Java 尝试将sqlite数据库从android手机发送到web服务器

我正在尝试将一个sqlite数据库从我的android手机发送到一个web服务器。当代码执行时，我没有收到任何错误，但是数据库没有出现在服务器上。下面是我的php代码和从android手机上传文件的代码。连接响应消息是get是“OK”，来自http客户机的响应是org.apache.http.message。BasicHttpResponse@4132dd40.

    public void uploadDatabase() {


    String urli = "http://uploadsite.com";
                String path = sql3.getPath();
                File file = new File(path);

            int bytesRead, bytesAvailable, bufferSize;
            byte[] buffer;
            int maxBufferSize = 1*1024*1024;
            String lineEnd = "\r\n";
            String twoHyphens = "--";
            String boundary =  "*****";


            try {
            HttpClient httpclient = new DefaultHttpClient();

            HttpPost httppost = new HttpPost(urli);

            URL url = new URL(urli);
            connection = (HttpURLConnection) url.openConnection();

            InputStreamEntity reqEntity = new InputStreamEntity(
                    new FileInputStream(file), -1);

            reqEntity.setContentType("binary/octet-stream");
            reqEntity.setChunked(true);

            HttpResponse response = httpclient.execute(httppost);
            String response2 = connection.getResponseMessage();
            Log.i("response", response.toString());
            Log.i("response", response2.toString());
        } catch (Exception e) {

        }
    }


<?php
$uploaddir = '/var/www/mvideos/uploads/';
$file = basename($_FILES['userfile']['name']);
$timestamp = time();
$uploadfile = $uploaddir . $timestamp . '.sq3';

if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
    echo "OK";
} else {
    echo "ERROR: $timestamp";
}

?>

public void uploadDatabase（）{
字符串urli=”http://uploadsite.com";
字符串路径=sql3.getPath（）；
文件=新文件（路径）；
int字节读取，字节可用，缓冲区大小；
字节[]缓冲区；
int maxBufferSize=1*1024*1024；
字符串lineEnd=“\r\n”；
字符串双连字符=“--”；
字符串边界=“*******”；
试一试{
HttpClient HttpClient=新的DefaultHttpClient（）；
HttpPost HttpPost=新的HttpPost（urli）；
URL=新URL（urli）；
connection=（HttpURLConnection）url.openConnection（）；
InputStreamEntity reqEntity=新的InputStreamEntity(
新文件输入流（文件），-1）；
requentity.setContentType（“二进制/八位字节流”）；
reqEntity.setChunked（真）；
HttpResponse response=httpclient.execute（httppost）；
字符串response2=connection.getResponseMessage（）；
Log.i（“response”，response.toString（））；
Log.i（“response”，response2.toString（））；
}捕获（例外e）{
}
}

我基于这个示例编写了代码，效果很好

String pathToOurFile = "/data/dada.jpg"; 
String urlServer = "http://sampleserver.com";

try {
    FileInputStream fis = new FileInputStream(new File(pathToOurFile));
    HttpClient httpClient = new DefaultHttpClient();
    HttpPost postRequest = new HttpPost(urlServer);
    byte[] data = IOUtils.toByteArray(fis);
    InputStreamBody isb = new InputStreamBody(new ByteArrayInputStream(data),pathToOurFile);
    StringBody sb1 = new StringBody("someTextGoesHere");
    StringBody sb2 = new StringBody("someTextGoesHere too");
    MultipartEntity multipartContent = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
    FileBody bin = new FileBody(new File(pathToOurFile));

    multipartContent.addPart("uploadedfile", bin);
    multipartContent.addPart("name", sb1);
    multipartContent.addPart("status", sb2);
    postRequest.setEntity(multipartContent);

    HttpResponse res = httpClient.execute(postRequest);
    res.getEntity().getContent().close();
} catch (Throwable e) {
    e.printStackTrace();
}

---

你让它工作了吗。如果是的话，怎么办。我需要做同样的事情。是的，我没有确切的代码，但我在下面放了一个我基于它的示例。