(Java)HTTP GET请求不断获得400个响应代码,尽管该链接在浏览器中运行良好
我正在尝试使用HTTP从Google Trends获取JSON响应。这是我的代码片段:(Java)HTTP GET请求不断获得400个响应代码,尽管该链接在浏览器中运行良好,java,rest,http,httpurlconnection,Java,Rest,Http,Httpurlconnection,我正在尝试使用HTTP从Google Trends获取JSON响应。这是我的代码片段: public class TestClass { public static void main(String[] args) throws Exception{ String address = "https://trends.google.com/trends/api/explore?hl=en-US&tz=240&req={\"comparisonItem\":[{\"
public class TestClass {
public static void main(String[] args) throws Exception{
String address = "https://trends.google.com/trends/api/explore?hl=en-US&tz=240&req={\"comparisonItem\":[{\"keyword\":\"Miley\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"},{\"keyword\":\"Hannah Montana\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"}],\"category\":0,\"property\":\"\"}";
URL url = new URL(address);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setRequestMethod("GET");
int responseCode = con.getResponseCode();
System.out.println("URL is "+address);
System.out.println("Response code is " + responseCode); }
}
这是输出:
URL is https://trends.google.com/trends/api/explore?hl=en-US&tz=240&req={"comparisonItem":[{"keyword":"Miley","geo":"US","time":"2012-01-01 2014-01-01"},{"keyword":"Hannah Montana","geo":"US","time":"2012-01-01 2014-01-01"}],"category":0,"property":""}
Response code is 400
如果我直接在浏览器中键入URL,Google会毫无问题地给我一个JSON文件。然而,如果我试图使用Java访问该URL,我会收到一个错误的请求。我怎样才能解决这个问题?提前感谢。您需要对URL的查询字符串部分进行URL编码。查看一些实现此目的的方法。您需要对URL的查询字符串部分进行URL编码。查看一些实现此目的的方法。我解决了您的问题。我强烈建议构建在ApacheHTTPAPI上
private static final HttpRequest<String> REQUEST =
HttpRequestBuilder.createGet("https://trends.google.com/trends/api/explore", String.class)
.addDefaultRequestParameter("hl", "en-US")
.addDefaultRequestParameter("tz", "240")
.responseDeserializer(ResponseDeserializer.ignorableDeserializer())
.build();
public void send() {
ResponseHandler<String> responseHandler = REQUEST.execute("req", "{\"comparisonItem\":[{\"keyword\":\"Miley\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"},{\"keyword\":\"Hannah Montana\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"}],\"category\":0,\"property\":\"\"}");
System.out.println(responseHandler.getStatusCode());
responseHandler.ifHasContent(System.out::println);
}
私有静态最终HttpRequest请求=
HttpRequestBuilder.createGet(“https://trends.google.com/trends/api/explore“,String.class)
.addDefaultRequestParameter(“hl”、“en-US”)
.addDefaultRequestParameter(“tz”,“240”)
.responseDeserializer(responseDeserializer.ignorableDeserializer())
.build();
公共无效发送(){
ResponseHandler ResponseHandler=REQUEST.execute(“req”、“{”comparisonItem\”:[{”关键字“:”麦莉“,”地理“:”美国“,”时间“:”2012-01-01 2014-01-01-01\”,“{”关键字“:”汉娜·蒙塔纳“,”地理“:”美国“,”时间“:”2012-01-01-01 2014-01-01\”,”类别“:”0,“,”财产“:”;
System.out.println(responseHandler.getStatusCode());
responseHandler.ifHasContent(System.out::println);
}
代码将打印您通过浏览器获得的响应代码200和响应正文。我解决了您的问题。我强烈建议构建在ApacheHTTPAPI上
private static final HttpRequest<String> REQUEST =
HttpRequestBuilder.createGet("https://trends.google.com/trends/api/explore", String.class)
.addDefaultRequestParameter("hl", "en-US")
.addDefaultRequestParameter("tz", "240")
.responseDeserializer(ResponseDeserializer.ignorableDeserializer())
.build();
public void send() {
ResponseHandler<String> responseHandler = REQUEST.execute("req", "{\"comparisonItem\":[{\"keyword\":\"Miley\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"},{\"keyword\":\"Hannah Montana\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"}],\"category\":0,\"property\":\"\"}");
System.out.println(responseHandler.getStatusCode());
responseHandler.ifHasContent(System.out::println);
}
私有静态最终HttpRequest请求=
HttpRequestBuilder.createGet(“https://trends.google.com/trends/api/explore“,String.class)
.addDefaultRequestParameter(“hl”、“en-US”)
.addDefaultRequestParameter(“tz”,“240”)
.responseDeserializer(responseDeserializer.ignorableDeserializer())
.build();
公共无效发送(){
ResponseHandler ResponseHandler=REQUEST.execute(“req”、“{”comparisonItem\”:[{”关键字“:”麦莉“,”地理“:”美国“,”时间“:”2012-01-01 2014-01-01-01\”,“{”关键字“:”汉娜·蒙塔纳“,”地理“:”美国“,”时间“:”2012-01-01-01 2014-01-01\”,”类别“:”0,“,”财产“:”;
System.out.println(responseHandler.getStatusCode());
responseHandler.ifHasContent(System.out::println);
}
代码将打印您通过浏览器获得的响应代码200和响应正文。您能否尝试不反斜杠转义url字符串中的双引号?尝试使用单引号,看看会发生什么?@DanielH.J。我刚试过,但没有成功如果我读对了,你是说当你把代码输出的URL粘贴到浏览器中时,它会打开?@fuzzyblankey是的,你能试着不反斜杠转义URL字符串中的双引号吗?尝试使用单引号,看看会发生什么?@DanielH.J。我刚试过,但没有成功如果我读对了,你是说当你将代码输出的URL粘贴到浏览器时,它会打开?@fuzzyblankey是的