Java 从neo4J语句中提取关系Result

如何从语句Result中提取关系

目前我有这样的想法：

while (results.hasNext()) {
        Record record = results.next();
        try {
            if (record.get(0).hasType(TYPE_SYSTEM.NODE())){
                Node node = record.get(0).asNode();
                //System.out.println(node.get("name") + ": " + node.get("guid"));

                // Add block
                if (node.hasLabel(configuration.getBlock())) {
                    Block block = Block.fromRecord(node);
                    blocks.addBlock(block);
                } else
                // Add property
                if (node.hasLabel(configuration.getProp())) {
                    Property property = Property.fromRecord(node);
                    String guid = property.getGuid();
                    Block block = blocks.getBlock(guid);
                    block.addProperty(property);
                } else
                // Add output
                if (node.hasLabel(configuration.getOutput())) {
                    Output output = Output.fromRecord(node);
                    String guid = output.getGuid();
                    Block block = blocks.getBlock(guid);
                    block.addOutput(output);
                } else
                // Add input
                if (node.hasLabel(configuration.getInput())) {
                    Input input = Input.fromRecord(node);
                    inputs.add(input);
                    String guid = input.getGuid();
                }

            }

MATCH (start:Block{name:'block_3'})
CALL apoc.path.subgraphNodes(start, {relationshipFilter:'PART_OF|hasOutPort>|connectsTo>|<hasInPort'}) YIELD node as block
WITH
  block,
  [(block)-[:PART_OF]->(prop) | prop] as properties,
  [(block)-[:hasOutPort]->(output) | output] as outputs,
  [(block)-[:hasInPort]->(input) | input] as inputs
RETURN block, properties, outputs, inputs

我最初的查询是这样的：

while (results.hasNext()) {
        Record record = results.next();
        try {
            if (record.get(0).hasType(TYPE_SYSTEM.NODE())){
                Node node = record.get(0).asNode();
                //System.out.println(node.get("name") + ": " + node.get("guid"));

                // Add block
                if (node.hasLabel(configuration.getBlock())) {
                    Block block = Block.fromRecord(node);
                    blocks.addBlock(block);
                } else
                // Add property
                if (node.hasLabel(configuration.getProp())) {
                    Property property = Property.fromRecord(node);
                    String guid = property.getGuid();
                    Block block = blocks.getBlock(guid);
                    block.addProperty(property);
                } else
                // Add output
                if (node.hasLabel(configuration.getOutput())) {
                    Output output = Output.fromRecord(node);
                    String guid = output.getGuid();
                    Block block = blocks.getBlock(guid);
                    block.addOutput(output);
                } else
                // Add input
                if (node.hasLabel(configuration.getInput())) {
                    Input input = Input.fromRecord(node);
                    inputs.add(input);
                    String guid = input.getGuid();
                }

            }

MATCH (start:Block{name:'block_3'})
CALL apoc.path.subgraphNodes(start, {relationshipFilter:'PART_OF|hasOutPort>|connectsTo>|<hasInPort'}) YIELD node as block
WITH
  block,
  [(block)-[:PART_OF]->(prop) | prop] as properties,
  [(block)-[:hasOutPort]->(output) | output] as outputs,
  [(block)-[:hasInPort]->(input) | input] as inputs
RETURN block, properties, outputs, inputs

匹配（开始：块{name:'Block_3'}）
调用apoc.path.subgraphNodes（start，{relationshipFilter:'PART|u OF | hasOutPort>| connectsTo>|），首先需要指定这些关系的别名并像节点一样返回它们。简化示例：

MATCH (a:Block)-[r:PART_OF]->(b:Block) RETURN a, r, b

这样，您的记录实例将包含a、r和b的数据（值实例）。在提取逻辑中，您将执行以下操作以获取关系数据：

Relationship r = record.get("r").asRelationship();