Java 错误404:源服务器找不到目标资源的当前表示形式,或者不愿意透露存在该表示形式
在服务器上运行web应用程序时出现404错误。。。我尝试了很多事情,但我无法解决这个问题 我的控制器代码是Java 错误404:源服务器找不到目标资源的当前表示形式,或者不愿意透露存在该表示形式,java,spring,spring-mvc,Java,Spring,Spring Mvc,在服务器上运行web应用程序时出现404错误。。。我尝试了很多事情,但我无法解决这个问题 我的控制器代码是 @Controller @RequestMapping("/customer") public class CustomerController { @RequestMapping("/list") public String listCustomers(Model theModel) { return "
@Controller
@RequestMapping("/customer")
public class CustomerController {
@RequestMapping("/list")
public String listCustomers(Model theModel) {
return "list-customers";
}
}
我的spring-mvc-crud-demo-servlet.xml文件如下所示
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx.xsd">
<!-- Add support for component scanning -->
<context:component-scan base-package="com.luv2code.springdemo" />
<!-- Add support for conversion, formatting and validation support -->
<mvc:annotation-driven/>
<!-- Define Spring MVC view resolver -->
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/view/" />
<property name="suffix" value=".jsp" />
</bean>
<!-- Step 1: Define Database DataSource / connection pool -->
<bean id="myDataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource"
destroy-method="close">
<property name="driverClass" value="com.mysql.cj.jdbc.Driver" />
<property name="jdbcUrl" value="jdbc:mysql://localhost:3306/web_customer_tracker?useSSL=false&serverTimezone=UTC" />
<property name="user" value="springstudent" />
<property name="password" value="springstudent" />
<!-- these are connection pool properties for C3P0 -->
<property name="initialPoolSize" value="5"/>
<property name="minPoolSize" value="5" />
<property name="maxPoolSize" value="20" />
<property name="maxIdleTime" value="30000" />
</bean>
<!-- Step 2: Setup Hibernate session factory -->
<bean id="sessionFactory"
class="org.springframework.orm.hibernate5.LocalSessionFactoryBean">
<property name="dataSource" ref="myDataSource" />
<property name="packagesToScan" value="com.luv2code.springdemo.entity" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<!-- Step 3: Setup Hibernate transaction manager -->
<bean id="myTransactionManager"
class="org.springframework.orm.hibernate5.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
<!-- Step 4: Enable configuration of transactional behavior based on annotations -->
<tx:annotation-driven transaction-manager="myTransactionManager" />
<!-- Add support for reading web resources: css, images, js, etc ... -->
<mvc:resources location="/resources/" mapping="/resources/**"></mvc:resources>
</beans>
org.hibernate.dialogue.mysqldialogue
真的
我的web.xml文件是
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1">
<display-name>spring-mvc-crud-demo</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-mvc-crud-demo-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
spring mvc crud演示
index.jsp
index.html
调度员
org.springframework.web.servlet.DispatcherServlet
上下文配置位置
/WEB-INF/spring-mvc-crud-demo-servlet.xml
1.
调度员
/
我使用了url:
http://localhost:8080/web-客户跟踪/客户/列表
我的项目结构是。。。
请帮我做这件事。。首先,动态项目是以错误的方式创建的 我已经使用了
tomcat8.5.57版本
来测试jdk8
在tomcat上部署项目时,我遇到了这个问题:
More than one fragment with the name [spring_web] was found. This is not legal with relative ordering. See section 8.2.2 2c of the Servlet specification for details. Consider using absolute ordering
我通过添加
我的github代码:(1)除非有令人信服的理由,否则请使用Spring Boot。(2) 您的“所有客户”URL通常应该是/customers
(没有ID的GET表示“检索所有”)。(3) 我认为问题在于你没有映射/**
,但我已经7年没有使用这种旧样式了,因为开机使它变得不必要。现在解决你的问题。@AnishB。这是github repo的链接。此repo将包含一些附加代码。。。我后来插入的。。。谢谢:)为您提供repo@AnishB你找到解决办法了吗?B非常感谢你宝贵的时间。但不幸的是,这对我不起作用。我认为会有一些环境问题。你能在linkedin上和我联系吗。我已经向你发送了一个连接请求。非常感谢你的时间和支持