Java 上传音频文件时通过HttpURLConnection传递参数

Java 上传音频文件时通过HttpURLConnection传递参数,java,php,android,parameter-passing,httpurlconnection,Java,Php,Android,Parameter Passing,Httpurlconnection,当我从一个堆栈溢出答案中获取代码时。 修改下面的代码,我试图将音频/视频文件发布到在线php服务器。一切正常文件正在正确上传并保存在数据库中,但问题是我也在发送文件参数,以便识别哪个用户正在发送录制,(用户id和候选人id以及文件类型),但在数据库中,它们的值为空/0 请有人告诉我我的代码有什么问题为什么它不适用于params。当我用POSTMAN检查我的php端服务器时,所有的值都正确地保存在文件中 try { FileInputStream fileInputStr

当我从一个堆栈溢出答案中获取代码时。

修改下面的代码,我试图将音频/视频文件发布到在线php服务器。一切正常文件正在正确上传并保存在数据库中,但问题是我也在发送文件参数,以便识别哪个用户正在发送录制,(用户id和候选人id以及文件类型),但在数据库中,它们的值为空/0

请有人告诉我我的代码有什么问题为什么它不适用于params。当我用POSTMAN检查我的php端服务器时,所有的值都正确地保存在文件中

try {
            FileInputStream fileInputStream = new FileInputStream(
                    sourceFile);
            URL url = new URL(Config.URL_UPLOAD);
            conn = (HttpURLConnection) url.openConnection();
            conn.setDoInput(true); // Allow Inputs
            conn.setDoOutput(true); // Allow Outputs
            conn.setUseCaches(false); // Don't use a Cached Copy
            conn.setRequestMethod("POST");
            conn.setRequestProperty("Connection", "Keep-Alive");
            conn.setRequestProperty("ENCTYPE", "multipart/form-data");
            conn.setRequestProperty("Content-Type",
                    "multipart/form-data;boundary=" + boundary);
            conn.setRequestProperty("uploadedfile", fileName);

            dos = new DataOutputStream(conn.getOutputStream());
            //here am adding the params

            param.put("user_id", Constants.user_id);
            param.put("candidate_id", "candiidateid1");
            param.put("file_type", Constants.file_type);
            BufferedWriter writer = new BufferedWriter(
                    new OutputStreamWriter(dos, "UTF-8"));
            writer.write(getPostDataString(param));
            dos.writeBytes(twoHyphens + boundary + lineEnd);
            dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + fileName + "\"" + lineEnd);

            dos.writeBytes(lineEnd);

            // create a buffer of maximum size
            bytesAvailable = fileInputStream.available();

            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            buffer = new byte[bufferSize];

            // read file and write it into form...
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            while (bytesRead > 0) {

                dos.write(buffer, 0, bufferSize);
                bytesAvailable = fileInputStream.available();
                bufferSize = Math.min(bytesAvailable, maxBufferSize);
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            }

            // send multipart form data necesssary after file data...
            dos.writeBytes(lineEnd);
            dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

            dialog.dismiss();
            // Responses from the server (code and message)
            serverResponseCode = conn.getResponseCode();
            String serverResponseMessage = conn.getResponseMessage();

            Log.i("uploadFile", "HTTP Response is : "
                    + serverResponseMessage + ": " + serverResponseCode);
            DataInputStream inStream = null;
            if (serverResponseCode == 200) {
                try {
                    Log.e("isStream = ", "" + inStream);
                    inStream = new DataInputStream(conn.getInputStream());
                    String str;
                    Log.e("isStream = ", "" + inStream);
                    while ((str = inStream.readLine()) != null) {
                        Log.e("Debug", "Server Response " + str);
                    }
                    inStream.close();
                    Log.e("isStream = ", "" + inStream);
                } catch (IOException ioex) {
                    Log.e("Debug", "error: " + ioex.getMessage(), ioex);
                }

            }

            // close the streams //
            fileInputStream.close();
            dos.flush();
            dos.close();

        } catch (MalformedURLException ex) {

            dialog.dismiss();
            ex.printStackTrace();


            Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
        } catch (Exception e) {

            dialog.dismiss();
            e.printStackTrace();


            Log.e("Upload file to server ",
                    "Exception : " + e.getMessage(), e);
        }

请参阅下面的URL,以获得清晰的答案来传递参数


请参考下面的URL,以获得清晰的答案来传递参数


DataOutputStream是一个Java实用程序类,用于编码简单的Java值。PHP可能无法以本机方式处理这种编码,因此您应该寻找其他跨语言的方式来传输元数据。PHP可能无法以本机方式处理这种编码,所以您应该寻找其他跨语言的方式来传输元数据。