如何通过双击图标来执行JAVA程序?
我已经写了一个java程序。现在我想在没有IDE、Eclipse等的情况下打开控制台java应用程序,但只需双击桌面上的可执行版本即可 我已经在Runnable.JAR文件中导出了java项目,但它无法打开。当我试图用cmd打开应用程序时。java-jarapplicationName.jar,一切正常。但是这个过程太复杂了,而且对用户不友好 那么,有没有任何可能的方法可以用JAVA来做这样的事情呢如何通过双击图标来执行JAVA程序?,java,file,icons,exe,double-click,Java,File,Icons,Exe,Double Click,我已经写了一个java程序。现在我想在没有IDE、Eclipse等的情况下打开控制台java应用程序,但只需双击桌面上的可执行版本即可 我已经在Runnable.JAR文件中导出了java项目,但它无法打开。当我试图用cmd打开应用程序时。java-jarapplicationName.jar,一切正常。但是这个过程太复杂了,而且对用户不友好 那么,有没有任何可能的方法可以用JAVA来做这样的事情呢 提前感谢:)根据操作系统创建一个bat或sh文件,并将java-jar ApplicationN
提前感谢:)根据操作系统创建一个
bat
或sh
文件,并将java-jar ApplicationName.jar
放在该文件中
您可以双击该文件来启动应用程序
Windows的示例:
创建一个文件
MyProgram.bat
。在文本编辑器中打开该文件。添加java-jar MyApplicationName.jar
(将MyApplicationName替换为应用程序的名称/jar的名称)。保存文件。双击创建的文件打开您的程序。今天早上我遇到了同样的问题,搜索了一下,然后根据可用的知识创建了一个静态类。它解决了Windows的问题,但其他系统的用户应该能够轻松添加必要的内容-我只是不知道正确的系统命令(如果有)。我保留了printEnvironmentInfo()方法以寻求帮助
它的作用:
它支持标准Java控制台应用程序的双击启动,而无需更改操作系统或创建文件。程序如下:
import javax.swing.*;
import java.io.File;
import java.io.IOException;
import java.security.CodeSource;
import java.util.Map;
import java.util.Properties;
/**
* Created by Reddit user king_of_the_universe / StackOverflow user Dreamspace President / dreamspace-president.com
* <p>
* v[(2), 2015-11-13 13:00 UTC]
* <p>
* One static method call will start a new instance of *THIS* application in the console and will EXIT the current
* instance. SO FAR ONLY WORKS ON WINDOWS! Users of other systems need to assist here. The methods are all in place.
*/
final public class AutoRunFromConsole {
final private static String FAILMESSAGE_TITLE = "Please run in console.";
final private static String FAILMESSAGE_BODY = "This application must be run in the console (or \"command box\").\n\nIn there, you have to type:\n\njava -jar nameofprogram.jar";
private static void showFailMessageAndExit() {
JOptionPane.showMessageDialog(null, FAILMESSAGE_BODY, FAILMESSAGE_TITLE, JOptionPane.INFORMATION_MESSAGE);
System.exit(0);
}
private enum OSType {
UNDETERMINED, WINDOWS, LINUX, MACOS
}
private static OSType getOsType() {
// final String osName = System.getProperty("os.name");
// final String osVersion = System.getProperty("os.version");
// final String osArchitecture = System.getProperty("os.arch");
// System.out.println("\n\nOSNAME: " + osName);
// System.out.println("\n\nOSVERSION: " + osVersion);
// System.out.println("\n\nOSARCHITECTURE: " + osArchitecture);
final String osName = System.getProperty("os.name", "").toLowerCase();
if (osName.startsWith("windows")) {
return OSType.WINDOWS;
} else if (osName.startsWith("linux")) {
return OSType.LINUX;
} else if (osName.startsWith("mac os") || osName.startsWith("macos") || osName.startsWith("darwin")) {
return OSType.MACOS;
}
return OSType.UNDETERMINED;
}
/**
* Checks if the program is currently running in console, and if not, starts the program from console and EXITS this
* instance of the program. Should be (one of) the first calls in your program.
* <p>
* This is the less safe variant of the method: To check if you're currently in the IDE, it just tries to find the
* executable name and if it exists in the current path. This should word perfectly at all times in IntelliJ - I
* don't know what values getExecutableName() returns inside Eclipse, but I suspect it will work just as well.
* <p>
* It's also less safe because you can't give a fallback executable name, but I believe it should do the trick in
* all situations.
* <p>
* If this is used on a system other than Windows, a message box is shown telling the user to start the program from
* the console. BECAUSE I DON'T KNOW HOW TO OPEN A CONSOLE ON OTHER SYSTEMS. SEE startExecutableInConsole();
*/
public static void runYourselfInConsole(final boolean stayOpenAfterEnd) {
runYourselfInConsole(false, stayOpenAfterEnd, null, null);
}
/**
* Checks if the program is currently running in console, and if not, starts the program from console and EXITS this
* instance of the program. Should be (one of) the first calls in your program.
* <p>
* This is the safer variant of the method: The first command line argument GIVEN BY THE IDE'S RUN CONFIGURATION
* should be "ide" (Case is ignored.), which this method will use to determine if it's running from the IDE.
* <p>
* It is also safer because you can give a fallback executable name in case getExecutableName() could not determine
* it.
* <p>
* Ultimately, it is safer because if the executable could not be determined, it shows a message box telling the
* user to start the program from the console.
* <p>
* You will probably never make use of this variant. It's meant to be a solution if all else seems to fail (e.g.
* customer calls and you need a quick fix).
* <p>
* If this is used on a system other than Windows, a message box is shown telling the user to start the program from
* the console. BECAUSE I DON'T KNOW HOW TO OPEN A CONSOLE ON OTHER SYSTEMS. SEE startExecutableInConsole();
*
* @param psvmArguments The arguments given to the main method.
* @param fallbackExecutableName Can be null. In case getExecutableName() can't determine the proper name, the
* fallback is used.
*/
public static void runYourselfInConsole(final String[] psvmArguments, final String fallbackExecutableName, final boolean stayOpenAfterEnd) {
runYourselfInConsole(true, stayOpenAfterEnd, psvmArguments, fallbackExecutableName);
}
/**
* see the other two methods
*/
private static void runYourselfInConsole(final boolean useSaferApproach, final boolean stayOpenAfterEnd, final String[] psvmArguments, final String fallbackExecutableName) {
String executableName = getExecutableName(fallbackExecutableName);
if (useSaferApproach) {
if (isRunFromIDE(psvmArguments)) {
return;
}
} else {
if (executableName == null) {
// Running from IDE.
return;
}
}
if (isRunningInConsole()) {
return;
}
if (executableName == null) {
showFailMessageAndExit();
}
startExecutableInConsole(executableName, stayOpenAfterEnd);
System.exit(0);
}
/**
* Opens a console window and starts the Java executable there.
* <p>
* If this is used on a system other than Windows, a message box is shown telling the user to start the program from
* the console. BECAUSE I DON'T KNOW HOW TO OPEN A CONSOLE ON OTHER SYSTEMS.
*
* @param executableName the full file name of the executable (without path)
* @param stayOpenAfterEnd If true (and if someone can figure out the necessary parameters for other systems than
* Windows), the console will not close once the executable has terminated. This is useful
* e.g. if you want to give some kind of bye bye message because you actually assumed that
* people start the program from console manually.
*/
private static void startExecutableInConsole(final String executableName, final boolean stayOpenAfterEnd) {
String launchString = null;
switch (getOsType()) {
case UNDETERMINED:
break;
case WINDOWS:
if (stayOpenAfterEnd) {
launchString = "cmd /c start cmd /k java -jar \"" + executableName+"\""; // No, using /k directly here DOES NOT do the trick.
} else {
launchString = "cmd /c start java -jar \"" + executableName+"\"";
}
break;
case LINUX:
break;
case MACOS:
// launchString="/usr/bin/open -a Terminal /path/to/the/executable";
break;
}
if (launchString == null) {
showFailMessageAndExit();
}
try {
Runtime.getRuntime().exec(launchString);
} catch (IOException e) {
e.printStackTrace();
}
}
/**
* @param args the args as given to PSVM
* @return whether the first command line argument was "ide" (ignoring case). Don't forget to change your IDE's run
* configuration accordingly.
*/
private static boolean isRunFromIDE(final String[] args) {
return args != null && args.length > 0 && args[0].equalsIgnoreCase("ide");
}
/**
* @return if System.console() is available. DOES NOT WORK properly from IDE, will return false then even though it
* should be true. Use isRunFromIDE or other means additionally.
*/
private static boolean isRunningInConsole() {
return System.console() != null;
}
/**
* @param fallbackExecutableName Can be null. In the very unlikely case this method can't determine the executable,
* the fallback will also be checked. But if the fallback also doesn't exist AS A FILE
* in the CURRENT path, null will be returned regardless, even if you're sure that
* your fallback should be correct.
* @return the name of the running jar file, OR NULL if it could not be determined (which should be a certainty
* while in IDE, hence can be abused for determining that).
*/
public static String getExecutableName(final String fallbackExecutableName) {
// APPROACH 1 - THE ONE EVERYBODY ON STACKOVERFLOW IS REPEATING
String executableNameFromClass = null;
final CodeSource codeSource = AutoRunFromConsole.class.getProtectionDomain().getCodeSource();
if (codeSource == null) {
System.err.println("UNEXPECTED: Main.class.getProtectionDomain().getCodeSource() returned null");
} else {
final String path = codeSource.getLocation().getPath();
if (path == null || path.isEmpty()) {
System.err.println("UNEXPECTED: codeSource.getLocation().getPath() returned null or empty");
} else {
executableNameFromClass = new File(path).getName();
}
}
// APPROACH 2 - QUERY SYSTEM PROPERTIES
final Properties properties = System.getProperties();
final String executableNameFromJavaClassPathProperty = properties.getProperty("java.class.path");
final String executableNameFromSunJavaCommandProperty = properties.getProperty("sun.java.command");
// System.out.println("\n\nexecutableNameFromClass:\n" + executableNameFromClass);
// System.out.println("\n\nexecutableNameFromJavaClassPathProperty:\n" + executableNameFromJavaClassPathProperty);
// System.out.println("\n\nexecutableNameFromSunJavaCommandProperty:\n" + executableNameFromSunJavaCommandProperty);
// System.out.println("\n\nfallbackExecutableName:\n" + fallbackExecutableName);
if (isThisProbablyTheExecutable(executableNameFromClass)) {
return executableNameFromClass;
}
if (isThisProbablyTheExecutable(executableNameFromJavaClassPathProperty)) {
return executableNameFromJavaClassPathProperty;
}
if (isThisProbablyTheExecutable(executableNameFromSunJavaCommandProperty)) {
return executableNameFromSunJavaCommandProperty;
}
if (isThisProbablyTheExecutable(fallbackExecutableName)) {
return fallbackExecutableName;
}
return null;
}
/**
* @param candidateName suspected name of the running java executable
* @return if name is not null, ends with ".jar" (Case is ignored.), and points to a FILE existing in the CURRENT
* directory.
*/
private static boolean isThisProbablyTheExecutable(final String candidateName) {
if (candidateName == null || !candidateName.toLowerCase().endsWith(".jar")) {
return false;
}
final File file = new File(candidateName);
return file.exists() && file.isFile();
}
public static void main(final String[] args) {
AutoRunFromConsole.runYourselfInConsole(true);
printEnvironmentInfo();
}
/**
* for debugging purposes
*/
public static void printEnvironmentInfo() {
System.out.println("\n\n\n\n-------------------------- System.getProperties() --------------------------");
final Properties properties = System.getProperties();
for (final Map.Entry<Object, Object> entry : properties.entrySet()) {
System.out.println(entry);
}
System.out.println("\n\n\n\n----------------------------- System.getenv() ------------------------------");
final Map<String, String> env = System.getenv();
for (final Map.Entry<String, String> entry : env.entrySet()) {
System.out.println(entry);
}
System.out.print("\n\n\n\n");
}
}
import javax.swing.*;
导入java.io.File;
导入java.io.IOException;
导入java.security.CodeSource;
导入java.util.Map;
导入java.util.Properties;
/**
*由Reddit用户king_of the_universe/StackOverflow用户Dreamspace President/Dreamspace-President.com创建
*
*v[(2),2015-11-13 13:00 UTC]
*
*一个静态方法调用将在控制台中启动*THIS*应用程序的新实例,并将退出当前
*例如。到目前为止,只适用于WINDOWS!其他系统的用户需要在此提供帮助。这些方法都已到位。
*/
最终公共类控制台{
最终私有静态字符串失败消息\u TITLE=“请在控制台中运行。”;
final private static String FAILMESSAGE\u BODY=“此应用程序必须在控制台(或\“命令框\”)中运行。\n\n在此,您必须键入:\n\njava-jar nameofprogram.jar”;
私有静态void showFailMessageAndExit(){
JOptionPane.showMessageDialog(null,FAILMESSAGE\u正文,FAILMESSAGE\u标题,JOptionPane.INFORMATION\u消息);
系统出口(0);
}
私有枚举OSType{
未确定,WINDOWS、LINUX、MACOS
}
私有静态OSType getOsType(){
//最后一个字符串osName=System.getProperty(“os.name”);
//最终字符串osVersion=System.getProperty(“os.version”);
//最终字符串osArchitecture=System.getProperty(“os.arch”);
//System.out.println(“\n\nOSNAME:”+osName);
//System.out.println(“\n\nOSVERSION:+osVersion”);
//System.out.println(“\n\n体系结构:“+osArchitecture”);
最后一个字符串osName=System.getProperty(“os.name”,”).toLowerCase();
if(osName.startsWith(“windows”)){
返回OSType.WINDOWS;
}else if(osName.startsWith(“linux”)){
返回OSType.LINUX;
}else if(osName.startsWith(“mac os”)| | osName.startsWith(“macos”)| | osName.startsWith(“达尔文”)){
返回OSType.MACOS;
}
返回OSType.undeminated;
}
/**
*检查该程序当前是否在控制台中运行,如果未运行,则从控制台启动该程序并退出此操作
*程序的实例。应该是程序中的第一个调用之一。
*
*这是该方法的一个不太安全的变体:要检查您当前是否在IDE中,它只会尝试查找
*可执行文件名,以及当前路径中是否存在该文件。这应该在