Java 从编辑文本中获取输入并保存在列表1中，但它将在其他列表中显示列表1的结果

我有两节课。第一个是

MainActivity.java

第二个是

EditBox.java

我试图做的是

MainActivity.java

创建4个列表，我想从EditBox.java中的编辑框中获取数据，并保存在

列表中。当我在
列表中的编辑框中输入时，它将在其他列表。请帮助我做什么
这是密码

MainActivity.java

public class MainActivity extends Activity 
{

    @Override
    protected void onCreate(Bundle savedInstanceState) 
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        ListView listView1 = (ListView) findViewById(R.id.listView1);

         String[] items = { "List 1", "List 2", "List 3","List 4" };


        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1, items);

        listView1.setAdapter(adapter);



        listView1.setOnItemClickListener(new OnItemClickListener() 
        {

            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position,long id)
            {

                String item = ((TextView)view).getText().toString();

                //Toast.makeText(getBaseContext(), item, Toast.LENGTH_LONG).show();

                Intent it1 =new Intent(getApplicationContext(),editbox.class); 

                startActivity(it1);

            }
        });



    }

    public boolean onCreateOptionsMenu(Menu menu) 
    {

        super.onCreateOptionsMenu(menu);
        menu.add("List").setIntent(new Intent(this,MainActivity.class));
        return true;
    }

}

在Editbox.java中，为什么只定义了一个编辑文本？是故意的还是您在复制和粘贴时忘记更改它。尝试更改edittext名称和R.id.\uuuuuuuuuuuuuuuuuuuuuuuu当您单击列表时，editbox活动处于打开状态，您在编辑框中输入num与其他列表相同，其中editbox相同，因此我定义了一个edittext。因此，您只能定义（findViewById）一次。你能很好地解释一下你不会这么做吗。从编辑文本框中获取数据并保存在列表中。每当我点击列表时，它都会显示数据/num
public class editbox extends Activity 
{

    private EditText nameText,nameText1;
    @Override
    protected void onCreate(Bundle savedInstanceState) 
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.editbox);

        nameText=(EditText)findViewById(R.id.editText1);
        SharedPreferences setting = getSharedPreferences("List 1",0);
        nameText.setText(setting.getString("List 1", ""));

        nameText=(EditText)findViewById(R.id.editText1);
        SharedPreferences setting1 = getSharedPreferences("List 2",0);
        nameText.setText(setting1.getString("List 2", "")); 




    }

    protected void onStop() 
    {

        super.onStop();

        SharedPreferences setting = getSharedPreferences("List 1",0);
        SharedPreferences.Editor editor = setting.edit();
        editor.putString("List 1", nameText.getText().toString());
        editor.commit();

        SharedPreferences setting1 = getSharedPreferences("List 2",0);
        SharedPreferences.Editor editor1 = setting1.edit();
        editor1.putString("List 2", nameText1.getText().toString());
        editor1.commit();
    }

    public boolean onCreateOptionsMenu(Menu menu) 
    {
        // Inflate the menu; this adds items to the action bar if it is present.
        //getMenuInflater().inflate(R.menu.main, menu);
        super.onCreateOptionsMenu(menu);
        menu.add("List 1").setIntent(new Intent(this,MainActivity.class));

        return true;
    }
}

nameText=(EditText)findViewById(R.id.editText1);
    SharedPreferences setting = getSharedPreferences("List 1",0);
    nameText.setText(setting.getString("List 1", ""));

// The problem is here
    nameText1=(EditText)findViewById(R.id.editText1); // get your second EditText ID here
    SharedPreferences setting1 = getSharedPreferences("List 2",0);
    nameText1.setText(setting1.getString("List 2", ""));