Java 旅行推销员2-opt至3-opt
我试图将旅行推销员问题的2-opt实现转化为3-opt。我知道,与2-opt相比,它是删除3条边并替换它们,希望获得更好的距离。我不知道如何更改/添加我的2-opt交换以使其成为3-opt交换。我面临的主要问题是如何确保在单个掉期函数中考虑所有8种掉期。 多谢各位 2-opt代码:Java 旅行推销员2-opt至3-opt,java,graph,traveling-salesman,Java,Graph,Traveling Salesman,我试图将旅行推销员问题的2-opt实现转化为3-opt。我知道,与2-opt相比,它是删除3条边并替换它们,希望获得更好的距离。我不知道如何更改/添加我的2-opt交换以使其成为3-opt交换。我面临的主要问题是如何确保在单个掉期函数中考虑所有8种掉期。 多谢各位 2-opt代码: private static int[] TwoOpt(int[] TSP) { double best = totalDistance; int numCities = TSP.le
private static int[] TwoOpt(int[] TSP) {
double best = totalDistance;
int numCities = TSP.length;
int visited = 0;
int current = 0;
int[] newTour = TSP;
while (visited < numCities) {
for (int i = 0; i < numCities - 1; i++) {
for (int j = i + 1; j < numCities; j++) {
int[] newerTour = Swap(i, j, newTour);
int newDistance = distance(newerTour);
if (newDistance < best) {
visited = 0;
best = newDistance;
newTour = newerTour;
}
}
}
visited++;
}
return newTour;
}
private static int distance(int[] newTour) {
int distance = 0;
for (int i = 0; i < newTour.length - 1; i++) {
distance += mstList.get(i).get(i + 1).p;
}
distance += mstList.get(newTour.length).get(0).p;
return distance;
}
private static int[] Swap(int i, int j, int[] tour) {
int size = tour.length;
int[] newerTour = new int[tour.length];
for (int c = 0; c <= i - 1; c++) {
newerTour[c] = tour[c];
}
int change = 0;
for (int d = i; d <= j; d++) {
newerTour[d] = tour[d - change];
change++;
}
for (int e = j + 1; e < size; e++) {
newerTour[e] = tour[e];
}
return newerTour;
}
private static int[]TwoOpt(int[]TSP){
双倍最佳=总距离;
int numCities=TSP.length;
int=0;
int电流=0;
int[]newTour=TSP;
while(访问 对于(int c=0;c而言,实际上只有4种形式的3-opt
将巡演分为3个部分A->、B->、C->
连接B到A和C的两条边上的2-opt为:
- A->
i、 只要把B的路线倒过来
现在是3-opt
- A->,B->
- A->,C->
请注意,A->,和A->,B->,,
private static int[] ThreeOpt(int[] TSP) {
double best = totalDistance;
int numCities = TSP.length;
int visited = 0;
int current = 0;
int[] newTour = TSP;
while (visited < numCities) {
for (int i = 0; i < numCities - 2; i++) {
for (int j = i + 1; j < numCities - 1; j++) {
for (int k = j + 1; k < numCities; k++) {
int[] newerTour = Swap(i, j, k, newTour);
int newDistance = distance(newTour);
if (newDistance < best) {
visited = 0;
best = newDistance;
newTour = newerTour;
}
}
}
}
visited++;
}
return newTour;
}