Java 名为“的方法没有适用的重载”；rf"；在“类型”中找到；mp3“U组织者”；

我不知道该怎么办，因为我确保了方法没有重复的名称，我试图搜索问题，但似乎每个人的问题都与我的不同，尽管输出显示类似的东西

代码：

问题在于：

public static void rf (String[] songname, String[] songpath, String[] artist, String[] genre, int[] count, String file){
   //...
}

您有六个参数，在方法实现中，

int cuunt[]

是一个数组

songname [count [0]] = line;
songpath [count [0]] = reader.readLine ();
artist [count [0]] = reader.readLine ();
genre [count [0]] = reader.readLine ();
count [0]++;

但是当调用该方法时，pass六个参数但是作为变量计算：

rf (songname, songpath, artist, genre, count, file);

search (songname, songpath, artist, genre, count, file);

要解决此问题，您需要重载方法，将count作为变量传递，以与方法实现相匹配。如果只想作为变量传递，则更改为数组。如下所示：

//method count array
public static void rf (String[] songname, String[] songpath, String[] artist, String[] genre, int[] count, String file) throws FileNotFoundException, IOException
{
    BufferedReader reader = new BufferedReader (new FileReader (file));

    String temp, line = null;

    while ((line = reader.readLine ()) != null)
    {
        songname [count [0]] = line;
        songpath [count [0]] = reader.readLine ();
        artist [count [0]] = reader.readLine ();
        genre [count [0]] = reader.readLine ();
        count [0]++;
    }


    reader.close ();
}

//overloaded six parameter method
//without count array. count variable
public static void rf (String[] songname, String[] songpath, String[] genre, int count, String file) throws FileNotFoundException, IOException
    {
        BufferedReader reader = new BufferedReader (new FileReader (file));

        String temp, line = null;

        while ((line = reader.readLine ()) != null)
        {
            songname [count [0]] = line;
            songpath [count [0]] = reader.readLine ();
            artist [count [0]] = reader.readLine (); - remove this line
            genre [count] = reader.readLine ();//change this too, genre [count[0]]
            count++;//since this is not a array change to count[0]++.
        }


        reader.close ();
    }

您还需要重载

search（）

与调用函数不匹配（

文件

参数不在实现中）：

更新：

这些也必须根据您的上述实现进行更改

songname [count [0]] = line;
songpath [count [0]] = reader.readLine ();
artist [count [0]] = reader.readLine ();
genre [count [0]] = reader.readLine ();
count [0]++;

我认为您可以将

count

参数作为数组传递给

rf（）

和

search（）

，而不是更改所有这些参数。否则，您需要更改整个程序。这取决于你想办法做到这一点

阅读更多关于

search (songname, songpath, artist, genre, count, file);

songname [count [0]] = line;
songpath [count [0]] = reader.readLine ();
artist [count [0]] = reader.readLine ();
genre [count [0]] = reader.readLine ();
count [0]++;