Java ORA-00979中的jOOQ JSON查询结果
我正在尝试对Oracle 19c数据库执行此查询:Java ORA-00979中的jOOQ JSON查询结果,java,jooq,Java,Jooq,我正在尝试对Oracle 19c数据库执行此查询: Field<JSON> employee = DSL.field("employee", JSON.class); Table<Record1<JSON>> employees = dsl .select(jsonObject(jsonEntry("id", EMPLOYEE.ID), jsonEntry("name", E
Field<JSON> employee = DSL.field("employee", JSON.class);
Table<Record1<JSON>> employees = dsl
.select(jsonObject(jsonEntry("id", EMPLOYEE.ID), jsonEntry("name", EMPLOYEE.NAME), jsonEntry("phones",
jsonArrayAgg(
jsonObject(jsonEntry("number", PHONE.PHONENUMBER), jsonEntry("type", PHONE.TYPE)))
)).as(employee))
.from(EMPLOYEE)
.join(PHONE).on(PHONE.EMPLOYEE_ID.eq(EMPLOYEE.ID))
.groupBy(EMPLOYEE.ID)
.asTable();
String json = dsl
.select(jsonArrayAgg(employees.field(employee)))
.from(employees)
.fetchOneInto(String.class);
jOOQs JSON功能不适用于Oracle吗?这与您的JSON使用无关。如果将其全部删除并编写此查询,也会发生同样的情况:
dsl.select(EMPLOYEE.ID,EMPLOYEE.NAME)
.来自(雇员)
.join(电话).on(电话.员工ID.eq(员工ID))
.groupBy(EMPLOYEE.ID);
您的查询将在MySQL、PostgreSQL或标准SQL中工作,在按主键列分组后,您仍然可以投影所有功能相关的列。但在甲骨文中,这是行不通的。因此,您必须将EMPLOYEE.NAME
添加到groupby
子句中
有一个相应转换SQL的功能请求,但jOOQ 3.14还不支持此功能:
请注意,
JSON_ARRAYAGG()
将空集聚合为NULL
,而不是聚合为空的[]
哦,对了。愚蠢的我!我正在将测试从PostgreSQL迁移到Oracle:-)谢谢!
org.springframework.jdbc.BadSqlGrammarException: jOOQ; bad SQL grammar
[select json_arrayagg("alias_113372058".employee) from
(select json_object(key ? value "EMPLOYEE"."ID", key ? value "EMPLOYEE"."NAME", key ? value json_arrayagg(json_object(key ? value "PHONE"."PHONENUMBER", key ? value "PHONE"."TYPE"))) employee from "EMPLOYEE" join "PHONE" on "PHONE"."EMPLOYEE_ID" = "EMPLOYEE"."ID" group by "EMPLOYEE"."ID") "alias_113372058"];
nested exception is java.sql.SQLSyntaxErrorException: ORA-00979: Kein GROUP BY-Ausdruck