Java SpringMVC嵌套模型验证
我有两种型号:Java SpringMVC嵌套模型验证,java,spring,validation,spring-mvc,Java,Spring,Validation,Spring Mvc,我有两种型号:User,Project public class Project{ private int id; @NotEmpty(message="Project Name can not be empty") private String name; private User manager; private User operator; //getter/setter omitted } public class User{ p
User,Project
public class Project{
private int id;
@NotEmpty(message="Project Name can not be empty")
private String name;
private User manager;
private User operator;
//getter/setter omitted
}
public class User{
private int id;
private String name;
//omit other properties and getter/setter
}
现在,当我创建一个新项目时,我将向ProjectController提交以下参数:
projects?name=jhon&manager.id=1&operator.id=2…
然后,我将创建一个新的项目对象并将其插入db
但是,我必须验证经理和操作员的id是否有效,也就是说,我将验证用户表中是否有匹配的id
所以我想知道如何实现这种验证
更新1:使用验证器 这是创建新项目的表单:
<sf:form method="${project.id==0?'post':'put'}" commandName="project" action="${context}${action}">
Manager:<sf:input path="manager.id" /> <sf:errors path="manager.id" /> <br />
Operator:<sf:input path="operator.id" /> <sf:errors path="operator.id" /> <br />
Name:<sf:input path="name" /> <sf:errors path="name" /> <br />
<input type="submit" value="Submit" />
</sf:form>
@Override
public void validate(Object obj, Errors errors) {
User user = (User) obj;
int id=user.getId();
User u=userDao.query(id);
if(u==null){
errors.rejectValue("id", "user does not exist!");
}
}
结果似乎确实有错误,但它的路径是project.id
,而在我的表单中它是project.manager.id
如何修复?在控制器中,您可以添加自定义验证器:
@InitBinder
protected void initBinder(WebDataBinder binder) {
binder.setValidator(new ProjectValidator());
}
在此验证器中,您可以检查
用户
对象或委托给用户验证器
,如第6.3节之前的最后一段所述,这里有一个可能的解决方案
在下面创建类:
...
import org.springframework.validation.Validator;
...
@Component
public class ProjectValidator implements Validator {
@Override
public boolean supports(Class<?> clazz) {
return Project.class.equals(clazz);
}
@Override
public void validate(Object target, Errors errors) {
Project project = (Project) target;
/* Do your checks here */
...
if (managerIdDoesNotMatch) {
errors.rejectValue("manager.id", "your_error_code");
}
...
if (operatorIdDoesNotMatch) {
errors.rejectValue("operator.id", "your_error_code");
}
...
}
}
这应该让你开始。您可以以不同的方式实例化/设置验证器,使用一个用户子验证器,但您可以了解总体思路
参考资料:
@Component
public class BeanValidator implements org.springframework.validation.Validator, InitializingBean {
private Validator validator;
public void afterPropertiesSet() throws Exception {
ValidatorFactory validatorFactory = Validation.buildDefaultValidatorFactory();
validator = validatorFactory.usingContext().getValidator();
}
public boolean supports(Class clazz) {
return true;
}
public void validate(Object target, Errors errors, String prefix) {
Set<ConstraintViolation<Object>> constraintViolations = validator.validate(target);
for (ConstraintViolation<Object> constraintViolation : constraintViolations) {
String propertyPath = constraintViolation.getPropertyPath().toString();
String message = constraintViolation.getMessage();
errors.rejectValue(prefix + "." + propertyPath, "", message);
}
}
public void validate(Object target, Errors errors) {
validate(target, errors, "");
}
}
@组件
公共类BeanValidator实现org.springframework.validation.Validator,初始化Bean{
私人验证器;
public void afterPropertieSet()引发异常{
ValidatorFactory=Validation.buildDefaultValidatorFactory();
validator=validatorFactory.usingContext().getValidator();
}
公共布尔支持(类clazz){
返回true;
}
公共无效验证(对象目标、错误、字符串前缀){
Set constraintViolations=validator.validate(目标);
for(ConstraintViolation ConstraintViolation:constraintViolations){
String propertyPath=constraintViolation.getPropertyPath().toString();
String message=constraintViolation.getMessage();
错误。拒绝值(前缀+“+”属性路径“”,消息);
}
}
公共无效验证(对象目标、错误){
验证(目标,错误,“”);
}
}
下面是我如何在UserValidator中使用它的:
@Component
public class UserValidator implements Validator {
@Autowired
BeanValidator beanValidator;
@Override
public boolean supports(Class<?> clazz) {
return User.class.equals(clazz);
}
@Override
public void validate(Object target, Errors errors) {
User user = (User) target;
beanValidator.validate(user.getAddress(), errors, "address");
}
}
@组件
公共类UserValidator实现验证器{
@自动连线
BeanValidator BeanValidator;
@凌驾
公共布尔支持(类clazz){
返回User.class.equals(clazz);
}
@凌驾
公共无效验证(对象目标、错误){
用户=(用户)目标;
验证(user.getAddress(),错误,“地址”);
}
}
参考资料:
private User manager;
private User operator;
像这样
@Valid
private User manager;
@Valid
private User operator;
如何对
项目执行验证?是否有自定义验证程序?您使用JSR-303验证吗?没有验证程序。我不知道怎么做。应该给你一个开始。我已经阅读了tt,我知道如何验证java类型的属性,但是我不知道复杂类型的验证,就像我的示例一样。我试着按照你的步骤。然而,它并没有像我预期的那样工作。你能查一下我的更新吗?谢谢。errors.rejectValue(“manager.id”,…)
。我无法尝试此操作,因为项目对象容器还包含另一个需要验证的用户实例操作符。那么,ProjectValidator应该完成此操作。另外,只调用控制器中的一个验证器更干净。看看我编辑过的答案。
private User manager;
private User operator;
@Valid
private User manager;
@Valid
private User operator;