Java 使用HttpURLConnection而不是HttpPost
我有一个用java编写的android应用程序代码。通过使用HttpPost和DefaultHttpClient库。目前,我正在对其进行重新编码,以将HttpPost和DefaultHttpClient库替换为HttpURLConnection,因为DefaultHttpClient已被删除。 我为我的一个项目做了这件事,它成功了 但是在当前的项目中,当使用HttpURLConnection而不是DefaultHttpClient时,我并没有从Web服务获得相同的响应。谁能帮我一下我哪里做错了 以下是旧代码:Java 使用HttpURLConnection而不是HttpPost,java,android,http-post,httpurlconnection,Java,Android,Http Post,Httpurlconnection,我有一个用java编写的android应用程序代码。通过使用HttpPost和DefaultHttpClient库。目前,我正在对其进行重新编码,以将HttpPost和DefaultHttpClient库替换为HttpURLConnection,因为DefaultHttpClient已被删除。 我为我的一个项目做了这件事,它成功了 但是在当前的项目中,当使用HttpURLConnection而不是DefaultHttpClient时,我并没有从Web服务获得相同的响应。谁能帮我一下我哪里做错了
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
String postParameter = "Param1=" + Value1 + "&Param2="+ Value2+ "&Param3="+Value3;
try {
httpPost.setEntity(new StringEntity(postParameter));
} catch (Exception e) {
e.printStackTrace();
}
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
xml = EntityUtils.toString(httpEntity);
这是我的新代码
_Url = new URL(Url);
HttpURLConnection urlconnection = (HttpURLConnection) _Url.openConnection();
urlconnection.setRequestMethod(Type);
urlconnection.setConnectTimeout(Timeout);
urlconnection.setUseCaches(false);
urlconnection.setDoInput(true);
urlconnection.setDoOutput(true);
String postParameter = "Param1=" + Value1 + "&Param2="+ Value2+ "&Param3="+Value3;
BufferedWriter writer = new BufferedWriter( new OutputStreamWriter(os));
writer.write(postParameter);
writer.flush();
writer.close();
os.close();
urlconnection.connect();
代码正在运行,没有任何错误,但Web服务给出的响应与它对旧代码给出的响应不同。试试这个
List nameValuePairs = new ArrayList(3);
nameValuePairs.add(new BasicNameValuePair("Param1", value1));
nameValuePairs.add(new BasicNameValuePair("Param2", value2));
nameValuePairs.add(new BasicNameValuePair("Param3", value3));
UrlEncodedFormEntity entity = new UrlEncodedFormEntity(nameValuePairs);
OutputStream post = request.getOutputStream();
entity.writeTo(post);
post.flush();
您没有获得输入流,请尝试下面的代码
try {
String postParameter = "Param1=" + Value1 + "&Param2="+ Value2+ "&Param3="+Value3;
URL url = new URL(UrlStr);
HttpURLConnection urlConnection = (HttpURLConnection) url
.openConnection();
urlConnection.setRequestMethod("POST");
urlConnection.setRequestProperty("Accept",
"application/json");
urlConnection.setRequestProperty("Content-Type",
"application/json");// setting your headers its a json in my case set your appropriate header
urlConnection.setDoOutput(true);
urlConnection.connect();// setting your connection
OutputStream os = null;
os = new BufferedOutputStream(
urlConnection.getOutputStream());
os.write(postParameter.toString().getBytes());
os.flush();// writing your data which you post
StringBuffer buffer = new StringBuffer();
InputStream is = urlConnection.getInputStream();
BufferedReader br = new BufferedReader(
new InputStreamReader(is));
String line = null;
while ((line = br.readLine()) != null)
buffer.append(line + "\r\n");
// reading your response
is.close();
urlConnection.disconnect();// close your connection
return buffer.toString();
} catch (Exception e) {
}
尝试过,但得到了与我的代码相同的响应:(您是否从服务器收到任何响应??状态代码等??是的,我收到的响应与您的代码相同,我收到的响应与我的新代码相同,服务器的响应错误。但是原始代码得到的是正确的。httpPost的setEntity方法对参数做了一些与写入outputstream不同的处理??抱歉,我没有在这里用我的问题编写获取inputstream的代码,但我已经在我的应用程序中编写了。我认为问题不在于inputstream。问题在于实体和outputstream。httpPost使用了setEntity方法,而我使用了outputstream和openconnection。我认为setEntity方法对参数做了一些不同的处理与写入OutputStream相比,您的requestmethod是什么?urlconnection.setRequestMethod(Type);只需尝试上面的代码,看看您得到了什么样的响应代码?