Java 摩根和一根绳子
我试图解决这个问题: 这是我的密码:Java 摩根和一根绳子,java,arrays,string,indexoutofboundsexception,Java,Arrays,String,Indexoutofboundsexception,我试图解决这个问题: 这是我的密码: import java.io.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; public class Solution { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = In
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
int t = Integer.parseInt(sc.nextLine());
while((t--)>0)
{
String s1 = sc.nextLine();
String s2 = sc.nextLine();
System.out.println(ms(s1,s2));
}
}
public static String ms(String s1, String s2)
{
StringBuffer sb = new StringBuffer();
int i,j;
for(i=0,j=0;i<s1.length() || j<s2.length() ;)
{
if(s1.charAt(i)>s2.charAt(j))
{
sb.append(s2.charAt(j));
if(j==s2.length())
break;
else
j++;
}
else
{
sb.append(s1.charAt(i));
if(i==s1.length())
break;
else
i++;
}
}
if(j==s2.length())
{
for(;i<s1.length();i++)
sb.append(s1.charAt(i));
return sb.toString();
}
else
{
for(;j<s2.length();j++)
sb.append(s2.charAt(j));
return sb.toString();
}
}
}
谁能告诉我哪里出了问题?我找不到错误…我不知道您正在尝试使用该程序,但我认为这将消除您的错误
for(i=0,j=0;i<s1.length() & j<s2.length() ;)
for(i=0,j=0;i我刚刚修改了for循环,如下所示,我可以在没有任何问题的情况下执行程序
for(i = 0, j = 0; i < s1.length() && j < s2.length();)
for(i=0,j=0;i
PFB的源代码
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int t = Integer.parseInt(sc.nextLine());
while ((t--) > 0) {
String s1 = sc.nextLine();
String s2 = sc.nextLine();
System.out.println(ms(s1, s2));
}
}
public static String ms(String s1, String s2) {
StringBuffer sb = new StringBuffer();
int i, j;
for (i = 0, j = 0; i < s1.length() && j < s2.length();) {
if (s1.charAt(i) > s2.charAt(j)) {
sb.append(s2.charAt(j));
if (j == s2.length())
break;
else
j++;
} else {
sb.append(s1.charAt(i));
if (i == s1.length())
break;
else
i++;
}
}
if (j == s2.length()) {
for (; i < s1.length(); i++)
sb.append(s1.charAt(i));
return sb.toString();
}
else {
for (; j < s2.length(); j++)
sb.append(s2.charAt(j));
return sb.toString();
}
}
}
import java.util.Scanner;
公开课考试{
公共静态void main(字符串[]args){
扫描仪sc=新的扫描仪(System.in);
int t=Integer.parseInt(sc.nextLine());
而((t--)>0){
字符串s1=sc.nextLine();
字符串s2=sc.nextLine();
系统输出println(ms(s1,s2));
}
}
公共静态字符串ms(字符串s1、字符串s2){
StringBuffer sb=新的StringBuffer();
int i,j;
对于(i=0,j=0;is2.字符(j)){
sb.追加(s2.字符(j));
如果(j==s2.length())
打破
其他的
j++;
}否则{
sb.追加(s1.字符(i));
如果(i==s1.length())
打破
其他的
i++;
}
}
如果(j==s2.length()){
对于(;i
WelliSide注意:这些问题通常可以通过在调试器中运行程序来解决;或者(不太“推荐”:通过为每个重要语句插入跟踪语句来解决。)
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int t = Integer.parseInt(sc.nextLine());
while ((t--) > 0) {
String s1 = sc.nextLine();
String s2 = sc.nextLine();
System.out.println(ms(s1, s2));
}
}
public static String ms(String s1, String s2) {
StringBuffer sb = new StringBuffer();
int i, j;
for (i = 0, j = 0; i < s1.length() && j < s2.length();) {
if (s1.charAt(i) > s2.charAt(j)) {
sb.append(s2.charAt(j));
if (j == s2.length())
break;
else
j++;
} else {
sb.append(s1.charAt(i));
if (i == s1.length())
break;
else
i++;
}
}
if (j == s2.length()) {
for (; i < s1.length(); i++)
sb.append(s1.charAt(i));
return sb.toString();
}
else {
for (; j < s2.length(); j++)
sb.append(s2.charAt(j));
return sb.toString();
}
}
}