Java 将最后的所有元素拆分并存储到一个数组中

我想将检索到的字符串值存储到一个数组或列表中，然后对它们进行排序。我尝试了许多方法以上述方式存储它们。但没有任何帮助。有人能在这方面帮助我吗

List<WebElement> list = webDriver.findElements(By.xpath(expression));
int listcount = list.size();    
List optionsList = null;
String options[] = new String[listcount];

for (int i=1; i<=listcount; i++) {                     
    options[i-1] = webDriver.findElement(By.xpath("expression")).getText();
    //contains three words eg: Test Engineer Madhu               
    String[] expectedOptions = options[i-1].split(" ");
    //splitting based on the space           
    String lastName =expectedOptions[expectedOptions.length-1]; 
    //taking the lastName.
    List<String> strArray = new ArrayList<String>();
    for (int k = 0; k < i; k++) {
       strArray.add(lastName);        
    }
    optionsList = Arrays.asList(lastName);
}          
System.out.println(optionsList);
//This always results in last option's last name eg: [Madhu]
}      

List List=webDriver.findElements（By.xpath（expression））；
int listcount=list.size（）；
列表选项列表=空；
字符串选项[]=新字符串[listcount]；
对于（inti=1；i，这里是用于获取数组中所有姓氏的修改代码

List<WebElement> list = webDriver.findElements(By.xpath(expression));
int listcount = list.size();    
List optionsList = null;
String options[] = new String[listcount];

for (int i=1; i<=listcount; i++) 
{                     
    options[i-1] = webDriver.findElement(By.xpath("expression")).getText();
    //contains three words eg: Test Engineer Madhu               
    String[] expectedOptions = options[i-1].split(" ");
    //splitting based on the space           
    // I hope the next line gives you the correct lastName
    String lastName =expectedOptions[expectedOptions.length-1]; 
    // lets store the last name in the array
    options[i-1] = lastName;        
 }         
 optionsList = Arrays.asList(options);
 // Iterate through the list to see all last names.

List List=webDriver.findElements（By.xpath（expression））；
int listcount=list.size（）；
列表选项列表=空；
字符串选项[]=新字符串[listcount]；
对于（int i=1；i您可以修改代码，如下所示：

for (int i=1; i<=listcount; i++) {  
        //contains three words eg: Test Engineer Madhu               
        String[] expectedOptions = options[i-1].split(" ");
        //splitting based on the space           
        String lastName =expectedOptions[expectedOptions.length-1]; 
        //taking the lastName.
        options[i - 1] = lastName;
    }
    optionsList = Arrays.asList(options); 
    System.out.println(optionsList);

for（int i=1；i您面临的问题是什么？我尝试了以下代码。但它总是只存储上次检索选项的姓氏。List strArray=new ArrayList（）；for（int k=0；koptions[i-1]=webDriver.findElement（By.xpath（“表达式”）.getText（）；
尝试
options[i-1]=list.get（i-1.getText（）；
选项[i-1]没有问题。相反，无法将检索到的姓氏存储到列表中。是否调试代码并检查数组
expectedOptions
是否正确填充？是的，Harbeer也提供了相同的解决方案。感谢您的帮助。