Java Spring批处理在启动运行方法之前启动simplejoblancher运行方法

我的作业配置如下所示

@SpringBootApplication
public class Test implements CommandLineRunner {

    @Autowired
    JobLauncher jobLauncher;

    @Autowired
    Job job;

    @Autowired
    private JobBuilderFactory jobs;

    @Autowired
    private StepBuilderFactory steps;

    public static void main(String[] args) {
        SpringApplication.run(Test.class, args);
    }

    @Override
    public void run(String... args) throws Exception {
        JobParameters params = new JobParametersBuilder()
                .addString("JobID", String.valueOf(System.currentTimeMillis()))
                .toJobParameters();
        jobLauncher.run(job, params);
    }
}

现在的问题是，当我运行这个测试应用程序时，SimpleZoblancher会在创建JobParameters之前启动run方法。从日志

10:12:58.422 - [    main] - INFO  SimpleJobLauncher                        - Job: [SimpleJob: [name=demoJob]] launched with the following parameters: [{}]
10:12:58.466 - [    main] - INFO  SimpleStepHandler                        - Step already complete or not restartable, so no action to execute: StepExecution: id=14, version=3, name=stepOne, status=COMPLETED, exitStatus=COMPLETED, readCount=0, filterCount=0, writeCount=0 readSkipCount=0, writeSkipCount=0, processSkipCount=0, commitCount=1, rollbackCount=0, exitDescription=
10:12:58.478 - [    main] - INFO  SimpleStepHandler                        - Step already complete or not restartable, so no action to execute: StepExecution: id=15, version=3, name=stepTwo, status=COMPLETED, exitStatus=COMPLETED, readCount=0, filterCount=0, writeCount=0 readSkipCount=0, writeSkipCount=0, processSkipCount=0, commitCount=1, rollbackCount=0, exitDescription=
10:12:58.498 - [    main] - INFO  SimpleJobLauncher                        - Job: [SimpleJob: [name=demoJob]] completed with the following parameters: [{}] and the following status: [COMPLETED] in 44ms
10:12:58.530 - [    main] - INFO  SimpleJobLauncher                        - Job: [SimpleJob: [name=demoJob]] launched with the following parameters: [{JobID=1592381578499}]

正如您从日志中看到的，第一个demoJob是在没有参数的情况下启动的

10:12:58.422 - [    main] - INFO  SimpleJobLauncher                        - Job: [SimpleJob: [name=demoJob]] launched with the following parameters: [{}]

在没有参数的情况下完成作业后，它将使用参数再次启动

10:12:58.530 - [    main] - INFO  SimpleJobLauncher                        - Job: [SimpleJob: [name=demoJob]] launched with the following parameters: [{JobID=1592381578499}]

假设应用程序中有两个作业，那么即使我想用指定的参数运行一个特定的作业，也会启动这两个作业

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是否仍有控制此行为的方法，以便Spring batch仅启动带有我需要的参数的作业

您可以通过向application.yml或application.properties添加属性来禁用启动时自动执行作业

spring.batch.job.enabled: false

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您的意思是在集成测试中禁用它，使用相同的属性spring.batch.job.enabled:false并将其放在项目的src/test/resources目录下的application.yml或application.properties中