Warning: file_get_contents(/data/phpspider/zhask/data//catemap/9/java/372.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Java和/或运算符不工作_Java_Operators_Conditional - Fatal编程技术网

Java和/或运算符不工作

Java和/或运算符不工作,java,operators,conditional,Java,Operators,Conditional,我使用以下语句在满足两个条件时中断循环: while (true) { if (uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2) || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4) && uAnswer2.equals(answerS1)|

我使用以下语句在满足两个条件时中断循环:

while (true)
    {
        if (uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4) 
                &&
                uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2)){
            break;
        }
当满足一个或两个&&条件时,循环将中断。但是,我编写的代码仅在两个条件都为真时才中断循环

上面的陈述有什么遗漏吗? 当做
Shei7141.

用括号括起来

if ( (uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4))
&&
(uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2)) )

甚至做一个正确答案的
HashSet
,这样做既干净又高效

answers1Set.contains(uAnswer1) && answers2Set.contains(uAnswer2)  

用括号括起来

if ( (uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4))
&&
(uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2)) )

甚至做一个正确答案的
HashSet
,这样做既干净又高效

answers1Set.contains(uAnswer1) && answers2Set.contains(uAnswer2)  

用括号括起来

if ( (uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4))
&&
(uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2)) )

甚至做一个正确答案的
HashSet
,这样做既干净又高效

answers1Set.contains(uAnswer1) && answers2Set.contains(uAnswer2)  

用括号括起来

if ( (uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4))
&&
(uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2)) )

甚至做一个正确答案的
HashSet
,这样做既干净又高效

answers1Set.contains(uAnswer1) && answers2Set.contains(uAnswer2)  

上述代码显示uAnswer1.equals(answerB4)和&uAnswer2.equals(answer1)处于状态

while (true)
    {
        if ((uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4)) 

                &&

                (uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2))){
            break;
        }

上述代码显示uAnswer1.equals(answerB4)和&uAnswer2.equals(answer1)处于状态

while (true)
    {
        if ((uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4)) 

                &&

                (uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2))){
            break;
        }

上述代码显示uAnswer1.equals(answerB4)和&uAnswer2.equals(answer1)处于状态

while (true)
    {
        if ((uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4)) 

                &&

                (uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2))){
            break;
        }

上述代码显示uAnswer1.equals(answerB4)和&uAnswer2.equals(answer1)处于状态

while (true)
    {
        if ((uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4)) 

                &&

                (uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2))){
            break;
        }
while(true) { 如果((uAnswer1.equals)(answerB1)| | uAnswer1.equals(answerB2) ||uAnswer1.equals(answerB3)| uAnswer1.equals(answerB4)) && (uAnswer2.equals(answer1)| | uAnswer2.equals(answer2))) 打破 }while(真) { 如果((uAnswer1.equals)(answerB1)| | uAnswer1.equals(answerB2) ||uAnswer1.equals(answerB3)| uAnswer1.equals(answerB4)) && (uAnswer2.equals(answer1)| | uAnswer2.equals(answer2))) 打破 }while(真) { 如果((uAnswer1.equals)(answerB1)| | uAnswer1.equals(answerB2) ||uAnswer1.equals(answerB3)| uAnswer1.equals(answerB4)) && (uAnswer2.equals(answer1)| | uAnswer2.equals(answer2))) 打破 }while(真) { 如果((uAnswer1.equals)(answerB1)| | uAnswer1.equals(answerB2) ||uAnswer1.equals(answerB3)| uAnswer1.equals(answerB4)) && (uAnswer2.equals(answer1)| | uAnswer2.equals(answer2))) 打破
}

以上代码显示
uAnswer1.equals(answerB4)和&uAnswer2.equals(answerS1)
处于
条件下。在这种情况下,
&
将优先于
|
@JigarJoshi的答案是正确的。
answerBn
answerSn
值在循环中是常量吗?上面的代码显示
uAnswer1.equals(answerB4)和&uAnswer2.equals(answerS1)
处于
条件中,在这种情况下,
&
将优先于
|
@JigarJoshi的答案是正确的。
answerBn
answerSn
值在循环中是常量吗?上面的代码显示
uAnswer1.equals(answerB4)和&uAnswer2.equals(answerS1)
处于
条件中,在这种情况下,
&
将优先于
|
@JigarJoshi的答案是正确的。
answerBn
answerSn
值在循环中是常量吗?上面的代码显示
uAnswer1.equals(answerB4)和&uAnswer2.equals(answerS1)
处于
条件中,在这种情况下,
&
将优先于
|
@JigarJoshi的答案正确。
answerBn
answerSn
值在循环中是否保持不变?