Java Can'；t实现字符串输出

如果我输入600 153 100 1，那么它将是是的，我可以煮那么多咖啡（甚至比那多1杯）

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但是这个权利是的，我可以煮那么多的咖啡（甚至比那多两杯）

你在煮咖啡

，而
你的配料太多了。

这意味着如果你的配料量正好合适，你就不会煮咖啡了

尝试更改此选项：

while（amountWater>200&&amountMilk>50&&amountCoffeeBeans>15）

为此：

while（amountWater>=200&&amountMilk>=50&&amountCoffeeBeans>=15）
当您只需要200份水时，为什么需要201份水（其他两种成分也是如此）？你当时是怎么想的？在这段时间内检查一下你的情况——正如前面提到的，你可以用200毫升水、50毫升牛奶和15克咖啡来煮咖啡，所以“>”可能是个问题。
        System.out.println("Write how many ml of water the coffee machine has: ");
    int waterInMachine = scanner.nextInt();
    System.out.println("Write how many ml of milk the coffee machine has: ");
    int milkInMachine = scanner.nextInt();
    System.out.println("Write how many grams of coffee beans the coffee machine has: ");
    int beansInMachine = scanner.nextInt();
    System.out.println("Write how many cups of coffee you will need: ");
    int countCups = scanner.nextInt();

    int water = 200 * countCups;
    int milk = 50 * countCups;
    int coffeeBeans = 15 * countCups;

    int amountWater = waterInMachine;
    int amountMilk = milkInMachine;
    int amountCoffeeBeans = beansInMachine;

    int count = 0;

    while (amountWater > 200 && amountMilk > 50 && amountCoffeeBeans > 15) {
        amountWater -= 200;
        amountMilk -= 50;
        amountCoffeeBeans -= 15;
        count++;
    }

    if (waterInMachine >= water && milkInMachine >= milk && beansInMachine >= coffeeBeans && count > countCups) {
        System.out.println("Yes, I can make that amount of coffee (and even " + (count - countCups) + " more than that)");
    } else if (waterInMachine >= water && milkInMachine >= milk && beansInMachine >= coffeeBeans) {
        System.out.println("Yes, I can make that amount of coffee");
    } else if (count < countCups) {
        System.out.println("No, I can make only " + count + " cup(s) of coffee");
    }

 if (waterInMachine> = water && milkInMachine> = milk && beansInMachine> = coffeeBeans && count> countCups) {
            System.out.println ("Yes, I can make that amount of coffee (and even" + (count) + "more than that)"); 
}