Java hibernate4:外键引用的列数错误。应该是2

我试图使用Hibernate注释为我的数据库表编写一个模型类

我有两个表，每个表都有一个主键

User

和

ChartDetails

package com.winnow.springservice.domain;

import java.io.Serializable;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;


//User Entity class mapped with hibernate
@Entity
@Table(name="User")
@SuppressWarnings(value = { "all" })
public class User implements Serializable
{

@Id
@Column(name="user_id")
public String user_Id;

@Column(name="user_name")
public String userName;
public String password;

@Column(name="last_login")
public String last_Login;

@Column(name="role_id")
public int role_Id;
public int status;




public String getUser_Id() {
    return user_Id;
}

public void setUser_Id(String user_Id) {
    this.user_Id = user_Id;
}

public String getLast_Login() {
    return last_Login;
}

public void setLast_Login(String last_Login) {
    this.last_Login = last_Login;
}

public int getRole_Id() {
    return role_Id;
}

public void setRole_Id(int role_Id) {
    this.role_Id = role_Id;
}

public int getStatus() {
    return status;
}

public void setStatus(int status) {
    this.status = status;
}

public String getUserName() {
    return userName;
}

public void setUserName(String userName) {

    System.out.println("username"+userName);
    this.userName = userName;
}

public String getPassword() {
    return password;
}

public void setPassword(String password)
{
    System.out.println("password "+password);
    this.password = password;
}


}

图表详情

package com.winnow.springservice.domain;

import java.io.Serializable;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name="Chart_Details")
@SuppressWarnings(value = { "all" })
public class ChartDetails implements Serializable
{

@Id
@Column(name="chart_id")
public int chartId;

@Id
@Column(name="chart_type_id")
public int chartTypeId;

@Column(name="chart_name")
public String chartName;

@Column(name="x_axis")
public String x_axis;

@Column(name="y_axis")
public String y_axis;

@Column(name="z_axis")
public int z_axis;

@Column(name="chart_filter_id")
public int chartFilterId;

@Column(name="is_data_table")
public boolean isDataTable;

@Column(name="dataset_id")
public int datasetId;

@Column(name="user_id")
public int userId;


@Column(name="project_id")
public int projectId;

}

我还有一个表-

chartstarredby

，它将

userId

和

chart\u id

作为上述两个表的外键

但我无法找到如何在

图表tarredby

表中引用这些约束

package com.winnow.springservice.domain;

import java.io.Serializable;
import java.util.Date;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.OneToMany;
import javax.persistence.OneToOne;
import javax.persistence.Table;
import javax.persistence.Temporal;
import javax.persistence.TemporalType;


@Entity
@Table(name="Chart_Starred_By")
@SuppressWarnings(value = { "all" })
public class ChartsStarredBy implements Serializable
{

@Id
public int id;

@Temporal(TemporalType.DATE)
public Date starred_date;


@ManyToOne
@JoinColumn(name = "FK_chart_id4")
private  ChartDetails chart_details;

@ManyToOne
@JoinColumn(name = "FK_user_id4")
private User user;

public Date getStarred_date() 
{
    return starred_date;
}

public void setStarred_date(Date starred_date) 
{
    this.starred_date = starred_date;
}

public User getUser() 
{
    return user;
}

public void setUser(User user) 
{
    this.user = user;
}

public ChartDetails getChart_details() {
    return chart_details;
}

public void setChart_details(ChartDetails chart_details) {
    this.chart_details = chart_details;
}

}

---

请帮我做到这一点？提前感谢。

首先，您应该为用户表创建一个作为主键的整数id。在代码中，您可以将其创建为字符串类型。

你在这里做错了

@ManyToOne
@JoinColumn(name = "FK_chart_id4")
private  ChartDetails chart_details;

@ManyToOne
@JoinColumn(name = "FK_user_id4")
private User user;

用户表和图表详细信息表中的ID为

@Id
@Column(name="user_id")
public String user_Id;

AND

@Id
@Column(name="chart_id")
public int chartId;

因此，当您引用另一个类的id时，应该在@JoinColumn中给出该id的名称。就这样

@ManyToOne
@JoinColumn(name = "chartId")
private  ChartDetails chart_details;

@ManyToOne
@JoinColumn(name = "user_Id")
private User user;

@ManyToOne
@ForeignKey(name = "user_Id")
private User    user;

您还可以像这样使用Hibernate中的@ForeignKey（name=“user\u Id”）注释

@ManyToOne
@JoinColumn(name = "chartId")
private  ChartDetails chart_details;

@ManyToOne
@JoinColumn(name = "user_Id")
private User user;

@ManyToOne
@ForeignKey(name = "user_Id")
private User    user;

---

示例教程：-

请在此处发布之前缩减源代码。不要用自动生成的JavaDoc让我们厌烦。使用一致的缩进，以便源代码高亮显示可以工作。所有这些都是对你希望得到帮助的人的礼貌。你问题的标题是什么意思？您收到的是错误消息吗？我在你的代码中看不到任何“Hibernate注释”——它们都是标准的JPA。