Java Spring数据OneToMany关系IP错误

有人能帮我提一个问题吗。我在文档中创建了对象结构，但relationschip-OneToMany不起作用

    Order:
    - Positions
    - Partners

    I receiving error:

    SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (order_id)' at line 1

订单：

@Getter
@Setter
@Entity
@Table(name = "e_orders")
public class Order {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "order_id")
    private int orderId;

    @Column(unique = true)
    private String orderNumber;
    private int count;

    @OneToMany(mappedBy = "e_orders", fetch = FetchType.LAZY)
    private List<Partner> partners;

    @OneToMany(mappedBy = "e_orders", fetch = FetchType.LAZY)
    private List<Position> positions;
}

职位：

@Getter
@Setter
@Entity
@Table(name = "e_position")
public class Position {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "position_id")
    private int id;

    private String guid;
    private String posnr;

    @ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
    @JoinColumn(name = "order_e_id")
    private Order attachedOrder;
}

---

我相信问题在于

mappedBy

值，因为

mappedBy

的值应该与相应类中的属性名称相同，而不是与

@表中的注释相同。因此，要解决这个问题，只需将
mappedBy
表单
e_orders
中的值更改为
attachedOrder
order
是一个受限的SQL单词，我已经更改为“e_orders”，但仍然是一个生成的SQL，当属性为
order
（Partner+Position）Yuriy Tsarkov。它在调用创建脚本之前崩溃。它在HibernateJpaConfiguration.class中配置的第一阶段直接崩溃
@Getter
@Setter
@Entity
@Table(name = "e_position")
public class Position {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "position_id")
    private int id;

    private String guid;
    private String posnr;

    @ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
    @JoinColumn(name = "order_e_id")
    private Order attachedOrder;
}