Java 根据优先级值进行筛选的最佳方法

在集合（Iterable）中，如果存在重复项，我希望筛选优先级值

类的数据表示可以如下所示：

[
  {
    "uuid": "56a00526-871f-43d4-86fe-0df1773f5cdf",
    "entry": "CASSIER",
    "rate": {
      "uuid": "0b264f4d-3f3f-4e39-3f3f-3f53263f303d",
      "type": 2,
      "rate": 430
    }
  },
  {
    "uuid": "663f5d3f-3f3f-48da-a743-3f7b3f753e65",
    "entry": "CASTET",
    "rate": {
      "uuid": "3fdf9f2c-3f3f-4e3f-3f3f-263fe29d8d07",
      "type": 1,
      "rate": 13
    }
  },
  {
    "uuid": "8eae8c39-d667-4cc5-9b91-544454961399",
    "entry": "CASTET",
    "rate": {
      "uuid": "133f0315-413f-493f-3f24-3f3f6d3f5874",
      "type": 2,
      "rate": 345
    }
  },
  {
    "uuid": "6D680178-9B05-4744-A004-163D4B3E1E84",
    "entry": "JOHN",
    "rate": {
      "uuid": "EE877ABD-932F-4B4C-AB23-B324363B0B60",
      "type": 1,
      "rate": 13
    }
  }
]

例外结果（优先级：rate.type=2）：

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是否存在Java流？

最后，我使用谓词筛选了一个Iterable，并在按速率对Iterable排序后筛选了一个流筛选器。类型：

public static <T> Predicate<T> distinctByKey(Function<? super T,Object> keyExtractor) {
    Map<Object,Boolean> seen = new ConcurrentHashMap<>();
    return t -> seen.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;
}

Stream s = StreamSupport.stream(registrations.spliterator(), false);
s.filter(distinctByKey((Registration r) -> r.getEntry().getUuid())).collect(Collectors.toList());

---

public static Predicate distinctByKey（函数）您使用的是哪种类型的集合？如果您使用的是标准集合，则可以使用Collections.sort来实现所需的功能。@SanjitKumarMishra我使用的是Iterable
public static <T> Predicate<T> distinctByKey(Function<? super T,Object> keyExtractor) {
    Map<Object,Boolean> seen = new ConcurrentHashMap<>();
    return t -> seen.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;
}

Stream s = StreamSupport.stream(registrations.spliterator(), false);
s.filter(distinctByKey((Registration r) -> r.getEntry().getUuid())).collect(Collectors.toList());