Java RESTWeb服务JSON格式
我正在尝试创建一个RESTWeb服务,它返回用户的详细信息 这是我的密码:Java RESTWeb服务JSON格式,java,json,web-services,rest,Java,Json,Web Services,Rest,我正在尝试创建一个RESTWeb服务,它返回用户的详细信息 这是我的密码: //Actual web service methods implemented from here @GET @Path("login/{email}/{password}") @Produces("application/json") public Tourist loginUser(@PathParam("email") String email, @PathParam("passw
//Actual web service methods implemented from here
@GET
@Path("login/{email}/{password}")
@Produces("application/json")
public Tourist loginUser(@PathParam("email") String email, @PathParam("password") String password) {
List<Tourist> tourists = super.findAll();
for (Tourist tourist : tourists) {
if (tourist.getEmail().equals(email) && tourist.getPassword().equals(password)) {
return tourist;
}
}
//if we got here the login failed
return null;
}
我需要的是:
{"tourist":{
"email": "adrian.olar@email.ro",
"fname": "Adrian",
"lname": "Olar",
"touristId": 1
}
}
我需要向我的代码中添加什么才能生成此对象?如果您真的想将游客
包装到另一个对象中,您可以这样做
tourism.java
:
package entities;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Tourist {
int touristId;
String email;
String fname;
String lname;
package entities;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class TouristWrapper {
Tourist tourist;
package rest;
import entities.Tourist;
import entities.TouristWrapper;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
@Path("/so")
public class SOResource {
@GET
@Path("/tourists/{id}")
@Produces("application/json")
public TouristWrapper loginUser(@PathParam("id") int id) {
Tourist tourist = new Tourist(id, "foo@example.com", "John", "Doe");
TouristWrapper touristWrapper = new TouristWrapper(tourist);
return touristWrapper;
}
}
TouristWrapper.java
:
package entities;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Tourist {
int touristId;
String email;
String fname;
String lname;
package entities;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class TouristWrapper {
Tourist tourist;
package rest;
import entities.Tourist;
import entities.TouristWrapper;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
@Path("/so")
public class SOResource {
@GET
@Path("/tourists/{id}")
@Produces("application/json")
public TouristWrapper loginUser(@PathParam("id") int id) {
Tourist tourist = new Tourist(id, "foo@example.com", "John", "Doe");
TouristWrapper touristWrapper = new TouristWrapper(tourist);
return touristWrapper;
}
}
SOResource.java
:
package entities;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Tourist {
int touristId;
String email;
String fname;
String lname;
package entities;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class TouristWrapper {
Tourist tourist;
package rest;
import entities.Tourist;
import entities.TouristWrapper;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
@Path("/so")
public class SOResource {
@GET
@Path("/tourists/{id}")
@Produces("application/json")
public TouristWrapper loginUser(@PathParam("id") int id) {
Tourist tourist = new Tourist(id, "foo@example.com", "John", "Doe");
TouristWrapper touristWrapper = new TouristWrapper(tourist);
return touristWrapper;
}
}
我已经简化了您的用例,但您明白了一点:不返回tourism
,而是返回一个tourismwrapper
。返回的JSON如下所示:
{
"tourist": {
"email": "foo@example.com",
"fname": "John",
"lname": "Doe",
"touristId": 1
}
}
这不是一个有效的JSON,因此在不违反规范的情况下不能使用。您确定这正是您想要的吗?这不是REST服务。json中的链接在哪里?@inf3rno链接不是REST所必需的。我不确定这是否只是一个示例,但您不应该通过GET提交密码信息,因为它会被缓存和检查。@Tichodromuraria您大错特错了。REST应该总是返回超媒体,而不仅仅是普通数据。谢谢,这是我一直在寻找的,我会试试这个