Java 如何确定在android中单击了哪个动态按钮？

我正在oncreate中创建一个动态按钮，我没有在XML中添加任何按钮

LinearLayout table = (LinearLayout)findViewById(R.id.linearlayout);
Button btnAttendance,btnSched;
btnAttendance = new Button(this);
btnSched = new Button(this);
btnAttendance.setOnClickListener(this);
btnSched.setOnClickListener(this);
table.addView(btnAttendance);
        table.addView(btnSched);

//这是我在实现侦听器时创建的OnClick方法：

@Override
    public void onClick(View arg0) {
        // TODO Auto-generated method stub
        BackgroundWorker fetchRiddles = new BackgroundWorker(DashActivity.this,"retrieveRiddles");
        switch (arg0.getId()) {
        case 1:  // in this case i usually put "R.id.Button1:" but my problem is that my buttons are dynamic
            fetchRiddles.execute("0,"+username);
            break;
        case 2:
            fetchRiddles.execute("1,"+username);
            break;
    }

---

如何使用开关确定单击了哪个按钮？“我的按钮”是动态创建的，没有在“我的xml”中放置任何按钮。

您可以通过编程方式设置ID：

btnAttendance = new Button(this);
btnAttendance.setId(100);
btnSched = new Button(this);
btnSched.setId(200);

然后比较：

@Override
    public void onClick(View arg0) {
        // TODO Auto-generated method stub
        BackgroundWorker fetchRiddles = new BackgroundWorker(DashActivity.this,"retrieveRiddles");
        switch (arg0.getId()) {
        case 100:  // in this case i usually put "R.id.Button1:" but my problem is that my buttons are dynamic
            fetchRiddles.execute("0,"+username);
            break;
        case 200:
            fetchRiddles.execute("1,"+username);
            break;
    }

---

您可以通过编程方式设置ID：

btnAttendance = new Button(this);
btnAttendance.setId(100);
btnSched = new Button(this);
btnSched.setId(200);

然后比较：

@Override
    public void onClick(View arg0) {
        // TODO Auto-generated method stub
        BackgroundWorker fetchRiddles = new BackgroundWorker(DashActivity.this,"retrieveRiddles");
        switch (arg0.getId()) {
        case 100:  // in this case i usually put "R.id.Button1:" but my problem is that my buttons are dynamic
            fetchRiddles.execute("0,"+username);
            break;
        case 200:
            fetchRiddles.execute("1,"+username);
            break;
    }