Java I';我试图将二维字符数组初始化为空格,但控制台中的输出很奇怪
下面是我的构造函数,我尝试用Java I';我试图将二维字符数组初始化为空格,但控制台中的输出很奇怪,java,multidimensional-array,char,Java,Multidimensional Array,Char,下面是我的构造函数,我尝试用空格初始化数组,但是当我打印出*作为边框(在我的toString中)时,奇怪的是控制台中的输出 // constructs a screen based on the dimensions public Screen(int height, int width) { screen = new char[height+2][width+2]; for (int i = 0; i < screen.length; i++) { for
空格
初始化数组,但是当我打印出*作为边框(在我的toString中)时,奇怪的是控制台中的输出
// constructs a screen based on the dimensions
public Screen(int height, int width) {
screen = new char[height+2][width+2];
for (int i = 0; i < screen.length; i++) {
for (int j = 0; j < screen[i].length; j++) {
screen[i][j] = ' ';
}
}
}
//根据尺寸构造屏幕
公共屏幕(整数高度、整数宽度){
屏幕=新字符[高度+2][宽度+2];
对于(int i=0;i
产量低于
*
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୪୪୪୪୪୪୪୪୪୪୪ 我有一个9乘9的屏幕,我不知道哪里出了问题
public String toString() {
String str = "";
for (int row = 0; row < screen.length; row++) {
for (int col = 0; col < screen[row].length; col++) {
if (row == 0 || col == 0 || row == screen.length-1) {
str += border;
} else {
border += screen[row][col];
}
}
str += "\n";
}
return str;
}
公共字符串toString(){
字符串str=“”;
for(int row=0;row
您的toString看起来很奇怪
你写道:
if (row == 0 || col == 0 || row == screen.length-1) {
str += border;
} else {
border += screen[row][col];
}
应该是:str+=screen[row][col]代码>
更好的解决方案
前面的解决方案会起作用,Netheress,我建议您这样做:
public static class Screen {
private char[][] screen;
private static final String BORDER = "*";
public Screen(int height, int width) {
screen = new char[height][width];
for (int i = 0; i < screen.length; i++) {
for (int j = 0; j < screen[i].length; j++) {
screen[i][j] = ' ';
}
}
}
@Override
public String toString() {
StringBuilder sb = new StringBuilder();
// add (screen.length + 2) for the first line.
for (int i = 0; i < screen.length + 2; i++) {
sb.append(BORDER);
}
sb.append(System.getProperty("line.separator"));
for (int i = 0; i < screen.length; i++) {
// star at the begin of each line
sb.append(BORDER);
for (int j = 0; j < screen[i].length; j++) {
sb.append(screen[i][j]);
}
// star at the end of each line
sb.append(BORDER);
sb.append(System.getProperty("line.separator"));
}
// add (screen.length + 2) for the last line.
for (int i = 0; i < screen.length + 2; i++) {
sb.append(BORDER);
}
return sb.toString();
}
}
公共静态类屏幕{
私有字符[][]屏幕;
私有静态最终字符串边框=“*”;
公共屏幕(整数高度、整数宽度){
屏幕=新字符[高度][宽度];
对于(int i=0;i
通过这种方式打印墙阵列,您不会覆盖边框内容。(在阵列周围添加星号,而不是在边框周围添加星号)你的toString看起来很奇怪
你写道:
if (row == 0 || col == 0 || row == screen.length-1) {
str += border;
} else {
border += screen[row][col];
}
应该是:str+=screen[row][col]代码>
更好的解决方案
前面的解决方案会起作用,Netheress,我建议您这样做:
public static class Screen {
private char[][] screen;
private static final String BORDER = "*";
public Screen(int height, int width) {
screen = new char[height][width];
for (int i = 0; i < screen.length; i++) {
for (int j = 0; j < screen[i].length; j++) {
screen[i][j] = ' ';
}
}
}
@Override
public String toString() {
StringBuilder sb = new StringBuilder();
// add (screen.length + 2) for the first line.
for (int i = 0; i < screen.length + 2; i++) {
sb.append(BORDER);
}
sb.append(System.getProperty("line.separator"));
for (int i = 0; i < screen.length; i++) {
// star at the begin of each line
sb.append(BORDER);
for (int j = 0; j < screen[i].length; j++) {
sb.append(screen[i][j]);
}
// star at the end of each line
sb.append(BORDER);
sb.append(System.getProperty("line.separator"));
}
// add (screen.length + 2) for the last line.
for (int i = 0; i < screen.length + 2; i++) {
sb.append(BORDER);
}
return sb.toString();
}
}
公共静态类屏幕{
私有字符[][]屏幕;
私有静态最终字符串边框=“*”;
公共屏幕(整数高度、整数宽度){
屏幕=新字符[高度][宽度];
对于(int i=0;i
通过这种方式打印墙阵列,您不会覆盖边框内容。(在阵列周围添加星号,而不是在边框周围添加星号)如何打印阵列?@AnthonyRaymond请看我的编辑,任何建议都会有用什么是边框
?为什么在你的toString()方法中它是递增的?你如何打印你的数组?@AnthonyRaymond请看我的编辑,任何建议都会有用什么是边框
?为什么在你的toString()方法中它是递增的?非常感谢,这是我犯的一个愚蠢的错误。我添加了一个更高级的解决方案,看一看。非常感谢,这是我犯的一个愚蠢的错误。我添加了一个更高级的解决方案,看一看。