Java 调车场中括号的保留
我正在研究本质上是调车场算法,但将中缀改为前缀,而不是RPN 我在努力保留括号,我现在过得很糟糕。目前我的代码是Java 调车场中括号的保留,java,string,algorithm,shunting-yard,Java,String,Algorithm,Shunting Yard,我正在研究本质上是调车场算法,但将中缀改为前缀,而不是RPN 我在努力保留括号,我现在过得很糟糕。目前我的代码是 String s = inFixList.get(i); Stack<Character> opStack = new Stack<Character>(); Stack<Character> solutionStack = new Stack<Character>();
String s = inFixList.get(i);
Stack<Character> opStack = new Stack<Character>();
Stack<Character> solutionStack = new Stack<Character>();
String solution = "";
for(char c : s.toCharArray())
{
if(Character.isLetter(c)||Character.isDigit(c))
{
solutionStack.push(c);
}
else if(c == '(')
{
opStack.push(c);
solutionStack.push(')');
}
else if(c == ')')
{
while(opStack.peek() != '(')
{
solutionStack.push(opStack.pop());
solutionStack.push('(');
}
opStack.pop();
}
else if (!Character.isSpaceChar(c))
{
if(opStack.isEmpty())
{
opStack.push(c);
}
else if(opStack.peek()!='(' &&(OPERATORS.indexOf(c) < OPERATORS.indexOf(opStack.peek())))
{
opStack.push(c);
}
else if(!opStack.isEmpty()&&(opStack.peek()!='('))
{
solutionStack.push(opStack.pop());
solutionStack.push('(');
opStack.push(c);
}
else
{
opStack.push(c);
}
}
}
while(opStack.size() != 0)
{
solutionStack.push(opStack.pop());
solutionStack.push('(');
}
while(!solutionStack.isEmpty())
{
solution+=solutionStack.pop();
}
System.out.println("Final Answer!"+solution);
String s=inFixList.get(i);
Stack opStack=新堆栈();
堆栈解决方案堆栈=新堆栈();
字符串解=”;
for(char c:s.toCharArray())
{
if(Character.islitter(c)| | Character.isDigit(c))
{
溶液粘度推压(c);
}
else如果(c=='(')
{
opStack.push(c);
溶液粘度推压(');
}
如果(c=='),则为else)
{
而(opStack.peek()!='(')
{
solutionStack.push(opStack.pop());
溶液粘度.推力('(');
}
opStack.pop();
}
else如果(!Character.isSpaceChar(c))
{
if(opStack.isEmpty())
{
opStack.push(c);
}
else if(opStack.peek()!='('&&&(OPERATORS.indexOf(c)
这正确地输出了左括号,但只输出了一种右括号。有人知道我应该在哪里添加它们吗?我发誓我错过了最后一个逻辑步骤,无法确定这是否是问题所在,但我在您编写的代码中注意到了这一点
else if(c == '(')
{
opStack.push(c);
solutionStack.push(')');
}
你真的想在这里加一个右括号吗?加一个左括号似乎更合理,尽管我可能错了