Java 无法从首选项(设置)检索字符串
我在Android应用程序中遇到了一个问题。问题是由于某种原因,我无法从我的Java 无法从首选项(设置)检索字符串,java,android,sharedpreferences,Java,Android,Sharedpreferences,我在Android应用程序中遇到了一个问题。问题是由于某种原因,我无法从我的preferences.xml文件中检索ListPreference的字符串。以下是我尝试的代码: private void showUserSettings() { SharedPreferences sharedPrefs = PreferenceManager .getDefaultSharedPreferences(this); try { String
preferences.xml
文件中检索ListPreference
的字符串。以下是我尝试的代码:
private void showUserSettings() {
SharedPreferences sharedPrefs = PreferenceManager
.getDefaultSharedPreferences(this);
try {
String feet = sharedPrefs.getString("feet", "NULL");
int intfeet = Integer.parseInt(feet);
int intinches = Integer.parseInt(sharedPrefs.getString("feet", "NULL").trim());
int weight = Integer.parseInt(sharedPrefs.getString("weight", "NULL").trim());
int age = Integer.parseInt(sharedPrefs.getString("age", "NULL").trim());
double calories;
double inches = ((intfeet * 12) + intinches);
if (gender.equals("Female")) {
//BMR = 655 + ( 4.35 x weight in pounds ) + ( 4.7 x height in inches ) - ( 4.7 x age in years )
calories = 655 + (4.35 * weight) + (4.7 * inches) - (4.7 * age);
}
else {
//66 + ( 6.23 x weight in pounds ) + ( 12.7 x height in inches ) - ( 6.8 x age in years )
calories = 66.5 + (6.23 * weight) + (12.7 * inches) - (6.8 * age);
}
//ListPreference listPreference = (ListPreference) findPreference("exercise");
//CharSequence currText = listPreference.getEntry();
String exercise = sharedPrefs.getString("exercise", "NULL").toString();
if (exercise.equals("Sedentary")) {
double sedentary = calories * 1.2;
Toast.makeText(getApplicationContext(), sedentary + "", Toast.LENGTH_LONG).show();
}
if (exercise.equals("Light")){
double light = calories * 1.375;
Toast.makeText(getApplicationContext(), light + "", Toast.LENGTH_LONG).show();
}
if (exercise.equals("Moderate")){
double moderate = calories * 1.55;
Toast.makeText(getApplicationContext(), moderate + "", Toast.LENGTH_LONG).show();
}
if (exercise.equals("Very active")) {
double veryactive = calories * 1.725;
Toast.makeText(getApplicationContext(), veryactive + "", Toast.LENGTH_LONG).show();
}
if (exercise.equals("Extra active")) {
double extraactive = calories * 1.9;
Toast.makeText(getApplicationContext(), extraactive + "", Toast.LENGTH_LONG).show();
}
else {
Toast.makeText(getApplicationContext(), "Uh oh", Toast.LENGTH_SHORT).show();
}
}catch (Exception e) {
e.printStackTrace();
}
}
每当它到达第二条if/else语句时,它就直接转到else语句。我不知道它为什么这样做。我搜索了SO和Google,但没有结果。我基本上撞到了砖墙。非常感谢您对这个问题的任何帮助。您所有的练习条件都是独立的,而else只与最后一个if语句关联。使用
else if
以我相信你想要的方式将它们绑定在一起。你是说当它到达这里时,if(exercise.equals(“Extra-active”){
,它只会转到else
?你设置了一个断点来查看exercise
的值吗?另外,你不需要调用toString()字符串上的
。