Java 在单独的线程中启动zookeeper
我试图通过以下方式将多个嵌入式zookeeper服务器从Java应用程序启动到单独的线程中:Java 在单独的线程中启动zookeeper,java,multithreading,configuration,distributed,apache-zookeeper,Java,Multithreading,Configuration,Distributed,Apache Zookeeper,我试图通过以下方式将多个嵌入式zookeeper服务器从Java应用程序启动到单独的线程中: String port1 = "2181"; String directory1 = new File(System.getProperty("java.io.tmpdir"), "zookeeper/data1").getAbsolutePath(); final ServerConfig config1 = new ServerConfig(); config1.parse(new String[]
String port1 = "2181";
String directory1 = new File(System.getProperty("java.io.tmpdir"), "zookeeper/data1").getAbsolutePath();
final ServerConfig config1 = new ServerConfig();
config1.parse(new String[] { port1, directory1 });
new Thread(new Runnable() {
@Override
public void run()
{
try{
ZooKeeperServerMain zk = new ZooKeeperServerMain()
zk.runFromConfig(config1);
}catch(Exception e){
e.printStackTrace();
}
}
}).run();
当我以这种方式启动zk时,主进程被阻塞,其余指令不执行!
有没有合适的方法在单独的线程中启动zookeeper?您在线程上调用的是run()
,而不是start()
new Thread(new Runnable() {
@Override
public void run()
{
try{
ZooKeeperServerMain zk = new ZooKeeperServerMain()
zk.runFromConfig(config1);
}catch(Exception e){
e.printStackTrace();
}
}
}).start();
您正在线程上调用run()
而不是start()
new Thread(new Runnable() {
@Override
public void run()
{
try{
ZooKeeperServerMain zk = new ZooKeeperServerMain()
zk.runFromConfig(config1);
}catch(Exception e){
e.printStackTrace();
}
}
}).start();