Java 使用OpenJPA时ORM中的死锁

Java 使用OpenJPA时ORM中的死锁,java,jpa,orm,deadlock,openjpa,Java,Jpa,Orm,Deadlock,Openjpa,当使用运行10的soapui执行负载测试时,我遇到了死锁。每个线程向我的web服务发出10个请求,该web服务调用OpenJPA实体管理器的perits方法 然后我执行单个请求,所有请求都结束得很好,但在多线程环境中,它以死锁结束 我得到的错误是: Deadlock found when trying to get lock; try restarting transaction {prepstmnt 12796448 UPDATE Assessment SET dateCompleted =

当使用运行10的
soapui
执行负载测试时,我遇到了死锁。每个线程向我的web服务发出10个请求,该web服务调用OpenJPA实体管理器的perits方法

然后我执行单个请求,所有请求都结束得很好,但在多线程环境中,它以死锁结束

我得到的错误是:

Deadlock found when trying to get lock; try restarting transaction {prepstmnt 12796448 UPDATE Assessment SET dateCompleted = ? WHERE id = ? [params=?, ?]} [code=1213, state=40001]
由于死锁而崩溃的方法如下:

@Override
public AssessmentKey update(AssessmentKey assessmentKey) {
    OpenJPAEntityManager openJpaEntityMgr = OpenJPAPersistence.cast(entityManager);
    for (Assessment assessment : assessmentKey.getAssessments()) {
        if (!entityManager.contains(assessment) && !openJpaEntityMgr.isDetached(assessment)) {
            LOGGER.debug("Persisting {}", assessment);
            entityManager.persist(assessment);
        }
    }
    return entityManager.merge(assessmentKey);
}
评估
是OpenJPA的一个实体,它只是一个包含JPA注释的普通实体。 如果你需要它的代码,就要它

我了解死锁是如何发生的,如何解决它们是在中提到的。但如何在ORM中解决这些问题,我无法找到答案

我的
persistence.xml
文件如下所示:

<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence">
    <persistence-unit name="com.groupgti.esb.online.tests">
        <provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider>
        <class>com.groupgti.esb.assessments.model.jpaimpl.Assessment</class>
        <exclude-unlisted-classes>true</exclude-unlisted-classes>
        <validation-mode>NONE</validation-mode>
        <properties>
            <property name="openjpa.Log" value="slf4j"/>
            <property name="openjpa.DataCache" value="false"/>
            <property name="openjpa.ReadLockLevel" value="none"/>
            <property name="openjpa.WriteLockLevel" value="pessimistic-write"/>
            <property name="openjpa.LockTimeout" value="10000"/>
            <property name="openjpa.RuntimeUnenhancedClasses" value="unsupported"/>
        </properties>
    </persistence-unit>
</persistence>
@ManyToOne(fetch = FetchType.EAGER, cascade = {CascadeType.PERSIST, CascadeType.MERGE})
@Index
@Column(nullable = false)
@ForeignKey
private AssessmentKey assessmentKey;
评估中
评估键
如下所示:

<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence">
    <persistence-unit name="com.groupgti.esb.online.tests">
        <provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider>
        <class>com.groupgti.esb.assessments.model.jpaimpl.Assessment</class>
        <exclude-unlisted-classes>true</exclude-unlisted-classes>
        <validation-mode>NONE</validation-mode>
        <properties>
            <property name="openjpa.Log" value="slf4j"/>
            <property name="openjpa.DataCache" value="false"/>
            <property name="openjpa.ReadLockLevel" value="none"/>
            <property name="openjpa.WriteLockLevel" value="pessimistic-write"/>
            <property name="openjpa.LockTimeout" value="10000"/>
            <property name="openjpa.RuntimeUnenhancedClasses" value="unsupported"/>
        </properties>
    </persistence-unit>
</persistence>
@ManyToOne(fetch = FetchType.EAGER, cascade = {CascadeType.PERSIST, CascadeType.MERGE})
@Index
@Column(nullable = false)
@ForeignKey
private AssessmentKey assessmentKey;

Assessment key
Assessment
OneToMany
的双向关系。
OneToMany
manytone
注释都具有
级联类型。持久化
和其他

要点是:

EntityManager
persist
Assessment
时,
AssessmentKey
也将保持。您应该需要再次保存或合并
AssessmentKey

让我提出以下建议或映射:

AssessmentKey.java

@OneToMany(fetch = FetchType.EAGER, cascade = {CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REMOVE}, 
           mappedBy = "assessmentKey", orphanRemoval=true)
private List<Assessment> assessments;
数据库操作

@Override
public AssessmentKey update(AssessmentKey assessmentKey) {
    OpenJPAEntityManager openJpaEntityMgr = OpenJPAPersistence.cast(entityManager);
    // there may be your operation
    return entityManager.merge(assessmentKey);
}
我假设,
Assessment
当前
AssessmentKey
对象的值可能如下

On System                               |   In Existing Database
ID      Description                     |   ID      Descrition
1001    AAA         => No Changes       |   1001    AAA
1002    BBB         => Need to update   |   1002    BB
null    DDD         => Need to add      |   1003    CCC     => need to remove.
当EntityManager合并
Assessment key
时,
EntityManager
将完成我在上述数据结构中提到的
评估的所有过程


注意:确保
OneToMany
注释中的
orphaneremovation=true

@您能否发布
O/R
Assessment
的关系?