Java 交叉连接
我使用以下SQL命令搜索特定日期内的可用房间:Java 交叉连接,java,sql,hibernate,hql,Java,Sql,Hibernate,Hql,我使用以下SQL命令搜索特定日期内的可用房间: select k.nr from room k where not exists (select 'x' from room_reserveration as kr INNER JOIN reserveration as r ON (r.reserveration_id = kr.reserveration_id) INNER JOIN hotel as h ON (h.hotel_id = r.hotel_id) where k.roo
select k.nr from room k
where not exists (select 'x' from room_reserveration as kr
INNER JOIN reserveration as r ON (r.reserveration_id = kr.reserveration_id)
INNER JOIN hotel as h ON (h.hotel_id = r.hotel_id)
where k.room_id = kr.room_id AND (r.begin_date between "2012-06-18" and "2012-06-27" ) and (r.end_date between "2012-06-18" and "2012-06-27" )
)
我试着转换成HQL:
session.createQuery("select k.nr from room k where not exists
(select 'x' from RoomReserveration kr, Reserveration r
join kr.Reserveration join k.hotel join kr.room
where (r.begin_date between '2012-06-18' and '2012-06-27' ) and
(r.eind_date between '2012-06-18' and '2012-06-27' ) )");
如果我编译java代码,我会得到以下输出:
Hibernate: select Room0_.nr as col_0_0_ from Room Room0_ where not (exists (select 'x' from Room_reservation Roomreser1_ inner join reservation reservation3_ on Roomreser1_.reservation_id=reservation3_.reservation_id inner join Room Room5_ on Roomreser1_.Room_id=Room5_.Room_id cross join reservation reservation2_ where (reservation2_.begin_date between '2012-06-18' and '2012-06-27') and (reservation2_.eind_date between '2012-06-18' and '2012-06-27')))
为什么在这里添加交叉连接却没有结果
映射:
客房预订:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="model.RoomReservation" table="room_reservation">
<id name="room_reservation_id">
<generator class="identity"/>
</id>
<property name="details"/>
<many-to-one name="reservation" column="reservation_id" />
<many-to-one name="room" column="room_id" />
</class>
</hibernate-mapping>
保留地
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="model.Reservation" table="reservation">
<id name="reservation_id">
<generator class="identity"/>
</id>
<property name="date_reservation" type="java.util.Date"/>
<property name="begin_date" type="java.util.Date"/>
<property name="eind_date" type="java.util.Date"/>
<set name="roomReservation" inverse="true">
<key column="reservation_id"/>
<one-to-many class="model.RoomReservation"/>
</set>
<many-to-one name="hotel" column="hotel_id" />
</class>
</hibernate-mapping>
房间
酒店:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="model.Hotel" table="hotel">
<id name="hotel_id">
<generator class="identity"/>
</id>
<property name="name"/>
<set name="rooms">
<key column="hotel_id"/>
<one-to-many class="model.Room"/>
</set>
</class>
</hibernate-mapping>
交叉连接来自这样一个事实,即您正在与
select 'x' from RoomReserveration kr, Reserveration r
查询应为:
select room.nr from Room room where not exists
(select 'x' from RoomReservation roomReservation
join roomReservation.reservation reservation
join reservation.hotel hotel
where (reservation.begin_date between '2012-06-18' and '2012-06-27')
and (reservation.eind_date between '2012-06-18' and '2012-06-27')
and roomReservation.room = room)
请注意,除了没有任何酒店的tofilter预订外,与hotel的连接没有任何用途。交叉连接是因为您与
select 'x' from RoomReserveration kr, Reserveration r
查询应为:
select room.nr from Room room where not exists
(select 'x' from RoomReservation roomReservation
join roomReservation.reservation reservation
join reservation.hotel hotel
where (reservation.begin_date between '2012-06-18' and '2012-06-27')
and (reservation.eind_date between '2012-06-18' and '2012-06-27')
and roomReservation.room = room)
请注意,与hotel的连接没有任何用途,只有tofilter预订没有任何酒店。我认为HQL连接与SQL连接的含义不同。实体映射将有助于解决这个问题。我不认为HQL连接与SQL连接的含义相同。实体映射将有助于为解决此问题提供一些帮助。