Java 双向多对一映射
我不熟悉JAVA和JPA,我在谷歌上搜索了解决方案,但没用。我找到了很多例子,但它们在我的场景中不起作用。 我想映射以下两个表: 书架桌Java 双向多对一映射,java,hibernate,jpa,mapping,Java,Hibernate,Jpa,Mapping,我不熟悉JAVA和JPA,我在谷歌上搜索了解决方案,但没用。我找到了很多例子,但它们在我的场景中不起作用。 我想映射以下两个表: 书架桌 CREATE TABLE "SOA2"."BOOKSHELF" ( "BOOKSHELF_ID" NUMBER(19,0) NOT NULL ENABLE, "NAME_TXT" VARCHAR2(255 CHAR), PRIMARY KEY ("BOOKSHELF_ID") USING INDEX PCTFREE 10 INITRANS 2
CREATE TABLE "SOA2"."BOOKSHELF" (
"BOOKSHELF_ID" NUMBER(19,0) NOT NULL ENABLE,
"NAME_TXT" VARCHAR2(255 CHAR),
PRIMARY KEY ("BOOKSHELF_ID") USING INDEX PCTFREE 10 INITRANS 2
MAXTRANS 255 NOCOMPRESS LOGGING
TABLESPACE "SOA2" ENABLE
) SEGMENT CREATION DEFERRED PCTFREE 10 PCTUSED 40 INITRANS 1
MAXTRANS 255 NOCOMPRESS LOGGING TABLESPACE "SOA2" ;
CREATE TABLE "SOA2"."BOOK" (
"BOOK_IX" NUMBER(19,0) NOT NULL ENABLE,
"BOOKSHELF_ID" NUMBER(19,0) NOT NULL ENABLE,
"NAME_TXT" VARCHAR2(255 CHAR),
PRIMARY KEY ("BOOK_IX", "BOOKSHELF_ID") USING INDEX PCTFREE 10 INITRANS 2
MAXTRANS 255 NOCOMPRESS LOGGING TABLESPACE "SOA2" ENABLE, CONSTRAINT "FK_RJWHY4FC"
FOREIGN KEY ("BOOKSHELF_ID")
REFERENCES "SOA2"."BOOKSHELF" ("BOOKSHELF_ID") ENABLE)
SEGMENT CREATION DEFERRED PCTFREE 10 PCTUSED 40 INITRANS 1
MAXTRANS 255 NOCOMPRESS LOGGING TABLESPACE "SOA2" ;
及
书桌
CREATE TABLE "SOA2"."BOOKSHELF" (
"BOOKSHELF_ID" NUMBER(19,0) NOT NULL ENABLE,
"NAME_TXT" VARCHAR2(255 CHAR),
PRIMARY KEY ("BOOKSHELF_ID") USING INDEX PCTFREE 10 INITRANS 2
MAXTRANS 255 NOCOMPRESS LOGGING
TABLESPACE "SOA2" ENABLE
) SEGMENT CREATION DEFERRED PCTFREE 10 PCTUSED 40 INITRANS 1
MAXTRANS 255 NOCOMPRESS LOGGING TABLESPACE "SOA2" ;
CREATE TABLE "SOA2"."BOOK" (
"BOOK_IX" NUMBER(19,0) NOT NULL ENABLE,
"BOOKSHELF_ID" NUMBER(19,0) NOT NULL ENABLE,
"NAME_TXT" VARCHAR2(255 CHAR),
PRIMARY KEY ("BOOK_IX", "BOOKSHELF_ID") USING INDEX PCTFREE 10 INITRANS 2
MAXTRANS 255 NOCOMPRESS LOGGING TABLESPACE "SOA2" ENABLE, CONSTRAINT "FK_RJWHY4FC"
FOREIGN KEY ("BOOKSHELF_ID")
REFERENCES "SOA2"."BOOKSHELF" ("BOOKSHELF_ID") ENABLE)
SEGMENT CREATION DEFERRED PCTFREE 10 PCTUSED 40 INITRANS 1
MAXTRANS 255 NOCOMPRESS LOGGING TABLESPACE "SOA2" ;
为便于理解,其结构如下所示
及
在所有的搜索之后,我使用了Eclipse“JPA Entities from Tables”工具。
它为我生成了以下类:
Bookshelf.java
@Entity
@Table(name="BOOKSHELF")
public class Bookshelf implements Serializable {
@Id
@Column(name="BOOKSHELF_ID", unique=true)
private long bookshelfId;
@Column(name="NAME_TXT")
private String nameTxt;
//bi-directional many-to-one association to Book
@OneToMany(mappedBy="bookshelf", cascade={CascadeType.ALL})
private List<Book> books;
public List<Book> getBooks() {
return this.books;
}
public void setBooks(List<Book> books) {
this.books = books;
}
//Code removed for the sake of brevity
}
@Entity
@Table(name="BOOK")
public class Book implements Serializable {
@EmbeddedId
private BookPK id;
@Column(name="NAME_TXT", length=255)
private String nameTxt;
//bi-directional many-to-one association to Bookshelf
@ManyToOne(cascade={CascadeType.ALL})
@JoinColumn(name="BOOKSHELF_ID", nullable=false, insertable=false, updatable=false)
private Bookshelf bookshelf;
//Code removed for the sake of brevity
}
@Embeddable
public class BookPK implements Serializable {
@Column(name="BOOK_IX")
private long bookIx;
@Column(name="BOOKSHELF_ID", insertable=false, updatable=false, unique=true, nullable=false)
private long bookshelfId;
public BookPK(long bkShlfId, long bkId) {
this.bookshelfId = bkShlfId;
this.bookIx = bkId;
}
//Code removed for the sake of brevity
//Physics Bookshelf
Bookshelf physicsShelf = new Bookshelf();
physicsShelf.setNameTxt("Physics");
physicsShelf.setBookshelfId(500);
//Add Books
Book book1 = new Book();
book1.setNameTxt("God and the Physics");
book1.setId(new BookPK(500, 600));
Book book2 = new Book();
book2.setNameTxt("Hyperspace");
//if I pass 500 as first param in below constructor
//Changing 500 to 501 solves the issue
book2.setId(new BookPK(500, 600)); //javax.persistence.EntityExistsException: A different object with the same identifier value was already associated with the session : [books.Book#books.BookPK@8a6d]
//Add Books into list
List<Book> bookList = new ArrayList<Book>();
bookList.add(book1);
//Error: Following error appears if I uncomment the following line
bookList.add(book2); //Caused by: java.sql.SQLIntegrityConstraintViolationException: ORA-02291: integrity constraint (SOA2.FK_RJ) violated - parent key not found
//Set Books
physicsShelf.setBooks(bookList);
EntityTransaction transaction = entitymanager.getTransaction();
transaction.begin();
entitymanager.persist(physicsShelf);
transaction.commit();
BookPK.java
@Entity
@Table(name="BOOKSHELF")
public class Bookshelf implements Serializable {
@Id
@Column(name="BOOKSHELF_ID", unique=true)
private long bookshelfId;
@Column(name="NAME_TXT")
private String nameTxt;
//bi-directional many-to-one association to Book
@OneToMany(mappedBy="bookshelf", cascade={CascadeType.ALL})
private List<Book> books;
public List<Book> getBooks() {
return this.books;
}
public void setBooks(List<Book> books) {
this.books = books;
}
//Code removed for the sake of brevity
}
@Entity
@Table(name="BOOK")
public class Book implements Serializable {
@EmbeddedId
private BookPK id;
@Column(name="NAME_TXT", length=255)
private String nameTxt;
//bi-directional many-to-one association to Bookshelf
@ManyToOne(cascade={CascadeType.ALL})
@JoinColumn(name="BOOKSHELF_ID", nullable=false, insertable=false, updatable=false)
private Bookshelf bookshelf;
//Code removed for the sake of brevity
}
@Embeddable
public class BookPK implements Serializable {
@Column(name="BOOK_IX")
private long bookIx;
@Column(name="BOOKSHELF_ID", insertable=false, updatable=false, unique=true, nullable=false)
private long bookshelfId;
public BookPK(long bkShlfId, long bkId) {
this.bookshelfId = bkShlfId;
this.bookIx = bkId;
}
//Code removed for the sake of brevity
//Physics Bookshelf
Bookshelf physicsShelf = new Bookshelf();
physicsShelf.setNameTxt("Physics");
physicsShelf.setBookshelfId(500);
//Add Books
Book book1 = new Book();
book1.setNameTxt("God and the Physics");
book1.setId(new BookPK(500, 600));
Book book2 = new Book();
book2.setNameTxt("Hyperspace");
//if I pass 500 as first param in below constructor
//Changing 500 to 501 solves the issue
book2.setId(new BookPK(500, 600)); //javax.persistence.EntityExistsException: A different object with the same identifier value was already associated with the session : [books.Book#books.BookPK@8a6d]
//Add Books into list
List<Book> bookList = new ArrayList<Book>();
bookList.add(book1);
//Error: Following error appears if I uncomment the following line
bookList.add(book2); //Caused by: java.sql.SQLIntegrityConstraintViolationException: ORA-02291: integrity constraint (SOA2.FK_RJ) violated - parent key not found
//Set Books
physicsShelf.setBooks(bookList);
EntityTransaction transaction = entitymanager.getTransaction();
transaction.begin();
entitymanager.persist(physicsShelf);
transaction.commit();
}
我以如下方式进行测试:Test.java
@Entity
@Table(name="BOOKSHELF")
public class Bookshelf implements Serializable {
@Id
@Column(name="BOOKSHELF_ID", unique=true)
private long bookshelfId;
@Column(name="NAME_TXT")
private String nameTxt;
//bi-directional many-to-one association to Book
@OneToMany(mappedBy="bookshelf", cascade={CascadeType.ALL})
private List<Book> books;
public List<Book> getBooks() {
return this.books;
}
public void setBooks(List<Book> books) {
this.books = books;
}
//Code removed for the sake of brevity
}
@Entity
@Table(name="BOOK")
public class Book implements Serializable {
@EmbeddedId
private BookPK id;
@Column(name="NAME_TXT", length=255)
private String nameTxt;
//bi-directional many-to-one association to Bookshelf
@ManyToOne(cascade={CascadeType.ALL})
@JoinColumn(name="BOOKSHELF_ID", nullable=false, insertable=false, updatable=false)
private Bookshelf bookshelf;
//Code removed for the sake of brevity
}
@Embeddable
public class BookPK implements Serializable {
@Column(name="BOOK_IX")
private long bookIx;
@Column(name="BOOKSHELF_ID", insertable=false, updatable=false, unique=true, nullable=false)
private long bookshelfId;
public BookPK(long bkShlfId, long bkId) {
this.bookshelfId = bkShlfId;
this.bookIx = bkId;
}
//Code removed for the sake of brevity
//Physics Bookshelf
Bookshelf physicsShelf = new Bookshelf();
physicsShelf.setNameTxt("Physics");
physicsShelf.setBookshelfId(500);
//Add Books
Book book1 = new Book();
book1.setNameTxt("God and the Physics");
book1.setId(new BookPK(500, 600));
Book book2 = new Book();
book2.setNameTxt("Hyperspace");
//if I pass 500 as first param in below constructor
//Changing 500 to 501 solves the issue
book2.setId(new BookPK(500, 600)); //javax.persistence.EntityExistsException: A different object with the same identifier value was already associated with the session : [books.Book#books.BookPK@8a6d]
//Add Books into list
List<Book> bookList = new ArrayList<Book>();
bookList.add(book1);
//Error: Following error appears if I uncomment the following line
bookList.add(book2); //Caused by: java.sql.SQLIntegrityConstraintViolationException: ORA-02291: integrity constraint (SOA2.FK_RJ) violated - parent key not found
//Set Books
physicsShelf.setBooks(bookList);
EntityTransaction transaction = entitymanager.getTransaction();
transaction.begin();
entitymanager.persist(physicsShelf);
transaction.commit();
//物理书架
Bookshelf physicsShelf=新书架();
physicshelf.setNameTxt(“Physics”);
physicsShelf.setBookshelfId(500);
//添加书籍
Book book1=新书();
book1.setNameTxt(“上帝与物理学”);
book1.setId(新BookPK(500600));
Book book2=新书();
book2.setNameTxt(“超空间”);
//如果我通过500作为下面构造函数中的第一个参数
//将500更改为501解决了这个问题
book2.setId(新BookPK(500600))//javax.persistence.EntityExistsException:具有相同标识符值的不同对象已与会话:[books.Book#books]关联。BookPK@8a6d]
//将书籍添加到列表中
List bookList=newarraylist();
图书目录。添加(第1册);
//错误:如果我取消注释以下行,将出现以下错误
增加(第2册)//原因:java.sql.SQLIntegrityConstraintViolationException:ORA-02291:违反完整性约束(SOA2.FK_RJ)-未找到父密钥
//订书
physicsShelf.setBooks(书目);
EntityTransaction=entitymanager.getTransaction();
transaction.begin();
entitymanager.persist(physicsShelf);
commit();
physicsShelf只成功插入了一本书,如果我在图书列表中插入第二本书,它会给出Test.java注释中描述的错误
请引导我
关于id应该是唯一的,但在您的情况下,您将book1和book2的id都设置为Book(500600) 因此,当您尝试添加
book2.setId(newBookPK(500600))时代码>它正在抱怨它已经存在
试一试
编辑:第二个问题
我想你可以。在书中尝试替换实体
@EmbeddedId
private BookPK id;
与
book2的bookId是否应与book1的bookId不同?在上面的代码中,两者的id似乎与600相同?谢谢你的回答。非常感谢。我想我已经试过了。成功了。很抱歉这个愚蠢的问题。谢谢你的回答。我的第二个问题呢?