Java Android：将动画插入对话框

我想休息一下，使用对话框单击鼠标。在对话框中，我想嵌入小动画。我已经这样做了，但它显示了我的运行时错误

public class Basic extends Activity {
    final Context context = this;
    EditText inputSearch;
    private ListView lv;
    ArrayAdapter<String> adapter;
    AnimationDrawable frameAnimation;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_word);
        // storing string resources into Array
        String[] adobe_products = getResources().getStringArray(R.array.basic_words);

        adapter = new ArrayAdapter<String>(this, R.layout.list_item, R.id.label, adobe_products);
        Arrays.sort(adobe_products, String.CASE_INSENSITIVE_ORDER);
        // ListView lv = getListView();
        lv = (ListView) findViewById(R.id.list);
        inputSearch = (EditText) findViewById(R.id.inputSearch);
        lv.setAdapter(adapter);

        inputSearch.addTextChangedListener(new TextWatcher() {

            @Override
            public void onTextChanged(CharSequence cs, int arg1, int arg2, int arg3) {
                // When user changed the Text
                Basic.this.adapter.getFilter().filter(cs);
            }

            @Override
            public void beforeTextChanged(CharSequence arg0, int arg1, int arg2, int arg3) {
                // TODO Auto-generated method stub

            }

            @Override
            public void afterTextChanged(Editable arg0) {
                // TODO Auto-generated method stub
            }
        });
        // listening to single list item on click
        lv.setOnItemClickListener(new OnItemClickListener() {
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
                String itemValue = (String) parent.getItemAtPosition(position);
                final Dialog dialog = new Dialog(context);

                switch (position) {

                    case 10:
                        dialog.setContentView(R.layout.anim);
                        ImageView image1 = (ImageView) dialog.findViewById(R.id.anim_image);
                        Button dialogButton = (Button) dialog.findViewById(R.id.dialogButtonOK);
                        dialogButton = (Button) dialog.findViewById(R.id.dialogButtonOK);
                        dialog.setTitle(itemValue);
                        image1.setImageResource(R.drawable.spin_animation);
                        frameAnimation = (AnimationDrawable) image1.getBackground();

                        // Start the animation (looped playback by default).
                        frameAnimation.start();
                        dialogButton.setOnClickListener(new OnClickListener() {
                            @Override
                            public void onClick(View v) {
                                dialog.dismiss();
                            }
                        });
                        dialog.show();

                }

            }
        });
    }
}

我的布局：

<!-- language: xml -->
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
tools:context=".MainActivity" >
<ImageView
    android:id="@+id/anim_image"
    android:layout_width="500sp"
    android:layout_height="500sp"/>
</RelativeLayout>

---

您的问题从这里开始：

ImageView image1 = (ImageView)      dialog.findViewById(R.id.anim_image);

---

确保所有findViewById（）方法都返回您想要的结果。其中一些肯定返回null。

有什么错误？显示您的logcat输出。请提供完整信息。此程序中使用的所有图像ID都存在于xml文件中。findViewById如何返回null？布局中没有dialogButtonOK。

ImageView image1 = (ImageView)      dialog.findViewById(R.id.anim_image);