Java GSON对象(RESTful api)
我有一个客户端(java),它将一些json数据发送到我的服务器(c++)。在此之后,我的服务器会根据java客户机的操作响应一些信息。目前,它的工作Java GSON对象(RESTful api),java,c++,json,rest,gson,Java,C++,Json,Rest,Gson,我有一个客户端(java),它将一些json数据发送到我的服务器(c++)。在此之后,我的服务器会根据java客户机的操作响应一些信息。目前,它的工作 Example body request: { "userEmail": "email@email.com", "userPassword": "12345678" } 和服务器,接收电子邮件和密码,执行操作并返回响应 但现在我需要更改java客户端以发送如下请求: { "userInformation":{ "
Example body request:
{
"userEmail": "email@email.com",
"userPassword": "12345678"
}
和服务器,接收电子邮件和密码,执行操作并返回响应
但现在我需要更改java客户端以发送如下请求:
{
"userInformation":{
"userEmail": "email@email.com",
"userPassword": "12345678"
}
}
public class LoginRequestArgs {
public UserInfo userInformation;
public LoginRequestArgs(String userEmail, String userPassword) {
userInformation = new UserInfo(userEmail, userPassword);
}
static class UserInfo {
public String userEmail;
public String userPassword;
public UserInfo(String userEmail, String userPassword) {
this.userEmail = userEmail;
this.userPassword = userPassword;
}
}
public static LoginRequestArgs fromStringJson(String data) {
try {
Gson gson = new Gson();
return gson.fromJson(data, LoginRequestArgs.class);
} catch (Exception e) {
return null;
}
}
public static LoginRequestArgs fromBytesJson(byte[] data) {
if (data == null)
return null;
try {
String str = new String(data, "utf-8");
return fromStringJson(str);
} catch (Exception e) {
return null;
}
}
}
此请求可用于登录。这是一个非常复杂的体系结构,所以我不能复制所有的代码,但是在登录类中我使用GSON(注:我只在C++服务器中工作,我不在客户端工作,它不可能联系java客户端来询问他这个疑惑)
Java客户端登录类
public final String userEmail;
public final String userPassword;
public LoginRequestArgs( String userEmail, String userPassword)
{
this.userEmail = userEmail;
this.userPassword = userPassword;
}
public static LoginRequestArgs fromStringJson(String data)
{
try
{
Gson gson = new Gson();
return gson.fromJson(data, LoginRequestArgs.class);
}
catch(Exception e)
{
return null;
}
}
public static LoginRequestArgs fromBytesJson(byte[] data)
{
if (data == null) return null;
try
{
String str = new String(data, "utf-8");
return fromStringJson(str);
}
catch (Exception e)
{
return null;
}
}
@Override
public String toJsonString()
{
try
{
Gson gson = new Gson();
return gson.toJson(this);
}
catch(Exception e)
{
return null;
}
}
@Override
public byte[] toJsonBytes()
{
try
{
return this.toJsonString().getBytes("utf-8");
}
catch (Exception e)
{
return null;
}
}
我有其他类连接到我的服务器并发送请求。此类调用login函数(请求是一个SerializableJSON变量),并将此请求放置到我的服务器request=loginRequestStargs.fromStringJson(args.httpEntity)代码>
(对于测试,我使用一个rest客户端chrome扩展)
我知道这很难理解,但要解释所有的事情并不容易。我试图解释本质
真正的问题是:我无法使java客户端发送“userInformation”中的电子邮件和密码。有人能帮我吗?谢谢
编辑(其他正文请求示例):
编辑2(身份验证方法):
编辑3(令牌):
编辑4:
{
"sessionId":{
"email":"email@email.com",
"password":"dasdas"
},
"userInformation":{
"userId": "userId1",
"userPassword": "12345678"
}
}
我已经把这个JSON发送到我的C++服务器,它的工作和解码会话ID也工作,这对我来说C++工作不是问题。但是我需要发送sessionId(或token),但在“AuthenticationMethod”中,这是我现在唯一需要实现的东西。注意“userInformation”及其类似的示例,例如“bookInformation”、“carInformation”,根据请求类型,我发送不同的数据,其中包含不同的键/值。。但在所有请求中都必须使用身份验证方法(会话id或令牌)
为了像我向您展示的那样工作,我实现了以下几点:
public class SessionId {
public String email;
public String password;
public SessionId(String email, String password)
{
this.email = email;
this.password = password;
}
}
在我的类的构造中(例如,可以是一个类,如LoginRequestStargs、login cass),我称之为super:
public UserInfo userInformation;
public SessionId sessionId;
public LoginRequestArgs(String email, String password,String userEmail, String userPassword)
{
super(email,password);
userInformation = new UserInfo(userEmail, userPassword);
}
static class UserInfo {
public String userId;
public String userPassword;
public UserInfo(String userEmail, String userPassword) {
this.userId = userEmail;
this.userPassword = userPassword;
}
}
所以现在,我只需要在会话id或令牌之前添加“authenticationMethod”(我相信这样做的方法对两者都是一样的)
****编辑5********
login.java
public class LoginRequestArgs implements SerializableJSON {
public UserInfo userInformation;
public AuthenticationMethod authenticationMethod;
public LoginRequestArgs(String email, String password,String userId, String userPassword)
{
AuthenticationMethod auth = new SessionId(email, password);
setAuth(auth);
userInformation = new UserInfo(userId, userPassword);
}
public void setAuth(AuthenticationMethod authenticationMethod){
this.authenticationMethod = authenticationMethod;
}
static class UserInfo {
public String userId;
public String userPassword;
public UserInfo(String userEmail, String userPassword) {
this.userId = userEmail;
this.userPassword = userPassword;
}
}
SessionId.java
public class SessionId extends AuthenticationMethod {
Session sessionId;
public SessionId(String email, String password)
{
this.sessionId = new Session(email,password);
}
static class Session{
String email;
String password;
public Session(String email, String password)
{
this.email = email;
this.password = password;
}
}
}
AuthenticationMethod.java
public class AuthenticationMethod {
}
您需要将loginRequestStargs
类更改为如下所示:
{
"userInformation":{
"userEmail": "email@email.com",
"userPassword": "12345678"
}
}
public class LoginRequestArgs {
public UserInfo userInformation;
public LoginRequestArgs(String userEmail, String userPassword) {
userInformation = new UserInfo(userEmail, userPassword);
}
static class UserInfo {
public String userEmail;
public String userPassword;
public UserInfo(String userEmail, String userPassword) {
this.userEmail = userEmail;
this.userPassword = userPassword;
}
}
public static LoginRequestArgs fromStringJson(String data) {
try {
Gson gson = new Gson();
return gson.fromJson(data, LoginRequestArgs.class);
} catch (Exception e) {
return null;
}
}
public static LoginRequestArgs fromBytesJson(byte[] data) {
if (data == null)
return null;
try {
String str = new String(data, "utf-8");
return fromStringJson(str);
} catch (Exception e) {
return null;
}
}
}
以下是您访问电子邮件和密码的方式:
loginRequestArgsInstance.userInformation.userEmail;
loginRequestArgsInstance.userInformation.userPassword;
您可能应该向这个类添加一些getter和setter,或者至少确保userInformation
不是null
有多种方法可以将会话细节包含到JSON中。一种方法是修改java类。大概是这样的:
{
"userInformation":{
"userEmail": "email@email.com",
"userPassword": "12345678"
}
}
public class LoginRequestArgs {
public UserInfo userInformation;
public LoginRequestArgs(String userEmail, String userPassword) {
userInformation = new UserInfo(userEmail, userPassword);
}
static class UserInfo {
public String userEmail;
public String userPassword;
public UserInfo(String userEmail, String userPassword) {
this.userEmail = userEmail;
this.userPassword = userPassword;
}
}
public static LoginRequestArgs fromStringJson(String data) {
try {
Gson gson = new Gson();
return gson.fromJson(data, LoginRequestArgs.class);
} catch (Exception e) {
return null;
}
}
public static LoginRequestArgs fromBytesJson(byte[] data) {
if (data == null)
return null;
try {
String str = new String(data, "utf-8");
return fromStringJson(str);
} catch (Exception e) {
return null;
}
}
}
Req.java
public class Req{
String data1;
String data2;
Auth authenticationMethod;
....
public void setAuth(Auth authenticationMethod){
this.authenticationMethod = authenticationMethod;
}
}
Auth.java
public class Auth{
....
}
AuthToken.java
public class AuthToken extends Auth {
Token token;
public AuthToken(String token) {
this.token = new Token(token);
}
static class Token {
String token;
public Token(String token) {
this.token = token;
}
}
}
AuthUserInfo.java
public class AuthUserInfo extends Auth {
UserInfo sessionId;
public AuthUserInfo(String email, String password) {
this.sessionId = new UserInfo(email, password);
}
static class UserInfo {
String email;
String password;
public UserInfo(String email, String password) {
this.email = email;
this.password = password;
}
}
}
下面是如何使用这些类:
Req req = new Req(...);
Auth auth = new AuthToken(...);// OR: new AuthUserInfo(...);
req.setAuth(auth);
String json = new Gson().toJson(req);
另一种方法是在创建JSON后向其添加新属性。您可以看到一个如何做到这一点的示例非常感谢您的帮助。这对我来说是一个很好的起点。可能它不起作用,因为我需要更多地研究我的java客户机,因为它有很多类。但是非常感谢你的回答,因为我正在寻找一个起点;)我尝试你的解决方案及其工作:非常感谢:)在你的解决方案之后,我需要调整我的JSON解析C++来获取用户信息里面的内容,但是对我来说很容易。hehe@Pik93我很高兴能帮上忙。祝你好运,再次你好。。如果我现在有这样的身体,如何在java中实现?更多的静态类?{“userInformation”:{“otherSection”:{“key1”:“value1”,“key2”:“value2”}}}@Pik93是的,您必须创建一个包含字段key1
和key2
的新类,并将该类型的变量添加到LoginRequestArgs
类中。无需在loginRequestStargs
中将类定义为静态类
,您可以为其创建单独的文件。