Java 套接字异常：使用JAXB解组时重置连接

我能够使用FileInputStream将xml文件解组到一个类来读取xml内容，并且在解组代码中使用InputStream而不是FileInputStream时遇到问题

元帅：

try {
    JAXBContext jaxbContext = JAXBContext.newInstance(Message.class);
    Marshaller jaxbMarshaller = jaxbContext.createMarshaller();

        JAXBElement<Message> je = 
            new JAXBElement<Message> (new QName(Message.class.getSimpleName()), Message.class, message);

    jaxbMarshaller.marshal(je, os);
} catch (JAXBException e) {
    e.printStackTrace();
}

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试试这样的

使用JAXBIntrospector获取值

String filepath="C:\\somepath";
FileInputStream xml = new FileInputStream(filepath);
Object result = unmarshaller.unmarshaller.unmarshal(xml);
Message msg = (Message) JAXBIntrospector.getValue(result);

StreamSource xml = new StreamSource(filepath);
JAXBElement<Message> msgclass = 
unmarshaller.unmarshal(xml, Message.class);

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“连接重置”与XML、JAXB、解组等无关。它通常是由写入已被对等方关闭的连接引起的。换句话说，应用程序协议错误

javax.xml.bind.UnmarshalException
 - with linked exception:
[java.net.SocketException: Connection reset]

String filepath="C:\\somepath";
FileInputStream xml = new FileInputStream(filepath);
Object result = unmarshaller.unmarshaller.unmarshal(xml);
Message msg = (Message) JAXBIntrospector.getValue(result);

StreamSource xml = new StreamSource(filepath);
JAXBElement<Message> msgclass = 
unmarshaller.unmarshal(xml, Message.class);