上标。^也是Java的异或运算符，但这里不是这样使用的。