如何在Java中旋转BuffereImage？

可能重复：

我当前使用的方法（如下）会导致BuffereImage随着角度参数的减小而变得越来越失真

public static BufferedImage getRotatedImage(BufferedImage src, int angle) { 

    if (src == null) {

      System.out.println("getRotatedImage: input image is null");
      return null;

    }

    int transparency = src.getColorModel().getTransparency();
    BufferedImage dest =  gc.createCompatibleImage(
                              src.getWidth(), src.getHeight(), transparency );
    Graphics2D g2d = dest.createGraphics();

    AffineTransform origAT = g2d.getTransform(); 

    AffineTransform rot = new AffineTransform(); 
    rot.rotate(Math.toRadians(angle), src.getWidth()/2, src.getHeight()/2); 
    g2d.transform(rot); 

    g2d.drawImage(src, 0, 0, null);   

    g2d.setTransform(origAT);   
    g2d.dispose();

    return dest; 

随着角度变小，这种情况变得越来越扭曲

public static BufferedImage getRotatedImage(BufferedImage src, int angle) { 

    if (src == null) {

      System.out.println("getRotatedImage: input image is null");
      return null;

    }

    int transparency = src.getColorModel().getTransparency();
    BufferedImage dest =  gc.createCompatibleImage(
                              src.getWidth(), src.getHeight(), transparency );
    Graphics2D g2d = dest.createGraphics();

    AffineTransform origAT = g2d.getTransform(); 

    AffineTransform rot = new AffineTransform(); 
    rot.rotate(Math.toRadians(angle), src.getWidth()/2, src.getHeight()/2); 
    g2d.transform(rot); 

    g2d.drawImage(src, 0, 0, null);   

    g2d.setTransform(origAT);   
    g2d.dispose();

    return dest; 

听起来你在做：

 img = base_img;
 for (i = 0; i < n; i++) {
   img = rotate(img, theta);
 }

img=base\u img；
对于（i=0；i

当你真的想做的时候：

for (i = 0; i < n; i++) {
  img = rotate(base_img, theta * n);
}

（i=0；i{ img=旋转（基准img，θ*n）； }

---

但我可能做出了不真实的假设。

答案不多？在绘制新的旋转版本之前，您可以先看一看图像，还是先清除图像？