如何在JAVA中读取.txt文件的特定部分_Java

如何在JAVA中读取.txt文件的特定部分

java

如何在JAVA中读取.txt文件的特定部分,java,Java,我一直在试图找出如何从.txt文件中读取。我知道如何读取整个文件，但在文件中的两个特定点之间读取时遇到困难。我还尝试使用scanner类，这是我到目前为止所拥有的： public void readFiles(String fileString)throws FileNotFoundException{ file = new File(fileString); Scanner scanner = null; line="";

我一直在试图找出如何从.txt文件中读取。我知道如何读取整个文件，但在文件中的两个特定点之间读取时遇到困难。我还尝试使用scanner类，这是我到目前为止所拥有的：

public void readFiles(String fileString)throws FileNotFoundException{

        file = new File(fileString);
        Scanner scanner = null; 
        line=""; 


        //access file
        try {
            scanner = new Scanner(file);
        } 
        catch (FileNotFoundException e) {
            System.out.println("File not found.");
        }


            // if more lines in file, go to next line
           while (scanner.hasNext())
            {
               line = scanner.next();


               if (scanner.equals("BGSTART")) //tag in the txt to locate position
               {
                   line = scanner.nextLine();
                   System.out.println(line);
                   lb1.append(line); //attaches to a JTextArea.
                   window2.add(lb1);//adds to JPanel
                }
            }

.txt文件如下所示：

BGSTART //内容 BGEND

当我运行程序时，面板上没有任何内容

我试图在这两点之间阅读它。我没有很多从txt文件中阅读的经验。有什么建议吗？

谢谢。

根据@SubOptimal的问题，假设

BGSTART

和

BGEND

在不同的行上，您需要执行以下操作：

boolean tokenFound = false;
while (scanner.hasNextLine())
{
   line = scanner.nextLine();

   //line, not scanner. 
   if (line.equals("BGSTART")) //tag in the txt to locate position
   {
       tokenFound = true;
   }
   else if (line.equals("BGEND"))
   {
       tokenFound = false;
   }

   if(tokenFound)
   {                   
       System.out.println(line);
       lb1.append(line); //attaches to a JTextArea.
       window2.add(lb1);//adds to JPanel
   }
}

一些改进：

try {
        Scanner scanner = new Scanner(new FileInputStream(file));

        //Moved the rest of the code within the try block.
        //As it was before, if there where any problems loading the file, you would have gotten an error message (File not found)
        //as per your catch block but you would then have gotten an unhandled null pointer exception when you would have tried to
        //execute this bit: scanner.hasNextLine()
        boolean tokenFound = false;
        while (scanner.hasNextLine()) {
            String line = scanner.nextLine().trim();

            //line, not scanner.
            if (line.equals("BGSTART")) //tag in the txt to locate position
            {
                tokenFound = true;
            } else if (line.equals("BGEND")) {
                tokenFound = false;
            }

            if ((tokenFound) && (!line.equals("BGSTART"))) {
                System.out.println(line);
               //I am not sure what is happening here.
                //lb1.append(line); //attaches to a JTextArea.
                //window2.add(lb1);//adds to JPanel
            }
        }
    } catch (Exception e) {
        System.out.println("File not found.");
    }

文件内容：

do not show line one
do not show line two
BGSTART 
this is a line
this is another line
this is a third line
BGEND
do not show line three
do not show line four

根据@SubOptimal的问题，假设

BGSTART

和

BGEND

在不同的行上，您需要执行以下操作：

boolean tokenFound = false;
while (scanner.hasNextLine())
{
   line = scanner.nextLine();

   //line, not scanner. 
   if (line.equals("BGSTART")) //tag in the txt to locate position
   {
       tokenFound = true;
   }
   else if (line.equals("BGEND"))
   {
       tokenFound = false;
   }

   if(tokenFound)
   {                   
       System.out.println(line);
       lb1.append(line); //attaches to a JTextArea.
       window2.add(lb1);//adds to JPanel
   }
}

一些改进：

try {
        Scanner scanner = new Scanner(new FileInputStream(file));

        //Moved the rest of the code within the try block.
        //As it was before, if there where any problems loading the file, you would have gotten an error message (File not found)
        //as per your catch block but you would then have gotten an unhandled null pointer exception when you would have tried to
        //execute this bit: scanner.hasNextLine()
        boolean tokenFound = false;
        while (scanner.hasNextLine()) {
            String line = scanner.nextLine().trim();

            //line, not scanner.
            if (line.equals("BGSTART")) //tag in the txt to locate position
            {
                tokenFound = true;
            } else if (line.equals("BGEND")) {
                tokenFound = false;
            }

            if ((tokenFound) && (!line.equals("BGSTART"))) {
                System.out.println(line);
               //I am not sure what is happening here.
                //lb1.append(line); //attaches to a JTextArea.
                //window2.add(lb1);//adds to JPanel
            }
        }
    } catch (Exception e) {
        System.out.println("File not found.");
    }

文件内容：

do not show line one
do not show line two
BGSTART 
this is a line
this is another line
this is a third line
BGEND
do not show line three
do not show line four

根据@SubOptimal的问题，假设

BGSTART

和

BGEND

在不同的行上，您需要执行以下操作：

boolean tokenFound = false;
while (scanner.hasNextLine())
{
   line = scanner.nextLine();

   //line, not scanner. 
   if (line.equals("BGSTART")) //tag in the txt to locate position
   {
       tokenFound = true;
   }
   else if (line.equals("BGEND"))
   {
       tokenFound = false;
   }

   if(tokenFound)
   {                   
       System.out.println(line);
       lb1.append(line); //attaches to a JTextArea.
       window2.add(lb1);//adds to JPanel
   }
}

一些改进：

try {
        Scanner scanner = new Scanner(new FileInputStream(file));

        //Moved the rest of the code within the try block.
        //As it was before, if there where any problems loading the file, you would have gotten an error message (File not found)
        //as per your catch block but you would then have gotten an unhandled null pointer exception when you would have tried to
        //execute this bit: scanner.hasNextLine()
        boolean tokenFound = false;
        while (scanner.hasNextLine()) {
            String line = scanner.nextLine().trim();

            //line, not scanner.
            if (line.equals("BGSTART")) //tag in the txt to locate position
            {
                tokenFound = true;
            } else if (line.equals("BGEND")) {
                tokenFound = false;
            }

            if ((tokenFound) && (!line.equals("BGSTART"))) {
                System.out.println(line);
               //I am not sure what is happening here.
                //lb1.append(line); //attaches to a JTextArea.
                //window2.add(lb1);//adds to JPanel
            }
        }
    } catch (Exception e) {
        System.out.println("File not found.");
    }

文件内容：

do not show line one
do not show line two
BGSTART 
this is a line
this is another line
this is a third line
BGEND
do not show line three
do not show line four

根据@SubOptimal的问题，假设

BGSTART

和

BGEND

在不同的行上，您需要执行以下操作：

boolean tokenFound = false;
while (scanner.hasNextLine())
{
   line = scanner.nextLine();

   //line, not scanner. 
   if (line.equals("BGSTART")) //tag in the txt to locate position
   {
       tokenFound = true;
   }
   else if (line.equals("BGEND"))
   {
       tokenFound = false;
   }

   if(tokenFound)
   {                   
       System.out.println(line);
       lb1.append(line); //attaches to a JTextArea.
       window2.add(lb1);//adds to JPanel
   }
}

一些改进：

try {
        Scanner scanner = new Scanner(new FileInputStream(file));

        //Moved the rest of the code within the try block.
        //As it was before, if there where any problems loading the file, you would have gotten an error message (File not found)
        //as per your catch block but you would then have gotten an unhandled null pointer exception when you would have tried to
        //execute this bit: scanner.hasNextLine()
        boolean tokenFound = false;
        while (scanner.hasNextLine()) {
            String line = scanner.nextLine().trim();

            //line, not scanner.
            if (line.equals("BGSTART")) //tag in the txt to locate position
            {
                tokenFound = true;
            } else if (line.equals("BGEND")) {
                tokenFound = false;
            }

            if ((tokenFound) && (!line.equals("BGSTART"))) {
                System.out.println(line);
               //I am not sure what is happening here.
                //lb1.append(line); //attaches to a JTextArea.
                //window2.add(lb1);//adds to JPanel
            }
        }
    } catch (Exception e) {
        System.out.println("File not found.");
    }

文件内容：

do not show line one
do not show line two
BGSTART 
this is a line
this is another line
this is a third line
BGEND
do not show line three
do not show line four

为什么不使用子字符串？找到BGSTART和BGEND后，您可以在以下代码行中的某个位置捕获它之间的字符串：

 StringBuilder sb= new StringBuilder();
 while (scanner.hasNextLine()) {
        String line = scanner.nextLine();
        sb.append(line);
 }
String capturedString = sampleString.substring(sb.toString().indexOf("BGSTART"),
          sb.toString().indexOf("BGEND"));

希望这有帮助

为什么不使用子字符串？找到BGSTART和BGEND后，您可以在以下代码行中的某个位置捕获它之间的字符串：

 StringBuilder sb= new StringBuilder();
 while (scanner.hasNextLine()) {
        String line = scanner.nextLine();
        sb.append(line);
 }
String capturedString = sampleString.substring(sb.toString().indexOf("BGSTART"),
          sb.toString().indexOf("BGEND"));

希望这有帮助

为什么不使用子字符串？找到BGSTART和BGEND后，您可以在以下代码行中的某个位置捕获它之间的字符串：

 StringBuilder sb= new StringBuilder();
 while (scanner.hasNextLine()) {
        String line = scanner.nextLine();
        sb.append(line);
 }
String capturedString = sampleString.substring(sb.toString().indexOf("BGSTART"),
          sb.toString().indexOf("BGEND"));

希望这有帮助

为什么不使用子字符串？找到BGSTART和BGEND后，您可以在以下代码行中的某个位置捕获它之间的字符串：

 StringBuilder sb= new StringBuilder();
 while (scanner.hasNextLine()) {
        String line = scanner.nextLine();
        sb.append(line);
 }
String capturedString = sampleString.substring(sb.toString().indexOf("BGSTART"),
          sb.toString().indexOf("BGEND"));

希望这有助于

几乎很好，但您正在做：

 if (scanner.equals("BGSTART")) //tag in the txt to locate position

您应该在

行

变量而不是

扫描仪

中查找文件内容
所以试试这个：

 if (line.equals("BGSTART")) //tag in the txt to locate position

几乎不错，但你正在做：

 if (scanner.equals("BGSTART")) //tag in the txt to locate position

您应该在

行

变量而不是

扫描仪

中查找文件内容
所以试试这个：

 if (line.equals("BGSTART")) //tag in the txt to locate position

几乎不错，但你正在做：

 if (scanner.equals("BGSTART")) //tag in the txt to locate position

您应该在

行

变量而不是

扫描仪

中查找文件内容
所以试试这个：

 if (line.equals("BGSTART")) //tag in the txt to locate position

几乎不错，但你正在做：

 if (scanner.equals("BGSTART")) //tag in the txt to locate position

您应该在

行

变量而不是

扫描仪

中查找文件内容
所以试试这个：

 if (line.equals("BGSTART")) //tag in the txt to locate position

令牌

BGSTART

和

BGEND

是否始终位于单独的行上？请签出

RandomAccessFile

。这是一个关于它的说明是的，它们在单独的行上。令牌

BGSTART

和

BGEND

始终在单独的行上吗？请查看

RandomAccessFile

。这是一个关于它的说明是的，它们在单独的行上。令牌

BGSTART

和

BGEND

始终在单独的行上吗？请查看

RandomAccessFile

。这是一个关于它的说明是的，它们在单独的行上。令牌

BGSTART

和

BGEND

始终在单独的行上吗？请查看

RandomAccessFile

。这是一个关于它的例子是的，它们在一个单独的行上。你的代码按预期打印，但它会用每个单词而不是短语创建一个新行。我尝试将line更改为line=scanner.nextLine（），但它不打印任何内容。我还得到一个异常“java.util.NoSuchElementException”，似乎在同一行。@Varoag：对不起，我的错，我做了一些更改，您的代码现在是这样的吗？（人们通常从文件中读取行，以某种方式读取您的

next

调用

nextLine

。）我添加了更改后的代码。现在它没有空格。基本上，文本是一整行。您建议使用行拆分器吗？@Varoag:为了避免多次编辑，您的BGSTART和BDEND是否会在没有其他单词的情况下位于单独的行上？此外，单词之间的空格也会被省略，您的代码也会按预期打印，但它会使用每个单词而不是短语创建新行。我尝试将line更改为line=scanner.nextLine（），但它不打印任何内容。我还得到一个异常“java.util.NoSuchElementException”，似乎在同一行。@Varoag：对不起，我的错，我做了一些更改，您的代码现在是这样的吗？（人们通常从文件中读取行，以某种方式读取您的

next

调用

nextLine

next

调用

nextLine