Java代码打印正确,但返回错误
以下代码:Java代码打印正确,但返回错误,java,string,return,Java,String,Return,以下代码: public class NewClass1 { public static String mus = ""; public static String musCal(String[] signal, int[] time) { int i = 0; while (i < signal.length) { switch (signal[i]) { case "x": {
public class NewClass1 {
public static String mus = "";
public static String musCal(String[] signal, int[] time) {
int i = 0;
while (i < signal.length) {
switch (signal[i]) {
case "x": {
// System.out.print("x = ");
mus = mus + "x";
int sum = time[i];
if (signal[i + 1] == "C") {
i++;
while (i < signal.length && signal[i] == "C") {
sum += time[i];
i++;
}
} else
i++;
// System.out.print(sum + " ");
mus = sum + " ";
break;
}
case "y": {
// System.out.print("y = ");
mus = mus + "y ";
int sum = time[i];
if (signal[i + 1] == "C") {
i++;
while (i < signal.length && signal[i] == "C") {
sum += time[i];
i++;
}
} else
i++;
// System.out.print(sum + " ");
mus = sum + " ";
break;
}
case "z": {
// System.out.print("z = ");
mus = mus + "z ";
int sum = time[i];
if (signal[i + 1] == "C") {
i++;
while (i < signal.length && signal[i] == "C") {
sum += time[i];
i++;
}
} else
i++;
// System.out.print(sum + " ");
mus = sum + " ";
break;
}
}
}
return mus;
}
public static void main(String[] args) {
String signal[] = { "x", "y", "y", "C", "C", "z", "C", "C", "x", "C" };
int time[] = { 2, 5, 1, 4, 7, 8, 2, 6, 4, 3 };
musCal(signal, time);
System.out.print(mus);
}
}
如果删除注释符号//以激活System.out.print语句,则代码将给出预期的输出。但当我试图以“String mus”的形式收集这个输出时,如代码所示,我只得到了输出字符串的最后一个元素,即7。作为java和编程的新手,我需要你的帮助。请帮助我更正return语句,以便通过连接或任何其他合适的方法获得正确的字符串“mus”输出。您可以使用
mus=sum + " ";
而不是像
mus = mus + sum + " "
另外,if和else并不总是使用括号,这是一种非常糟糕的代码风格,我谴责Java发明家如果只想执行一行代码,就将括号设为可选括号。您也可以将此解决方案用于: 替换mus=总和+; mus+=sum+
mus = mus + sum + " "