Java contains(otherString)给出;“意外类型”;
上述内容将不会编译,并给出错误“意外类型。必需:变量,找到:值” 我不明白为什么String.contains()应该返回布尔值Java contains(otherString)给出;“意外类型”;,java,string,contains,bluej,Java,String,Contains,Bluej,上述内容将不会编译,并给出错误“意外类型。必需:变量,找到:值” 我不明白为什么String.contains()应该返回布尔值 String doubleSpace = " "; String news = "The cat jumped. The dog did not."; while (news.contains(doubleSpace) = true) { news=news.replaceAll(" ", " "); } while (news.contains(d
String doubleSpace = " ";
String news = "The cat jumped. The dog did not.";
while (news.contains(doubleSpace) = true)
{
news=news.replaceAll(" ", " ");
}
while (news.contains(doubleSpace))
{
news=news.replaceAll(" ", " ");
}
应该是
while (news.contains(doubleSpace) = true)
while (news.contains(doubleSpace) = true)
=用于分配
==用于检查条件。您的while循环是错误的,请执行以下操作。您通过使用赋值进行赋值,因此会得到该错误。也无需与true进行比较,因为
包含(…)
函数本身将根据需要返回true或false
while (news.contains(doubleSpace) == true)
{
news=news.replaceAll(" ", " ");
}
有一个编译错误 应该是
while (news.contains(doubleSpace) = true)
while (news.contains(doubleSpace) = true)
字符串上的方法.contains()已返回布尔值
所以你不应该应用比较
无论如何,如果应用布尔运算符'='而不是'='
所以你的代码可以
while(news.contains(doubleSpace)==true)
或者更准确地说